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(a) What is the significance of the critical point in a phase diagram? (b) Why does the line that separates the gas and liquid phases end at the critical point?

Short Answer

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(a) The critical point in a phase diagram refers to the unique combination of temperature and pressure where the liquid phase and the gas phase become identical, and their physical properties become the same. This phenomenon is known as phase coexistence. Beyond the critical point, a single-phase called the supercritical fluid exists, which has properties of both liquids and gases. (b) The line that separates the gas and liquid phases in a phase diagram is called the vaporization curve or vapor-liquid equilibrium curve. It ends at the critical point because, at this point, the attractive forces between particles are no longer sufficient to keep them in the liquid state but still allow them to remain in a fluid state. The critical point represents the saturation pressure and temperature at which the gas and liquid phases can no longer be distinguished, resulting in the substance existing solely as a supercritical fluid.

Step by step solution

01

Part (a): Significance of the critical point

A critical point in a phase diagram refers to the unique combination of temperature and pressure at which the distinction between liquid and gaseous phases vanishes. At this point, the liquid phase and the gas phase become identical, and their physical properties like density and viscosity become the same. This phenomenon is known as phase coexistence. Beyond the critical point, we can only observe a single-phase called the supercritical fluid. Supercritical fluids exhibit properties of both liquids and gases, which is useful in various industries as solvents for chemical reactions.
02

Part (b): The line that separates gas and liquid phases ends at the critical point

The line that separates the gas and liquid phases in a phase diagram is called the vaporization curve or vapor-liquid equilibrium curve. This curve helps us understand the equilibrium behavior of substances when they are subjected to different pressure and temperature conditions. When we move along this curve, the system is at equilibrium, which means that both liquid and gas phases coexist. As we reach the critical point, phase boundaries disappear due to the fusion of gas and liquid phases into a supercritical fluid. This occurrence is caused by the change of the substance's properties, particularly the van der Waals forces which hold particles together in a liquid phase. At the critical point, the attractive forces are not strong enough to keep particles in a liquid state exclusively, but spatial proximity allows the particles to move closer and remain in a fluid state. The critical point represents the saturation pressure and temperature at which gas and liquid phases can no longer be distinguished. As a result, the line separating the gas and liquid phases ends at the critical point, and beyond that point, the substance exists solely as a supercritical fluid.

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Most popular questions from this chapter

One of the attractive features of ionic liquids is their low vapor pressure, which in turn tends to make them nonflammable. Why do you think ionic liquids have lower vapor pressures than most room-temperature molecular liquids?

(a) Place the following substances in order of increasing volatility: \(\mathrm{CH}_{4}, \mathrm{CBr}_{4}, \mathrm{CH}_{2} \mathrm{Cl}_{2}, \mathrm{CH}_{3} \mathrm{Cl}, \mathrm{CHBr}_{3}\), and \(\mathrm{CH}_{2} \mathrm{Br}_{2}\). (b) How do the boiling points vary through this series? (c) Explain your answer to part (b) in terms of intermolecular forces.

(a) What atoms must a molecule contain to participate in hydrogen bonding with other molecules of the same kind? (b) Which of the following molecules can form hydrogen bonds with other molecules of the same kind: \(\mathrm{CH}_{3} \mathrm{~F}_{,} \mathrm{CH}_{3} \mathrm{NH}_{2}, \mathrm{CH}_{3} \mathrm{OH}, \mathrm{CH}_{3} \mathrm{Br} ?\)

At standard temperature and pressure the molar volumes of \(\mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) gases are \(22.06\) and \(22.40 \mathrm{~L}\), respectively. (a) Given the different molecular weights, dipole moments, and molecular shapes, why are their molar volumes nearly the same? (b) On cooling to \(160 \mathrm{~K}\), both substances form crystalline solids. Do you expect the molar volumes to decrease or increase on cooling the gases to \(160 \mathrm{~K}\) ? (c) The densities of crystalline \(\mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) at \(160 \mathrm{~K}\) are \(2.02\) and \(0.84 \mathrm{~g} / \mathrm{cm}^{3}\), respectively. Calculate their molar volumes. (d) Are the molar volumes in the solid state as similar as they are in the gaseous state? Explain. (e) Would you expect the molar volumes in the liquid state to be closer to those in the solid or gaseous state?

Based on the type or types of intermolecular forces, predict the substance in each pair that has the higher boiling point: (a) propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) or \(n\)-butane \(\left(\mathrm{C}_{4} \mathrm{H}_{10}\right)\), (b) diethyl ether \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3}\right)\) or 1-butanol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\), (c) sulfur dioxide \(\left(\mathrm{SO}_{2}\right)\) or sulfur trioxide \(\left(\mathrm{SO}_{3}\right)\), (d) phosgene \(\left(\mathrm{Cl}_{2} \mathrm{CO}\right)\) or formaldehyde \(\left(\mathrm{H}_{2} \mathrm{CO}\right)\).

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