Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Does the reactivity of a metal correlate with its first ionization energy? Explain.

Short Answer

Expert verified
In conclusion, there is an inverse relationship between a metal's reactivity and its first ionization energy. Reactive metals, such as alkali and alkaline earth metals, have low ionization energies, which allows them to lose electrons more easily and be more reactive in chemical reactions. On the other hand, metals with higher ionization energies, such as transition metals, are generally less reactive. This trend can be observed within groups and periods in the periodic table.

Step by step solution

01

Defining Reactivity

Reactivity refers to how quickly and easily a substance undergoes a chemical reaction. In this case, we're focused on metals, so we'll consider how quickly and easily a metal reacts with other substances. Reactive metals, like alkali metals, tend to lose electrons easily and form cations (positively charged ions).
02

Defining Ionization Energy

Ionization energy is the energy required to remove an electron from an atom or ion. The first ionization energy refers to the energy needed to remove the outermost electron in a neutral atom to form a cation (positively charged ion). Generally, ionization energies decrease down a group in the periodic table and increase across a period.
03

Relationship between Reactivity and Ionization Energy

There is an inverse relationship between the reactivity of a metal and its first ionization energy. Reactive metals tend to have low first ionization energies. This means they can lose their outermost electrons more easily, and as a result, form positive ions readily, which leads to a higher reactivity. On the other hand, metals with higher ionization energies have a more difficult time losing electrons and therefore are less reactive.
04

Examples of Metals and their Reactivity

To further illustrate this relationship, let's look at some examples: 1. Alkali metals (Group 1 elements): These metals, like lithium (Li), sodium (Na), and potassium (K), are highly reactive due to their low ionization energies. They lose their single outer electron easily, forming a +1 cation. 2. Alkaline Earth metals (Group 2 elements): These metals, like magnesium (Mg) and calcium (Ca), have slightly higher ionization energies than alkali metals. As a result, they are still reactive but not as much as the alkali metals. They usually form a +2 cation. 3. Transition metals (Groups 3-12 elements): Metals from these groups, like iron (Fe) and copper (Cu), have relatively higher ionization energies and are less reactive compared to alkali and alkaline earth metals. In conclusion, there is an inverse relationship between a metal's reactivity and its first ionization energy. Reactive metals have low ionization energies, allowing them to lose electrons easily and participate in chemical reactions more readily. This trend can be observed within the periodic table from groups and periods.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionization Energy
Ionization energy refers to the amount of energy required to remove an electron from an atom. It's an important concept because it helps us understand how strongly an atom holds onto its electrons. Usually, the first ionization energy is what people talk about most. This is the energy needed to remove the very first electron from a neutral atom.
In general, moving across a period from left to right in the periodic table, ionization energy increases. This is because atoms have more protons as you go across a period, resulting in a stronger attraction between the nucleus and electrons. Similarly, going down a group in the periodic table, ionization energy decreases.
Why do you ask? Well, atoms are getting larger down a group, meaning the outer electrons are further from the nucleus. This leads to a weaker attraction, allowing these electrons to be removed with less energy.
  • Know that: Higher ionization energy means the atom holds its electrons tightly.
  • Lower ionization energy suggests electrons are more easily lost.
Periodic Table
The periodic table is a systematic arrangement of elements, designed to group elements with similar properties together. This arrangement helps us predict the properties of elements, including their chemical reactivity and physical properties.
Elements are placed in rows, called periods, and columns, known as groups or families. As you move across a period from left to right, the atomic number increases, and generally, the ionization energy increases as well. This increase is because electrons are added to the same energy level, while protons are added to the nucleus, enhancing the attraction between the nucleus and electrons.
Going down a group, elements exhibit a decrease in ionization energy, as additional electron shells are added, making it easier for atoms to lose their outer electrons. This pattern is key when studying the reactivity of metals, which is linked to how easily they lose electrons.
  • The periodic table helps us predict reactivity based on position.
  • Reactive metals are typically found in specific groups, such as alkali metals.
Alkali Metals
Alkali metals belong to Group 1 of the periodic table and are known for their high reactivity. This group includes elements like lithium (Li), sodium (Na), and potassium (K). These metals are characterized by having a single electron in their outermost shell, which they can lose very easily to form a cation with a charge of +1.
The reactivity of alkali metals is primarily due to their low first ionization energies. Because it's quite easy for these metals to lose their outer electron, they tend to react quickly and vigorously, especially with substances like water.
  • Notably: As you move down the group, from lithium to cesium, the reactivity increases.
  • This occurs because the outer electron is further away from the nucleus in larger atoms, making it easier to lose.
In summary, alkali metals are excellent examples of the relationship between ionization energy and reactivity. Their position on the periodic table tells us that they are some of the most reactive metals, highlighting how useful the table is in predicting chemical behavior.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write balanced equations for the following reactions: (a) potassium oxide with water, (b) diphosphorus trioxide with water, (c) chromium(III) oxide with dilute hydrochloric acid, (d) selenium dioxide with aqueous potassium hydroxide.

One way to measure ionization energies is ultraviolet photoelectron spectroscopy (UPS, or just PES), a technique based on the photoelectric effect. coo (Section 6.2 ) In PES, monochromatic light is directed onto a sample, causing electrons to be emitted. The kinetic energy of the emitted electrons is measured. The difference between the energy of the photons and the kinetic energy of the electrons corresponds to the energy needed to remove the electrons (that is, the ionization energy). Suppose that a PES experiment is performed in which mercury vapor is irradiated with ultraviolet light of wavelength \(58.4 \mathrm{nm}\). (a) What is the energy of a photon of this light in eV? (b) Write an equation that shows the process corresponding to the first ionization energy of \(\mathrm{Hg}\). (c) The kinetic energy of the emitted electrons is measured to be \(10.75 \mathrm{eV}\). What is the first ionization energy of Hg in kJ/mol? (d) Using Figure 7.9 , determine which of the halogen elements has a first ionization energy closest to that of mercury.

(a) Write the electron configuration for \(\mathrm{Li}\), and estimate the effective nuclear charge experienced by the valence electron. (b) The energy of an electron in a one-electron atom or ion equals \(\left(-2.18 \times 10^{-18} \mathrm{~J}\right)\left(\frac{Z^{2}}{n^{2}}\right)\) where \(Z\) is the nuclear charge and \(n\) is the principal quantum number of the electron. Estimate the first ionization energy of Li. (c) Compare the result of your calculation with the value reported in Table 7.4 and explain the difference. (d) What value of the effective nuclear charge gives the proper value for the ionization energy? Does this agree with your explanation in \((\mathrm{c}) ?\)

Identify at least two ions that have the following ground-state electron configurations: (a) \([\mathrm{Ar}] ;\) (b) \([\mathrm{Ar}] 3 d^{5}\); (c) \([\mathrm{Kr}] 5 s^{2} 4 d^{10}\)

Zinc in its \(2+\) oxidation state is an essential metal ion for life. \(\mathrm{Zn}^{2+}\) is found bound to many proteins that are involved in biological processes, but unfortunately \(\mathrm{Zn}^{2+}\) is hard to detect by common chemical methods. Therefore, scientists who are interested in studying \(\mathrm{Zn}^{2+}\) -containing proteins will frequently substitute \(\mathrm{Cd}^{2+}\) for \(\mathrm{Zn}^{2+}\), since \(\mathrm{Cd}^{2+}\) is easier to detect. (a) On the basis of the properties of the elements and ions discussed in this chapter and their positions in the periodic table, describe the pros and cons of using \(\mathrm{Cd}^{2+}\) as a \(\mathrm{Zn}^{2+}\) substitute. (b) Proteins that speed up (catalyze) chemical reactions are called enzymes. Many enzymes are required for proper metabolic reactions in the body. One problem with using \(\mathrm{Cd}^{2+}\) to replace \(\mathrm{Zn}^{2+}\) in enzymes is that \(\mathrm{Cd}^{2+}\) substitution can decrease or even eliminate enzymatic activity. Can you suggest a different metal ion that might replace \(\mathrm{Zn}^{2+}\) in enzymes instead of \(\mathrm{Cd}^{2+} ?\) Justify your answer.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free