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Consider water and glycerol, \(\mathrm{CH}_{2}(\mathrm{OH}) \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{2} \mathrm{OH}\). (a) Would you expect them to be miscible in all proportions? Explain. (b) List the intermolecular attractions that occur between a water molecule and a glycerol molecule.

Short Answer

Expert verified
(a) Yes, water and glycerol are expected to be miscible in all proportions due to their similar polar nature and hydrogen bonding capabilities. (b) The intermolecular attractions between water and glycerol molecules are hydrogen bonds, formed between the oxygen atom of the hydroxyl group in glycerol and the hydrogen atom of the water molecule, and vice versa.

Step by step solution

01

Understand the molecular structures of water and glycerol

Water has a molecular formula of H2O, and glycerol has a molecular formula of \(\mathrm{CH}_{2}(\mathrm{OH})\mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{2} \mathrm{OH}\). Both compounds contain oxygen and hydrogen atoms. In water, the oxygen atom is bound to two hydrogen atoms, while in glycerol, there are three hydroxyl groups \((\mathrm{OH})\), each connected to a carbon atom.
02

Determine miscibility

A rule of thumb when considering whether two substances are miscible is "like dissolves like." This means that polar substances are more likely to mix well with other polar substances, and nonpolar substances are more likely to mix well with other nonpolar substances. Both water and glycerol are polar compounds, as they have oxygen and hydrogen atoms, which leads to hydrogen bonding. Since they are both polar substances, it can be expected that they would be miscible in all proportions.
03

Explain miscibility

Water and glycerol are miscible in all proportions because they are both polar and exhibit hydrogen bonding. The hydrogen bonds between their molecules enable them to mix well, as they have similar interactions with each other.
04

Identify intermolecular attractions

The specific intermolecular attractions occurring between water and glycerol molecules are hydrogen bonds. These hydrogen bonds are formed between the oxygen atom of the hydroxyl group in glycerol and the hydrogen atom of the water molecule. Additionally, there can be hydrogen bonding between the oxygen atom of the water molecule and the hydrogen atom of the hydroxyl group in glycerol. In summary: (a) Water and glycerol are expected to be miscible in all proportions due to their similar polar nature and hydrogen bonding capabilities. (b) The intermolecular attractions between water and glycerol molecules are hydrogen bonds, formed between the oxygen atom of the hydroxyl group in glycerol and the hydrogen atom of the water molecule, and vice versa.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrogen Bonding
Hydrogen bonding is a unique and strong type of dipole-dipole attraction. It occurs when a hydrogen atom is directly bonded to a highly electronegative atom such as oxygen, nitrogen, or fluorine. In the case of water (H₂O) and glycerol (C₃H₈O₃), hydrogen bonding plays a significant role in their behavior and interactions.

  • Water has hydrogen atoms bonded to oxygen, creating a polar molecule with areas of partial positive and negative charges due to the uneven distribution of electrons.
  • Glycerol, with its three hydroxyl (-OH) groups, also supports strong hydrogen bonding. Each hydroxyl group in glycerol can form hydrogen bonds with water and other hydroxyl groups.
Hydrogen bonds are not actual chemical bonds but are strong enough to significantly influence the properties of compounds. They increase boiling and melting points, and in the case of water and glycerol, enable them to mix thoroughly, displaying complete miscibility.
Polar Molecules
Polar molecules are those in which there is an uneven distribution of electron density, leading to regions of positive and negative charge. This is typically due to the presence of polar bonds, where electrons are shared unequally between atoms. Water and glycerol are classic examples.

  • In water, the oxygen atom draws the shared electrons from hydrogen towards itself, resulting in a partial negative charge on the oxygen and a partial positive charge on the hydrogen atoms.
  • Glycerol, consisting of multiple hydroxyl groups, has similar polar characteristics where the electron-rich oxygen atoms contribute to its overall polarity.
These polar interactions make both water and glycerol compatible with substances that also have polar characteristics, leading to their miscibility. Polar substances tend to interact well through dipole-dipole interactions or hydrogen bonds, demonstrating the adage "like dissolves like."
Miscibility
Miscibility refers to the ability of two substances to mix and form a homogeneous solution. When two liquids are miscible, they dissolve in each other in all proportions. The concept of miscibility is vital when considering mixtures like water and glycerol.

  • The high degree of polarity in both water and glycerol, supported by their capacity for hydrogen bonding, allows them to be miscible. Their similar polarity means that they prefer to interact with each other rather than separating.
  • When dissolved, the molecules of these liquids freely intermingle due to their mutual attractions, forming a stable mixture that does not separate over time.
Unlike polar substances, nonpolar substances do not mix well with polar ones because they lack such interactions. The principle that "like dissolves like" highlights the importance of matching polarity and intermolecular forces to achieve miscibility.

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Most popular questions from this chapter

Are gases always miscible with each other? Explain. [Section 13.1]

By referring to Figure 13.15, determine whether the addition of \(40.0 \mathrm{~g}\) of each of the following ionic solids to \(100 \mathrm{~g}\) of water at \(40^{\circ} \mathrm{C}\) will lead to a saturated solution: (a) \(\mathrm{NaNO}_{3}\), (b) \(\mathrm{KCl}_{\text {, }}\) (c) \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\), (d) \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\)

At ordinary body temperature \(\left(37^{\circ} \mathrm{C}\right)\), the solubility of \(\mathrm{N}_{2}\) in water at ordinary atmospheric pressure ( \(1.0 \mathrm{~atm})\) is \(0.015 \mathrm{~g} / \mathrm{L}\). Air is approximately \(78 \mathrm{~mol} \% \mathrm{~N}_{2}\). (a) Calculate the number of moles of \(\mathrm{N}_{2}\) dissolved per liter of blood, assuming blood is a simple aqueous solution. (b) At a depth of \(100 \mathrm{ft}\) in water, the external pressure is \(4.0 \mathrm{~atm}\). What is the solubility of \(\mathrm{N}_{2}\) from air in blood at this pressure? (c) If a scuba diver suddenly surfaces from this depth, how many milliliters of \(\mathrm{N}_{2}\) gas, in the form of tiny bubbles, are released into the bloodstream from each liter of blood?

Oil and water are immiscible. Which is the most likely reason? (a) Oil molecules are denser than water. (b) Oil molecules are composed mostly of carbon and hydrogen. (c) Oil molecules have higher molar masses than water. (d) Oil molecules have higher vapor pressures than water. (e) Oil molecules have higher boiling points than water.

The presence of the radioactive gas radon \((\mathrm{Rn})\) in well water presents a possible health hazard in parts of the United States. (a) Assuming that the solubility of radon in water with 1 atm pressure of the gas over the water at \(30^{\circ} \mathrm{C}\) is \(7.27 \times 10^{-3} \mathrm{M}\), what is the Henry's law constant for radon in water at this temperature? (b) A sample consisting of various gases contains \(3.5 \times 10^{-6}\) mole fraction of radon. This gas at a total pressure of 32 atm is shaken with water at \(30^{\circ} \mathrm{C}\). Calculate the molar concentration of radon in the water.

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