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Compounds like \(\mathrm{CCl}_{2} \mathrm{~F}_{2}\) are known as chlorofluorocarbons, or CFCs. These compounds were once widely used as refrigerants but are now being replaced by compounds that are believed to be less harmful to the environment. The heat of vaporization of \(\mathrm{CCl}_{2} \mathrm{~F}_{2}\) is \(289 \mathrm{~J} / \mathrm{g}\). What mass of this substance must evaporate to freeze \(200 \mathrm{~g}\) of water initially at \(15^{\circ} \mathrm{C}\) ? (The heat of fusion of water is \(334 \mathrm{~J} / \mathrm{g}\); the specific heat of water is \(4.18 \mathrm{~J} / \mathrm{g}-\mathrm{K}\).)

Short Answer

Expert verified
Approximately 187.75 grams of CCl2F2 must evaporate to freeze 200 grams of water initially at 15ºC.

Step by step solution

01

Calculate the heat to cool the water to 0ºC

We can use the specific heat formula to find the heat required to cool the water to 0ºC: Q = mcΔT where Q is the heat, m is the mass of the water (200g), c is the specific heat of the water (4.18 J/g-K), and ΔT is the temperature change (0ºC - 15ºC). Q = (200 g)(4.18 J/g-K)(-15 K) Q = -12540 J
02

Calculate the heat to freeze the water at 0ºC

We can use the heat of fusion formula to find the heat required to freeze the water at 0ºC: Q = mLf where m is the mass of the water (200g) and Lf is the heat of fusion for water (334 J/g). Q = (200 g)(334 J/g) Q = 66800 J
03

Sum the heat required in both steps

Now, we sum the heat required to cool the water and the heat required to freeze it: Total heat (Q_total) = Q1 + Q2 = -12540 J + 66800 J = 54260 J
04

Calculate the mass of CCl2F2 that must evaporate to absorb the total heat

Finally, we can find the mass of CCl2F2 that must evaporate by using the heat of vaporization formula: Q = mLv where m is the mass of the CCl2F2 we need to find, and Lv is the heat of vaporization for CCl2F2 (289 J/g). 54260 J = m(289 J/g) To find the mass of CCl2F2, we can rearrange the equation and solve for m: m = 54260 J / 289 J/g m ≈ 187.75 g So, approximately 187.75 grams of CCl2F2 must evaporate to freeze 200 grams of water initially at 15ºC.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chlorofluorocarbons
Chlorofluorocarbons, or CFCs, are a group of organic compounds that contain carbon, chlorine, and fluorine atoms. These compounds are notably used in refrigeration, air conditioning, and as propellants in aerosol sprays in the past. However, CFCs have been found to contribute significantly to ozone layer depletion, a crucial component of the Earth's atmosphere that protects living organisms from harmful ultraviolet radiation.
Environmental concerns have led to regulations phasing out the use of CFCs. Alternatives, such as hydrochlorofluorocarbons (HCFCs) and hydrofluorocarbons (HFCs), which are less ozone-depleting, are now replacing CFCs.
Understanding the environmental impact of these compounds is essential for making responsible choices in chemical manufacturing and usage. Initiatives and international agreements, like the Montreal Protocol, have been instrumental in addressing the harmful effects of CFCs on the ozone layer.
Heat of Vaporization
When a substance changes from liquid to gas, it absorbs a precise amount of heat energy without changing its temperature. This energy is called the heat of vaporization. It is crucial in processes where energy transfers during phase changes, like in refrigeration cycles.
For chlorofluorocarbon \(\text{CCl}_2\text{F}_2\), the heat of vaporization is given as 289 J/g. This means that every gram of this substance requires 289 joules of energy to convert from liquid to gas at its boiling point.
For practical applications, knowing the heat of vaporization helps in calculating the energy required for processes involving evaporation. For example, in the exercise, it helps determine how much \(\text{CCl}_2\text{F}_2\) must evaporate to absorb enough heat to freeze water.
Heat of Fusion
The heat of fusion is the amount of energy necessary to change a substance from solid to liquid at its melting point. For ice, specifically, it indicates the energy required to melt ice into water at 0°C.
In this problem, the heat of fusion for water is given as 334 J/g. It tells us that 334 joules are needed for each gram of ice to melt. Similarly, when freezing water, the same amount of energy must be released.
Understanding the heat of fusion is important for calculating the energy involved in phase transitions. In our example, it ensures accurate calculations of how much energy is required to freeze 200 grams of water starting at 15ºC. This calculation is necessary to determine how much \(\text{CCl}_2\text{F}_2\) needs to evaporate.
Specific Heat Capacity
Specific heat capacity is the amount of heat required to raise the temperature of one gram of a substance by one degree Celsius or Kelvin. It is a property unique to each material and is crucial in thermodynamic calculations.
The specific heat capacity of water is 4.18 J/g-K, indicating that raising one gram of water by 1ºC requires 4.18 joules of energy. This property is essential in understanding how materials react to heat changes.
In this exercise, the specific heat capacity helps calculate the energy removed from water as it cools from 15ºC to 0ºC. Understanding this concept allows for accurate determination of total energy involved in cooling and freezing processes, key for deciding how much \(\text{CCl}_2\text{F}_2\) must evaporate to facilitate these changes.

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Most popular questions from this chapter

Acetone \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\right]\) is widely used as an industrial solvent. (a) Draw the Lewis structure for the acetone molecule and predict the geometry around each carbon atom. (b) Is the acetone molecule polar or nonpolar? (c) What kinds of intermolecular attractive forces exist between acetone molecules? (d) 1-Propanol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\) has a molecular weight that is very similar to that of acetone, yet acetone boils at \(56.5^{\circ} \mathrm{C}\) and 1 -propanol boils at \(97.2^{\circ} \mathrm{C}\). Explain the difference.

Suppose the vapor pressure of a substance is measured at two different temperatures. (a) By using the ClausiusClapeyron equation (Equation 11.1) derive the following relationship between the vapor pressures, \(P_{1}\) and \(P_{2}\), and the absolute temperatures at which they were measured, \(T_{1}\) and \(T_{2}:\) $$ \ln \frac{P_{1}}{P_{2}}=-\frac{\Delta H_{\text {vap }}}{R}\left(\frac{1}{T_{1}}-\frac{1}{T_{2}}\right) $$ (b) Gasoline is a mixture of hydrocarbons, a major component of which is octane \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\right)\). Octane has a vapor pressure of \(13.95\) torr at \(25^{\circ} \mathrm{C}\) and a vapor pressure of \(144.78\) torr at \(75^{\circ} \mathrm{C}\). Use these data and the equation in part (a) to calculate the heat of vaporization of octane. (c) By using the equation in part (a) and the data given in part (b), calculate the normal boiling point of octane. Compare your answer to the one you obtained from Exercise 11.80. (d) Calculate the vapor pressure of octane at \(-30^{\circ} \mathrm{C}\).

The boiling points, surface tensions, and viscosities of water and several alcohols are as follows: (a) For ethanol, propanol, and \(n\)-butanol the boiling points, surface tensions, and viscosities all increase. What is the reason for this increase? (b) How do you explain the fact that propanol and ethylene glycol have similar molecular weights ( 60 versus \(62 \mathrm{amu}\) ), yet the viscosity of ethylene glycol is more than 10 times larger than propanol? (c) How do you explain the fact that water has the highest surface tension but the lowest viscosity?

As the intermolecular attractive forces between molecules increase in magnitude, do you expect each of the following to increase or decrease in magnitude? (a) Vapor pressure, (b) heat of vaporization, (c) boiling point, (d) freezing point, (e) viscosity, (f) surface tension, (g) critical temperature.

(a) When you exercise vigorously, you sweat. How does this help your body cool? (b) A flask of water is connected to a vacuum pump. A few moments after the pump is turned on, the water begins to boil. After a few minutes, the water begins to freeze. Explain why these processes occur.

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