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(a) What is the difference between hybrid orbitals and molecular orbitals? (b) How many electrons can be placed into each MO of a molecule? (c) Can antibonding molecular orbitals have electrons in them?

Short Answer

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(a) Hybrid orbitals are mixtures of atomic orbitals within an atom to achieve a more stable bonding configuration, while molecular orbitals are formed by the overlap of atomic orbitals from different atoms, resulting in bonding or antibonding orbitals. (b) Each molecular orbital can hold a maximum of two electrons, following the Pauli Exclusion Principle. (c) Yes, antibonding molecular orbitals can have electrons in them, but they weaken the bond between atoms and electrons will first fill up the lower-energy bonding orbitals before occupying antibonding molecular orbitals.

Step by step solution

01

(a) Difference between hybrid orbitals and molecular orbitals

Hybrid orbitals and molecular orbitals are two different concepts in chemistry that help explain the bonding and arrangement of atoms in molecules. Hybrid orbitals are mixtures of atomic orbitals within an atom. This mixing or hybridization happens when atomic orbitals with similar energy levels combine to form new orbitals with a hybrid character. The purpose of the hybridization is to achieve a more stable configuration for bonding with other atoms. Molecular orbitals, on the other hand, are formed by the overlap of atomic orbitals from different atoms. They are mathematical functions used to describe the spatial distribution and behavior of electrons in a molecule. When atomic orbitals overlap, they form molecular orbitals that can be either bonding or antibonding, depending on the type of overlap.
02

(b) Number of electrons in each MO of a molecule

Each molecular orbital (MO) can hold a maximum of two electrons, following the Pauli Exclusion Principle. The principle states that no two electrons in a molecule can have the same set of quantum numbers. Therefore each molecular orbital can accommodate two electrons having opposite spins.
03

(c) Antibonding molecular orbitals having electrons

Yes, antibonding molecular orbitals can have electrons in them. Antibonding molecular orbitals have a higher energy state than the bonding molecular orbitals and are formed due to the out-of-phase or destructive combination of atomic orbitals from different atoms. When electrons populate the antibonding molecular orbitals, they weaken the bond between the atoms and increase its energy. If the number of electrons in bonding and antibonding orbitals is equal, the bond order becomes zero, and no bond is formed between the atoms. Generally, electrons will first fill up the lower-energy bonding orbitals before occupying antibonding molecular orbitals.

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Most popular questions from this chapter

The phosphorus trihalides \(\left(\mathrm{PX}_{3}\right)\) show the following variation in the bond angle \(\mathrm{X}-\mathrm{P}-\mathrm{X}: \mathrm{PF}_{3}, 96.3^{\circ} ; \mathrm{PCl}_{3}, 100.3^{\circ} ; \mathrm{PBr}_{3}\), \(101.0^{\circ} ; \mathrm{PI}_{3}, 102.0^{\circ} .\) The trend is generally attributed to the change in the electronegativity of the halogen. (a) Assuming that all electron domains are the same size, what value of the \(\mathrm{X}-\mathrm{P}-\mathrm{X}\) angle is predicted by the VSEPR model? (b) What is the general trend in the \(\mathrm{X}-\mathrm{P}-\mathrm{X}\) angle as the halide electronegativity increases? (c) Using the VSEPR model, explain the observed trend in \(\mathrm{X}-\mathrm{P}-\mathrm{X}\) angle as the electronegativity of \(X\) changes. (d) Based on your answer to part (c), predict the structure of \(\mathrm{PBrCl}_{4}\).

How does a trigonal pyramid differ from a tetrahedron so far as molecular geometry is concerned?

(a) Explain why \(\mathrm{BrF}_{4}^{-}\) is square planar, whereas \(\mathrm{BF}_{4}^{-}\) is tetrahedral. (b) How would you expect the \(\mathrm{H}-\mathrm{X}-\mathrm{H}\) bond angle to vary in the series \(\mathrm{H}_{2} \mathrm{O}, \mathrm{H}_{2} \mathrm{~S}, \mathrm{H}_{2} \mathrm{Se}\) ? Explain. (Hint: The size of an electron pair domain depends in part on the electronegativity of the central atom.)

Why are there no \(s p^{4}\) or \(s p^{5}\) hybrid orbitals?

The lactic acid molecule, \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH},\) gives sour milk its unpleasant, sour taste. (a) Draw the Lewis structure for the molecule, assuming that carbon always forms four bonds in its stable compounds. (b) How many \(\pi\) and how many \(\sigma\) bonds are in the molecule? (c) Which CO bond is shortest in the molecule? (d) What is the hybridization of atomic orbitals around the carbon atom associated with that short bond? (e) What are the approximate bond angles around each carbon atom in the molecule?

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