Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Using only the periodic table, arrange each set of atoms in order from largest to smallest: (a) \(\mathrm{K}, \mathrm{Li}, \mathrm{Cs} ;\) (b) \(\mathrm{Pb}, \mathrm{Sn}, \mathrm{Si} ;\) (c) \(\mathrm{F}, \mathrm{O}, \mathrm{N}\)

Short Answer

Expert verified
Using the periodic table and considering the atomic size trends, we can arrange the given sets of atoms in order from largest to smallest as follows: (a) Cs > K > Li; (b) Pb > Sn > Si; (c) N > O > F.

Step by step solution

01

(a) Arrange K, Li, Cs in Order of Size

All three elements, K (Potassium), Li (Lithium), and Cs (Cesium), belong to Group 1 (alkali metals) in the periodic table. As we move down the group, the atomic size increases. So, the order of these elements, from largest to smallest, is Cs > K > Li.
02

(b) Arrange Pb, Sn, Si in Order of Size

Pb (Lead), Sn (Tin), and Si (Silicon) belong to Group 14 in the periodic table. As we move down the group, the atomic size increases. Therefore, the order of these elements, from largest to smallest, is Pb > Sn > Si.
03

(c) Arrange F, O, N in Order of Size

F (Fluorine), O (Oxygen), and N (Nitrogen) are all elements in the same period, Period 2. As you move from left to right across a period, the atomic size decreases. Thus, the order of these elements, from largest to smallest, is N > O > F.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Size
Atomic size, often referred to as atomic radius, is the distance from the center of an atom’s nucleus to the outer edge of its electron cloud. Understanding atomic size gives insight into how atoms will interact with each other in chemical reactions.

Several factors influence atomic size:
  • Nuclear Charge: The number of protons in an atom's nucleus affects its size. More protons increase the positive charge, pulling electrons closer which can decrease size.
  • Electron Shielding: Inner electrons can shield outer electrons from the nucleus's pull, sometimes causing them to be held less tightly, increasing atomic size.
Atomic size plays a critical role in determining an element's properties and reactivity. By understanding the periodic trends associated with atomic size, we can make informed predictions about how atoms will behave in various chemical contexts.
Group Trends
In the periodic table, elements are grouped into columns known as groups or families. One of the key trends within a group is how atomic size changes as you move down the group.

Here is how atomic size behaves within groups:
  • Atomic size increases moving down a group. This is because additional electron shells are added as you progress downwards, which increases the distance between the nucleus and the electron cloud.
  • Each step down adds a new layer of electrons, enhancing the effect of electron shielding, thus eclipsing the increased nuclear charge.
For example, within the alkali metals group (Group 1), lithium is smaller than potassium, which in turn is smaller than cesium. This is consistently observed across other groups, indicating a clear and predictable pattern.

Recognizing group trends helps in predicting how an element might react, which is crucial for various chemical applications.
Period Trends
While navigating across a period in the periodic table, the atomic size trend behaves differently compared to within a group. Periodic trends provide valuable insights into how atomic properties evolve as one moves from left to right across a row.

Key aspects of period trends include:
  • Atomic size decreases as you move from left to right across a period. This is due to the increase in nuclear charge (more protons) within the same electron shell, drawing electrons closer to the nucleus and reducing atomic radius.
  • No additional electron shells are added, which keeps electron shielding constant while the nucleus's pull strengthens, resulting in smaller atoms.
For instance, in Period 2, nitrogen is larger than oxygen, which is larger than fluorine. This reflects the increasing nuclear pull shrinking atomic size across the period.

Understanding period trends is essential for foreseeing chemical bonding and interactions, aiding significantly in the study of chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) What is meant by the terms acidic oxide and basic oxide? (b) How can we predict whether an oxide will be acidic or basic based on its composition?

Some ions do not have a corresponding neutral atom that has the same electron configuration. For each of the following ions, identify the neutral atom that has the same number of electrons and determine if this atom has the same electron configuration. If such an atom does not exist, explain why. (b) \(\mathrm{Sc}^{3+}\) (d) \(\mathrm{Zn}^{2+},(\mathrm{e}) \mathrm{Sn}^{4+}\) (a) \(\mathrm{Cl}\) (c) \(\mathrm{Fe}^{2+}\)

(a) How is the concept of effective nuclear charge used to simplify the numerous electron-electron repulsions in a manyelectron atom? (b) Which experiences a greater effective nuclear charge in a Be atom, the 1 s electrons or the 2 s electrons? Explain.

Consider the \(\mathrm{A}_{2} \mathrm{X}_{4}\) molecule depicted here, where \(\mathrm{A}\) and \(\mathrm{X}\) are elements. The \(\mathrm{A}-\mathrm{A}\) bond length in this molecule is \(d_{1},\) and the four \(\mathrm{A}-\mathrm{X}\) bond lengths are each \(d_{2}\). (a) In terms of \(d_{1}\) and \(d_{2}\), how could you define the bonding atomic radii of atoms \(A\) and \(X ?(b)\) In terms of \(d_{1}\) and \(d_{2}\), what would you predict for the \(\mathrm{X}-\mathrm{X}\) bond length of an \(\mathrm{X}_{2}\) molecule? \([\) Section 7.3\(]\)

Consider the isoelectronic ions \(\mathrm{F}^{-}\) and \(\mathrm{Na}^{+}\). (a) Which ion is smaller? (b) Using Equation 7.1 and assuming that core electrons contribute 1.00 and valence electrons contribute 0.00 to the screening constant, \(S,\) calculate \(Z_{\text {eff }}\) for the \(2 p\) electrons in both ions. (c) Repeat this calculation using Slater's rules to estimate the screening constant, \(S\). (d) For isoelectronic ions, how are effective nuclear charge and ionic radius related?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free