Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

For each of the following gas-phase reactions, indicate how the rate of disappearance of each reactant is related to the rate of appearance of each product: (a) \(\mathrm{H}_{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)\) (b) \(2 \mathrm{~N}_{2} \mathrm{O}(g) \longrightarrow 2 \mathrm{~N}_{2}(g)+\mathrm{O}_{2}(g)\) (c) \(\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)\) (d) \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{NH}_{2}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{NH}_{3}(g)\)

Short Answer

Expert verified
(a) Rate of disappearance of \(\mathrm{H}_{2} \mathrm{O}_{2} = -\)rate of appearance of \(\mathrm{H}_{2} = -\)rate of appearance of \(\mathrm{O}_{2}\) (b) Rate of disappearance of \(\mathrm{N}_{2}\mathrm{O} = -\cfrac{1}{2}\) rate of appearance of \(\mathrm{N}_{2}=-\cfrac{1}{2}\) rate of appearance of \(\mathrm{O}_{2}\) (c) Rate of disappearance of \(\mathrm{N}_{2} = -\cfrac{1}{3}\) rate of disappearance of \(\mathrm{H}_{2}=-\cfrac{1}{2}\) rate of appearance of \(\mathrm{NH}_{3}\) (d) Rate of disappearance of \(\mathrm{C}_{2}\mathrm{H}_{3}\mathrm{NH}_{2} = -\)rate of appearance of \(\mathrm{C}_{2}\mathrm{H}_{4}=-\)rate of appearance of \(\mathrm{NH}_{3}\)

Step by step solution

01

Analyze the coefficients

The coefficients for this reaction are all 1, which means the molar ratios between all elements are equal.
02

Write the rate relationships

Since the coefficients are all 1, the rate of disappearance of \(\mathrm{H}_{2} \mathrm{O}_{2}\) is equal to the rate of appearance of both \(\mathrm{H}_{2}\) and \(\mathrm{O}_{2}\). Thus, we have: Rate of disappearance of \(\mathrm{H}_{2} \mathrm{O}_{2} = -\)rate of appearance of \(\mathrm{H}_{2} = -\)rate of appearance of \(\mathrm{O}_{2}\) (b) Reaction: \(2 \mathrm{~N}_{2} \mathrm{O}(g) \longrightarrow 2 \mathrm{~N}_{2}(g)+\mathrm{O}_{2}(g)\)
03

Analyze the coefficients

The coefficients in this reaction are 2 for \(\mathrm{N}_{2}\mathrm{O}\), \(\mathrm{N}_{2}\) and 1 for \(\mathrm{O}_{2}\).
04

Write the rate relationships

Given the coefficients, the rate of disappearance of \(2\,\mathrm{N}_{2}\mathrm{O}\) is twice the rate of appearance of both \(2\,\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\). Thus: Rate of disappearance of \(\mathrm{N}_{2}\mathrm{O} = -\cfrac{1}{2}\) rate of appearance of \(\mathrm{N}_{2}=-\cfrac{1}{2}\) rate of appearance of \(\mathrm{O}_{2}\) (c) Reaction: \(\mathrm{N}_{2}(g) + 3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)\)
05

Analyze the coefficients

The coefficients in this reaction are 1 for \(\mathrm{N}_{2}\), 3 for \(\mathrm{H}_{2}\) and 2 for \(\mathrm{NH}_{3}\).
06

Write the rate relationships

With the given coefficients, the rate of disappearance of \(\mathrm{N}_{2}\) is \(\cfrac{1}{3}\) of the rate of disappearance of \(\mathrm{H}_{2}\) and \(\cfrac{1}{2}\) of the rate of appearance of \(\mathrm{NH}_{3}\): Rate of disappearance of \(\mathrm{N}_{2} = -\cfrac{1}{3}\) rate of disappearance of \(\mathrm{H}_{2}=-\cfrac{1}{2}\) rate of appearance of \(\mathrm{NH}_{3}\) (d) Reaction: \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{NH}_{2}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{NH}_{3}(g)\)
07

Analyze the coefficients

The coefficients for this reaction are all 1, which means the molar ratios between all elements are equal.
08

Write the rate relationships

Since the coefficients are all 1, the rate of disappearance of \(\mathrm{C}_{2}\mathrm{H}_{3}\mathrm{NH}_{2}\) is equal to the rate of appearance of both \(\mathrm{C}_{2}\mathrm{H}_{4}\) and \(\mathrm{NH}_{3}\). Thus: Rate of disappearance of \(\mathrm{C}_{2}\mathrm{H}_{3}\mathrm{NH}_{2} = -\)rate of appearance of \(\mathrm{C}_{2}\mathrm{H}_{4}=-\)rate of appearance of \(\mathrm{NH}_{3}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate of Disappearance
In chemical reactions, substances are transformed as reactants turn into products. Naturally, this means that as a reaction progresses, the quantities of reactants decrease. The speed at which a reactant is consumed in a reaction is known as the rate of disappearance. This rate is crucial because it helps scientists and engineers understand how quickly a reactant is being used up, which influences how they might conduct or control a reaction. The rate of disappearance is typically expressed as a negative value. This negative sign is important because concentrations of reactants decrease over time. Mathematically, for a reactant \( A \), the rate of disappearance is represented as:\[ -\frac{d[A]}{dt} \]where \([A]\) is the concentration of reactant \( A \) and \( t \) is time. In the context of balanced chemical equations, the rate of disappearance can help determine how fast each reactant is being consumed relative to the creation of products by comparing their molar relationships.
Rate of Appearance
Conversely to disappearance, the rate of appearance refers to how quickly products form in a chemical reaction. As reactants decrease, products increase, thus scientists are just as interested in the rate at which products appear. The rate of appearance is expressed as a positive value, indicating an increase in product concentration over time. For a product \( B \), this rate can be described as:\[ \frac{d[B]}{dt} \]which considers the concentration of product \( B \) over time \( t \). These rates can vary depending on the conditions of the reaction and the stoichiometry of the balanced equation. Understanding the rate of appearance is essential for optimizing conditions in industrial and laboratory settings, ensuring products are formed at desired rates.
Molar Coefficients
Molar coefficients are integral parts of balanced chemical equations. They indicate the relative amounts of each reactant and product involved in a reaction. These coefficients are essential for understanding how the rate of disappearance of reactants relates to the rate of appearance of products.In chemical equations, molar coefficients are the numbers placed before compounds or elements. For instance, in the reaction \( 2 \mathrm{N}_2\mathrm{O}(g) \rightarrow 2 \mathrm{N}_2(g) + \mathrm{O}_2(g) \), the molar coefficients are 2 for \( \mathrm{N}_2\mathrm{O} \) and \( \mathrm{N}_2 \), and 1 for \( \mathrm{O}_2 \).Using these coefficients, we can deduce the stoichiometric relations, which allow us to calculate the rates at which different substances decrease or increase during the reaction. The molar ratio given by these coefficients helps in setting up proportional relationships between rates of disappearing reactants and appearing products.
Chemical Reactions
Chemical reactions are processes where reactants are converted into products through the breaking and forming of chemical bonds. These reactions are fundamental to chemistry, underlying everything from biological functions to industrial processes. Understanding a chemical reaction involves looking at the equation, which reveals vital details like reactants, products, and stoichiometric relationships. For example, the reaction \( \mathrm{N}_2 + 3\mathrm{H}_2 \rightarrow 2\mathrm{NH}_3 \) illustrates how nitrogen and hydrogen combine to form ammonia. Reactions have certain characteristics, such as exothermic or endothermic nature, which describe whether they release or absorb heat. Understanding rates and stoichiometry enables chemists to control reactions for various applications, including manufacturing, pharmaceuticals, and energy production. By evaluating these factors, scientists can predict and manipulate the outcomes of reactions to align with desired goals, making the study of reaction rates crucial in the field of chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Urea \(\left(\mathrm{NH}_{2} \mathrm{CONH}_{2}\right)\) is the end product in protein metabolism in animals. The decomposition of urea in \(0.1 \mathrm{M} \mathrm{HCl}\) occurs according to the reaction $$ \mathrm{NH}_{2} \mathrm{CONH}_{2}(a q)+\mathrm{H}^{+}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{NH}_{4}^{+}(a q)+\mathrm{HCO}_{3}^{-}(a q) $$ The reaction is first order in urea and first order overall. When \(\left[\mathrm{NH}_{2} \mathrm{CONH}_{2}\right]=0.200 \mathrm{M}\), the rate at \(61.05^{\circ} \mathrm{C}\) is \(8.56 \times 10^{-5} \mathrm{M} / \mathrm{s}\). (a) What is the rate constant, \(k\) ? (b) What is the concentration of urea in this solution after \(4.00 \times 10^{3} \mathrm{~s}\) if the starting concentration is \(0.500 \mathrm{M}\) ? (c) What is the halflife for this reaction at \(61.05^{\circ} \mathrm{C}\) ?

As described in Exercise 14.41, the decomposition of sulfuryl chloride \(\left(\mathrm{SO}_{2} \mathrm{Cl}_{2}\right)\) is a first-order process. The rate constant for the decomposition at \(660 \mathrm{~K}\) is \(4.5 \times 10^{-2} \mathrm{~s}^{-1}\). (a) If we begin with an initial \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) pressure of 450 torr, what is the partial pressure of this substance after \(60 \mathrm{~s}\) ? (b) At what time will the partial pressure of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) decline to one-tenth its initial value?

(a) Most commercial heterogeneous catalysts are extremely finely divided solid materials. Why is particle size important? (b) What role does adsorption play in the action of a heterogeneous catalyst?

The following kinetic data are collected for the initial rates of a reaction \(2 \mathrm{X}+\mathrm{Z} \longrightarrow\) products: $$ \begin{array}{llll} \hline \text { Experiment } & {[\mathrm{X}]_{0}(M)} & {[\mathrm{Z}]_{0}(M)} & \text { Rate }(M / \mathrm{s}) \\ \hline 1 & 0.25 & 0.25 & 4.0 \times 10^{1} \\ 2 & 0.50 & 0.50 & 3.2 \times 10^{2} \\ 3 & 0.50 & 0.75 & 7.2 \times 10^{2} \\ \hline \end{array} $$ (a) What is the rate law for this reaction? (b) What is the value of the rate constant with proper units? (c) What is the reaction rate when the initial concentration of \(X\) is \(0.75 M\) and that of \(Z\) is \(1.25 M ?\)

(a) What is meant by the term reaction rate? (b) Name three factors that can affect the rate of a chemical reaction. (c) Is the rate of disappearance of reactants always the same as the rate of appearance of products?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free