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We can draw an analogy between the attraction of an electron to a nucleus and seeing a lightbulb -in essence, the more \(n u=\) clear charge the electron "sees," the greater the attraction. (a) Within this analogy, discuss how the screening by core electrons is analogous to putting a frosted-glass lampshade between the lightbulb and your eyes, as shown in the illustration. (b) Explain how we could mimic moving to the right in a row of the periodic table by changing the wattage of the lightbulb. (c) How would you change the wattage of the bulb and/or the frosted glass to mimic the effect of moving down a column of the periodic table? [Section 7.2]

Short Answer

Expert verified
In summary, the attraction between an electron and the nucleus can be compared to seeing a lightbulb. (a) The shielding effect of core electrons is analogous to a frosted glass lampshade that reduces the intensity of the light perceived, thus weakening the attraction. (b) Moving to the right in a row of the periodic table can be represented by increasing the wattage of the lightbulb, as the increased nuclear charge leads to greater attraction. (c) Moving down a column of the periodic table can be demonstrated by making the frosted glass thicker and placing the lampshade further away from your eyes, representing the increased shielding effect and greater distance between the outer electrons and the nucleus.

Step by step solution

01

Part (a): Core Electron Shielding and Frosted Glass Lampshade Analogy

The shielding effect occurs when core electrons shield outer electrons from the full positive charge of the nucleus. This causes the effective nuclear charge experienced by the outer electrons to be less than the actual nuclear charge. In the analogy, the lightbulb represents the nucleus, and the brightness of the light represents the nuclear charge. The frosted glass lampshade corresponds to the core electrons, as it shields the light and reduces its intensity (like how core electrons reduce the effective nuclear charge experienced by outer electrons). In this scenario, your eyes are like outer electrons, and their attraction to the nucleus is represented by their ability to see the light.
02

Part (b): Mimicking Moving Across a Row in the Periodic Table

Moving to the right in a row of the periodic table means increasing the atomic number and the nuclear charge. Therefore, in our analogy, we would increase the wattage of the lightbulb to represent a higher nuclear charge as we move to the right in the periodic table. Increasing the wattage of the lightbulb makes it brighter, hence corresponding to an increase in nuclear charge and greater attraction between the electron and the nucleus. Keep in mind, the shielding effect remains consistent across a row of the periodic table.
03

Part (c): Changing Wattage and Frosted Glass to Mimic Moving Down a Column of the Periodic Table

When moving down a column of the periodic table, there is an increase in the number of energy levels and core electrons, which leads to a greater shielding effect. In the analogy, to represent this increased shielding effect when moving down a column, we can make the frosted glass on the lampshade thicker, which will cause more of the light to be blocked. By increasing the thickness of the frosted glass, fewer light rays reach your eyes, analogous to the increased shielding effect that reduces the effective nuclear charge experienced by outer electrons. Additionally, the atomic size increases as we move down the periodic table, implying that the distance between the nucleus and the outer electron increases. In our analogy, we could represent this by placing the lampshade further away from your eyes, which will also cause you to perceive a less intense light, corresponding to a reduced effective nuclear charge.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Core Electron Shielding
Core electron shielding is a fundamental concept in atomic structure that relates to how inner electrons can partially block the attractive force between the nucleus and the outermost electrons. Imagine the nucleus as a bright lightbulb. The brightness represents its positive charge, attracting electrons towards it. However, just like a frosted glass lampshade can dim the light reaching your eyes, core electrons shield outer electrons from fully experiencing this attractive force. This happens because inner electrons repel the outer electrons, effectively decreasing the positive nuclear charge that is "seen" by the outer electrons.

When you have multiple layers of electrons, the outer electrons don't entirely feel the nucleus's full positive charge. Instead, they feel an "effective nuclear charge," which is weaker due to the presence of inner electron shielding. This concept is crucial for understanding interactions within the atom and the atom's size and behavior as you move across periods and groups in the periodic table.
Periodic Table Trends
Periodic table trends are the predictable patterns observed across different elements as you move left to right across a period, or top to bottom down a group. These trends largely relate to atomic size, ionization energy, and effective nuclear charge. You can think of them as varying the wattage of a lightbulb to see more or less of the nucleus's "brightness," or charge.

When moving right across a period on the periodic table, the atomic number increases. Each new element adds a proton and an electron. The added electron enters the same energy level, so the core electron shielding doesn't significantly change. However, the increased nuclear charge draws electrons closer, making the atom smaller and increasing the effective nuclear charge.
  • Rightward movement across a period: Increasing nuclear charge and decreasing atomic size.
Conversely, moving down a group increases the number of electron shells. This increases the distance between the nucleus and the outer shell electrons, which decreases the effective nuclear charge due to more shielding by core electrons and results in a larger atomic size.
  • Downward movement in a group: Increased atomic size due to added electron shells and greater core electron shielding.
Atomic Structure
Understanding atomic structure is like understanding the architecture of a building from the inside out. At the core of any atom lies the nucleus, a dense center composed of positively charged protons and neutral neutrons. Orbiting this nucleus are negatively charged electrons. These electrons are arranged in specific energy levels or shells around the nucleus, similar to layers of an onion.

Each element on the periodic table has a unique atomic structure that defines its chemical properties and behavior. The number of protons (atomic number) determines the element's identity. Alongside protons, electrons surround the nucleus in a way that balances the charge. The electrons arranged in layers or shells are influenced by effective nuclear charge, core electron shielding, and periodic table trends.

Key aspects of atomic structure include:
  • Nucleus: Contains protons and neutrons; positively charged.
  • Electron shells: Levels where electrons reside, influenced by energy and effective nuclear charge.
  • Effective nuclear charge: The net positive charge experienced by outer electrons, influenced by core electron shielding.
Understanding these basic principles helps in appreciating how elements interact and react, forming the foundation for more advanced chemical concepts.

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Most popular questions from this chapter

Some metal oxides, such as \(\mathrm{Sc}_{2} \mathrm{O}_{3},\) do not react with pure water, but they do react when the solution becomes either acidic or basic. Do you expect \(\mathrm{Sc}_{2} \mathrm{O}_{3}\) to react when the solution becomes acidic or when it becomes basic? Write a balanced chemical equation to support your answer.

(a) If the core electrons were totally effective at screening the valence electrons and the valence electrons provided no screening for each other, what would be the effective nuclear charge acting on the \(3 s\) and \(3 p\) valence electrons in \(\mathrm{P}\) ? (b) Repeat these calculations using Slater's rules. (c) Detailed calculations indicate that the effective nuclear charge is \(5.6+\) for the \(3 s\) electrons and \(4.9+\) for the \(3 p\) electrons. Why are the values for the \(3 s\) and \(3 p\) electrons different? (d) If you remove a single electron from a \(\mathrm{P}\) atom, which orbital will it come from? Explain.

Using only the periodic table, arrange each set of atoms in order from largest to smallest: (a) \(\mathrm{K}, \mathrm{Li}, \mathrm{Cs} ;\) (b) \(\mathrm{Pb}, \mathrm{Sn}, \mathrm{Si} ;\) (c) \(\mathrm{F}, \mathrm{O}, \mathrm{N}\)

The first ionization energy and electron affinity of Ar are both positive values. (a) What is the significance of the positive value in each case? (b) What are the units of electron affinity?

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