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The following quote about ammonia \(\left(\mathrm{NH}_{3}\right)\) is from a textbook of inorganic chemistry: "It is estimated that \(26 \%\) of the hydrogen bonding in \(\mathrm{NH}_{3}\) breaks down on melting, \(7 \%\) on warming from the melting to the boiling point, and the final \(67 \%\) on transfer to the gas phase at the boiling point." From the standpoint of the kinetic energy of the molecules, explain (a) why there is a decrease of hydrogen-bonding energy on melting and (b) why most of the loss in hydrogen bonding occurs in the transition from the liquid to the vapor state.

Short Answer

Expert verified
When ammonia melts, the kinetic energy of the molecules increases as they can move more freely in the liquid state compared to the solid state. This increase in kinetic energy allows for some hydrogen bonding to be overcome, resulting in a decrease in hydrogen bonding energy (26% during melting). As ammonia transitions from a liquid to a gas, the kinetic energy of the molecules further increases, providing even more freedom to move and overcome a larger portion of hydrogen bonding. In this phase, 67% of the hydrogen bonding breaks down, causing most of the loss in hydrogen bonding to occur during the transition from liquid to vapor state.

Step by step solution

01

Understanding kinetic energy and hydrogen bonding

Kinetic energy refers to the energy possessed by an object due to its motion. In the case of ammonia, this refers to the energy of the molecules as they move. Hydrogen bonding is a type of intermolecular force that occurs between molecules containing hydrogen atoms bonded to highly electronegative atoms (such as nitrogen in NH₃). These forces cause the molecules to stick together, and they need to be overcome for a substance to change its state (e.g., from liquid to gas). Now, let's use this understanding to explain the observations in the exercise.
02

Explaining the decrease of hydrogen-bonding energy on melting

When ammonia melts, meaning it transitions from a solid to a liquid state, the kinetic energy of the molecules increases. This is because in the liquid state, the molecules can move more freely compared to the solid state. The increase in kinetic energy allows the molecules to overcome some of the hydrogen bonding, causing a decrease in hydrogen bonding energy. Therefore, 26% of the hydrogen bonding breaks down during the melting process.
03

Explaining the loss of hydrogen bonding in transition from liquid to vapor state

As ammonia transitions from a liquid state to a vapor (gas) state, the kinetic energy of the molecules further increases. In the gas phase, the molecules have even more freedom to move compared to the liquid state, allowing them to overcome a larger portion of the hydrogen bonding. This is why 67% of the hydrogen bonding breaks down during the transition from liquid to vapor state, making it the phase where most of the loss in hydrogen bonding occurs. Overall, the increase in kinetic energy as ammonia changes from different states allows the molecules to overcome hydrogen bonding to various extents, which explains the given observations about hydrogen bonding in ammonia.

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Most popular questions from this chapter

Name the phase transition in each of the following situations and indicate whether it is exothermic or endothermic: (a) Bromine vapor turns to bromine liquid as it is cooled. (b) Crystals of iodine disappear from an evaporating dish as they stand in a fume hood. (c) Rubbing alcohol in an open container slowly disappears. (d) Molten lava from a volcano turns into solid rock.

Based on the type or types of intermolecular forces, predict the substance in each pair that has the higher boiling point: (a) propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) or \(n\)-butane \(\left(\mathrm{C}_{4} \mathrm{H}_{10}\right)\), (b) diethyl ether \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3}\right)\) or 1-butanol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\), (c) sulfur dioxide \(\left(\mathrm{SO}_{2}\right)\) or sulfur trioxide \(\left(\mathrm{SO}_{3}\right)\), (d) phosgene \(\left(\mathrm{Cl}_{2} \mathrm{CO}\right)\) or formaldehyde \(\left(\mathrm{H}_{2} \mathrm{CO}\right)\).

(a) What is the relationship between surface tension and temperature? (b) What is the relationship between viscosity and temperature? (c) Why do substances with high surface tension also tend to have high viscosities?

(a) What is the significance of the critical point in a phase diagram? (b) Why does the line that separates the gas and liquid phases end at the critical point?

(a) What atoms must a molecule contain to participate in hydrogen bonding with other molecules of the same kind? (b) Which of the following molecules can form hydrogen bonds with other molecules of the same kind: \(\mathrm{CH}_{3} \mathrm{~F}_{,} \mathrm{CH}_{3} \mathrm{NH}_{2}, \mathrm{CH}_{3} \mathrm{OH}, \mathrm{CH}_{3} \mathrm{Br} ?\)

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