Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Classify each of the following statements as true or false: (a) Although both molecular solids and covalent-network solids have covalent bonds, the melting points of molecular solids are much lower because their covalent bonds are much weaker. (b) Other factors being equal, highly symmetric molecules tend to form solids with higher melting points than asymmetrically shaped molecules.

Short Answer

Expert verified
(a) False. The lower melting points of molecular solids compared to covalent-network solids are due to the weaker intermolecular forces in molecular solids, not weaker covalent bonds. (b) True. Highly symmetric molecules generally form solids with higher melting points due to their more efficient packing in the crystalline lattice, leading to stronger molecular interactions.

Step by step solution

01

Statement (a) Analysis

To classify statement (a) as true or false, we need to understand the difference between molecular solids and covalent-network solids, as well as the effect of bond strength on melting points. Molecular solids are formed by weak intermolecular forces (such as dipole-dipole, London dispersion, and hydrogen bonding), while covalent-network solids have a continuous network of covalent bonds between their atoms. The key point is that molecular solids have weaker intermolecular forces, whereas covalent-network solids have strong covalent bonds. Let's analyze the given statement. (a) Although both molecular solids and covalent-network solids have covalent bonds, the melting points of molecular solids are much lower because their covalent bonds are much weaker.
02

Statement (a) Classification

The given statement (a) is false. The melting points of molecular solids are much lower than those of covalent-network solids, but this is not because their covalent bonds are weaker. The difference in melting points is due to the weak intermolecular forces in molecular solids compared to the strong covalent bonds in covalent-network solids.
03

Statement (b) Analysis

To classify statement (b) as true or false, we need to understand the effect of molecular symmetry on the melting points of solids. Highly symmetric molecules can pack more efficiently in a crystalline lattice, leading to stronger interactions between the molecules and higher melting points. Asymmetric molecules generally cannot pack as efficiently, resulting in weaker interactions and lower melting points. Let's analyze the given statement. (b) Other factors being equal, highly symmetric molecules tend to form solids with higher melting points than asymmetrically shaped molecules.
04

Statement (b) Classification

The given statement (b) is true. When other factors are equal, highly symmetric molecules do tend to form solids with higher melting points because they can pack more efficiently in the crystalline lattice, leading to stronger molecular interactions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The rutile and fluorite structures, shown here (anions are colored green), are two of the most common structure types of ionic compounds where the cation to anion ratio is \(1: 2\). (a) For \(\mathrm{CaF}_{2}\) and \(\mathrm{ZnF}_{2}\) use ionic radii, \(\mathrm{Ca}^{2+}(r=1.14 \mathrm{~A}), \mathrm{Zn}^{2+}(r=0.88 \mathrm{~A})\), and \(\mathrm{F}(r=1.19 \mathrm{~A})\), to predict which compound is more likely to crystallize with the fluorite structure and which with the rutile structure. (b) What are the coordination numbers of the cations and anions in each of these structures?

State whether each sentence is true or false: (a) Metals have high electrical conductivities because the electrons in the metal are delocalized. (b) Metals have high electrical conductivities because they are denser than other solids. (c) Metals have large thermal conductivities because they expand when heated. (d) Metals have small thermal conductivities because the delocalized electrons cannot easily transfer the kinetic energy imparted to the metal from heat.

For each of the following pairs of semiconductors, which one will have the larger band gap: (a) InP or InAs, (b) Ge or AIP, (c) AgI or CdTe?

Introduction of carbon into a metallic lattice generally results in a harder, less ductile substance with lower electrical and thermal conductivities. Explain why this might be so.

The coordination number for \(\mathrm{Mg}^{2+}\) ion is usually six. Assuming this assumption holds, determine the anion coordination number in the following compounds: (a) \(\mathrm{MgS}_{\text {, }}\) (b) \(\mathrm{MgF}_{2}\), (c) \(\mathrm{MgO}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free