Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A match is lit and held under a cold piece of metal. The following observations are made: (a) The match burns. (b) The metal gets warmer. (c) Water condenses on the metal. (d) Soot (carbon) is deposited on the metal. Which of these occurrences are due to physical changes, and which are due to chemical changes?

Short Answer

Expert verified
Observations (a) and (d) are chemical changes as they involve the formation of new substances. In (a), the match burns, forming water vapor and carbon dioxide, and in (d), soot (carbon) is deposited on the metal. Observations (b) and (c) are physical changes, as the metal getting warmer and water condensing on the metal do not involve the formation of new substances.

Step by step solution

01

Observation (a): The match burns

Burning is a chemical change as it involves the formation of new substances. In this case, when the match burns, it reacts with oxygen in the air and forms water vapor and carbon dioxide, both of which are new substances with different properties from the original match.
02

Observation (b): The metal gets warmer

The metal getting warmer is a physical change. This is because no new substances are formed, and the changes in temperature are only temporary. The identity of the metal remains the same, it just has more energy in the form of heat.
03

Observation (c): Water condenses on the metal

Water condensation on the metal is a physical change. This is because the water is simply changing states (from gas to liquid) due to the temperature difference between the metal and the surrounding air. The identity of the water does not change in this process.
04

Observation (d): Soot (carbon) is deposited on the metal

Soot deposition is a chemical change. During the combustion of the match, carbon is produced as a byproduct, and this is deposited onto the metal. Carbon is a new substance with different properties from the original match and oxygen in the air, thus, it is a chemical change. In summary, Observations (a) and (d) are chemical changes, while Observations (b) and (c) are physical changes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use appropriate metric prefixes to write the following measurements without use of exponents: (a) \(2.3 \times 10^{-10} \mathrm{~L}\), (b) \(4.7 \times 10^{-6} \mathrm{~g}\), (c) \(1.85 \times 10^{-12} \mathrm{~m}\), (d) \(16.7 \times 10^{6} \mathrm{~s}\), (e) \(15.7 \times 10^{3} \mathrm{~g}\), (f) \(1.34 \times 10^{-3} \mathrm{~m}\), (g) \(1.84 \times 10^{2} \mathrm{~cm}\)

Gold is alloyed (mixed) with other metals to increase its hardness in making jewelry. (a) Consider a piece of gold jewelry that weighs \(9.85 \mathrm{~g}\) and has a volume of \(0.675 \mathrm{~cm}^{3}\). The jewelry contains only gold and silver, which have densities of \(19.3\) and \(10.5 \mathrm{~g} / \mathrm{cm}^{3}\), respectively. If the total volume of the jewelry is the sum of the volumes of the gold and silver that it contains, calculate the percentage of gold (by mass) in the jewelry. (b) The relative amount of gold in an alloy is commonly expressed in units of carats. Pure gold is 24 carat, and the percentage of gold in an alloy is given as a percentage of this value. For example, an alloy that is \(50 \%\) gold is 12 carat. State the purity of the gold jewelry in carats.

The distance from Earth to the Moon is approximately \(240,000 \mathrm{mi}\). (a) What is this distance in meters? (b) The peregrine falcon has been measured as traveling up to \(350 \mathrm{~km} /\) \(\mathrm{hr}\) in a dive. If this falcon could fly to the Moon at this speed, how many seconds would it take? (c) The speed of light is \(3.00 \times 10^{8} \mathrm{~m} / \mathrm{s}\). How long does it take for light to travel from Earth to the Moon and back again? (d) Earth travels around the Sun at an average speed of \(29.783 \mathrm{~km} / \mathrm{s}\). Convert this speed to miles per hour.

Perform the following conversions: (a) \(5.00\) days to \(\mathrm{s}\), (b) \(0.0550 \mathrm{mi}\) to \(\mathrm{m}\), (c) \(\$ 1.89 / \mathrm{gal}\) to dollars per liter, (d) \(0.510 \mathrm{in} . / \mathrm{ms}\) to \(\mathrm{km} / \mathrm{hr}\), (e) \(22.50 \mathrm{gal} / \mathrm{min}\) to \(\mathrm{L} / \mathrm{s}\), (f) \(0.02500 \mathrm{ft}^{3}\) to \(\mathrm{cm}^{3}\).

The total rate at which power used by humans worldwide is approximately \(15 \mathrm{TW}\) (terawatts). The solar flux averaged over the sunlit half of Earth is \(680 \mathrm{~W} / \mathrm{m}^{2}\). (assuming no clouds). The area of Earth's disc as seen from the sun is \(1.28 \times 10^{14} \mathrm{~m}^{2}\). The surface area of Earth is approximately \(197,000,000\) square miles. How much of Earth's surface would we need to cover with solar energy collectors to power the planet for use by all humans? Assume that the solar energy collectors can convert only \(10 \%\) of the available sunlight into useful power.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free