Chapter 7: Problem 81
Write a balanced equation for the reaction that occurs in each of the following cases: (a) Ozone decomposes to dioxygen. (b) Xenon reacts with fluorine. (Write three different equations.) (c) Sulfur reacts with hydrogen gas. (d) Fluorine reacts with water.
Short Answer
Expert verified
a) 2O3 → 3O2
b)
1) Xe + 3F2 → XeF6
2) Xe + 2F2 → XeF4
3) Xe + F2 → XeF2
c) S + H2 → H2S
d) F2 + 2H2O → 4HF + O2
Step by step solution
01
Write unbalanced equation
Ozone (O3) decomposes to dioxygen (O2), which can be written as:
O3 → O2
02
Balance the equation
In order to balance the equation, we need two molecules of ozone decomposing to three molecules of dioxygen, so the balanced equation is:
2O3 → 3O2
b) Xenon reacts with fluorine (Three different equations).
03
Write unbalanced equations
Xenon can react with fluorine to form three different xenon fluorides: Xenon hexafluoride (XeF6), xenon tetrafluoride (XeF4), and xenon difluoride (XeF2). The three unbalanced reactions are:
1) Xe + F2 → XeF6
2) Xe + F2 → XeF4
3) Xe + F2 → XeF2
04
Balance the equations
To balance these three reactions, we must adjust the stoichiometric coefficients like this:
1) Xe + 3F2 → XeF6
2) Xe + 2F2 → XeF4
3) Xe + F2 → XeF2
c) Sulfur reacts with hydrogen gas.
05
Write unbalanced equation
Sulfur (S) reacts with hydrogen gas (H2) to form hydrogen sulfide (H2S), which can be written as:
S + H2 → H2S
06
Balance the equation
In order to balance the equation, we need two hydrogen atoms for every one sulfur atom. The balanced equation is:
S + H2 → H2S
d) Fluorine reacts with water.
07
Write unbalanced equation
Fluorine (F2) reacts with water (H2O) to form hydrogen fluoride (HF) and oxygen gas (O2), which can be written as:
F2 + H2O → HF + O2
08
Balance the equation
In order to balance the equation, we must have four atoms of hydrogen, two atoms of oxygen and two atoms of fluorine on both sides. So, the balanced equation is:
F2 + 2H2O → 4HF + O2
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Balancing Equations
Balancing chemical equations is all about ensuring that the number of atoms for each element is the same on both sides of the reaction. This makes sure that mass is conserved during the reaction, a fundamental principle in chemistry.
To balance an equation, follow these steps:
\( \text{O}_3 \rightarrow \text{O}_2 \).
In this case, you will balance it by adding a coefficient of 2 before \( \text{O}_3 \) and a 3 before \( \text{O}_2 \) resulting in:
\( 2\text{O}_3 \rightarrow 3\text{O}_2 \). This shows that 2 ozone molecules decompose into 3 dioxygen molecules.
To balance an equation, follow these steps:
- Write the unbalanced equation.
- Count the number of each type of atom on both sides of the equation.
- Add coefficients to the compounds to equalize the number of atoms per element on each side.
- Double-check your work to ensure mass is conserved.
\( \text{O}_3 \rightarrow \text{O}_2 \).
In this case, you will balance it by adding a coefficient of 2 before \( \text{O}_3 \) and a 3 before \( \text{O}_2 \) resulting in:
\( 2\text{O}_3 \rightarrow 3\text{O}_2 \). This shows that 2 ozone molecules decompose into 3 dioxygen molecules.
Stoichiometry
Stoichiometry is the exciting process of using balanced equations to determine the quantitative relationships between reactants and products in a chemical reaction. It is crucial because it allows chemists to predict how much of a substance is needed or produced in a given reaction.
For example, in the balanced reaction between xenon and fluorine to form XeF6: \( \text{Xe} + 3\text{F}_2 \rightarrow \text{XeF}_6 \), you can see that 1 mole of xenon reacts with 3 moles of fluorine to produce 1 mole of xenon hexafluoride. From here, stoichiometry can help calculate the amounts of each reactant required to obtain a specified amount of product, and vice versa.
A helpful tip is to always use the mole ratio from the balanced equation to convert between different chemical species.
For example, in the balanced reaction between xenon and fluorine to form XeF6: \( \text{Xe} + 3\text{F}_2 \rightarrow \text{XeF}_6 \), you can see that 1 mole of xenon reacts with 3 moles of fluorine to produce 1 mole of xenon hexafluoride. From here, stoichiometry can help calculate the amounts of each reactant required to obtain a specified amount of product, and vice versa.
A helpful tip is to always use the mole ratio from the balanced equation to convert between different chemical species.
Reaction Types
Understanding different types of chemical reactions can help in predicting the outcomes and behavior of reactions. Here are some common types:
Moreover, recognizing the reaction type helps in balancing the equation and predicting the direction and products of the reaction.
- Decomposition Reaction: A single compound breaks down into simpler substances, like the decomposition of ozone to dioxygen.
- Synthesis Reaction: Simple substances combine to form a more complex compound, like sulfur reacting with hydrogen to produce hydrogen sulfide.
- Single Replacement Reaction: An element replaces a similar element in a compound.
- Double Replacement Reaction: Two compounds exchange partners to form two new compounds.
Moreover, recognizing the reaction type helps in balancing the equation and predicting the direction and products of the reaction.