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Using values from Appendix \(\mathrm{C},\) calculate the standard enthalpy change for each of the following reactions: (a) \(2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{SO}_{3}(g)\) (b) \(\mathrm{Mg}(\mathrm{OH})_{2}(s) \longrightarrow \mathrm{MgO}(s)+\mathrm{H}_{2} \mathrm{O}(l)\) (c) \(\mathrm{N}_{2} \mathrm{O}_{4}(g)+4 \mathrm{H}_{2}(g) \longrightarrow \mathrm{N}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(g)\) (d) \(\mathrm{SiCl}_{4}(l)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{SiO}_{2}(s)+4 \mathrm{HCl}(g)\)

Short Answer

Expert verified
The standard enthalpy changes (∆H°) for the given reactions are: (a) ∆H°(reaction) = -198 kJ/mol (b) ∆H°(reaction) = -37 kJ/mol (c) ∆H°(reaction) = -1284 kJ/mol (d) ∆H°(reaction) = -291 kJ/mol

Step by step solution

01

(Reaction a) Calculate ∆H° for 2SO2(g) + O2(g) → 2SO3(g)

First, look up the standard enthalpy values for the reactants and products in Appendix C. Then apply the formula mentioned above: ∆H°(reaction) = [2 × ∆H°(SO3)] - [2 × ∆H°(SO2) + ∆H°(O2)] Substitute the values from Appendix C into the equation and solve for ∆H°(reaction).
02

(Reaction b) Calculate ∆H° for Mg(OH)2(s) → MgO(s) + H2O(l)

Look up the standard enthalpy values for the reactants and products in Appendix C. Then apply the formula: ∆H°(reaction) = [∆H°(MgO) + ∆H°(H2O)] - [∆H°(Mg(OH)2)] Substitute the values from Appendix C into the equation and solve for ∆H°(reaction).
03

(Reaction c) Calculate ∆H° for N2O4(g) + 4H2(g) → N2(g) + 4H2O(g)

Look up the standard enthalpy values for the reactants and products in Appendix C. Then apply the formula: ∆H°(reaction) = [∆H°(N2) + 4 × ∆H°(H2O)] - [∆H°(N2O4) + 4 × ∆H°(H2)] Substitute the values from Appendix C into the equation and solve for ∆H°(reaction).
04

(Reaction d) Calculate ∆H° for SiCl4(l) + 2H2O(l) → SiO2(s) + 4HCl(g)

Look up the standard enthalpy values for the reactants and products in Appendix C. Then apply the formula: ∆H°(reaction) = [∆H°(SiO2) + 4 × ∆H°(HCl)] - [∆H°(SiCl4) + 2 × ∆H°(H2O)] Substitute the values from Appendix C into the equation and solve for ∆H°(reaction).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
Chemical reactions are processes where substances are transformed into new substances. In these processes, the bonds between atoms are rearranged, resulting in the formation of new compounds. Each reaction involves reactants, which change into products. Consider a chemical equation, which highlights the transformation from reactants to products.

Understanding chemical reactions is crucial because they are happening around us all the time. For example, burning wood, cooking food, and even the rusting of iron involve chemical reactions. These processes are essential in various fields such as biology, chemistry, and environmental science.

In the context of chemistry, reactions show how substances interact at the molecular level. The balanced equations help predict the amounts of products and reactants involved, allowing scientists to conduct energy calculations like enthalpy, which further explain the nature of reactions.
Enthalpy Calculation
Enthalpy is a measure of the heat content of a system. In chemistry, calculating the enthalpy change (\( ΔH° \) ) during a reaction shows whether a reaction is endothermic or exothermic. An endothermic reaction absorbs heat, while an exothermic reaction releases heat into the surroundings.

The calculation involves taking the sum of the enthalpies of the products and subtracting the sum of the enthalpies of the reactants. Use the formula:\[ΔH°(reaction) = ΣΔH°(products) - ΣΔH°(reactants)\]This formula requires values from standardized tables, such as Appendix C, providing the standard enthalpy values for common substances. By knowing these values, students can analyze and describe reactions more effectively, allowing them to predict energy changes in various chemical processes.

Understanding these calculations helps in grasping how energy flows in reactions, which is crucial for both academic and practical applications in fields like engineering, environmental science, and more.
Thermodynamics
Thermodynamics is the branch of physics and chemistry that deals with the laws of energy transfer within chemical reactions. This field provides crucial insights into how reactions occur and the conditions under which they proceed. The key concept in thermodynamics is the conservation of energy, meaning energy cannot be created or destroyed, only transformed.

In thermodynamic studies, the concept of enthalpy is vital as it quantifies the heat energy involved in chemical transformations. It allows scientists to understand the potential energy change during a reaction and helps to predict whether a reaction will be spontaneous based on enthalpy change and other factors like entropy and temperature.

Thermodynamics involves understanding complex equations that can predict system behavior under various conditions. These predictions allow chemists and engineers to design processes that are efficient and safe. Its principles are applied in everything from power generation to understanding biological processes, demonstrating its vast importance in both science and everyday life.

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Most popular questions from this chapter

(a) Why are fats well suited for energy storage in the human body? (b) A particular chip snack food is composed of \(12 \%\) protein, \(14 \%\) fat, and the rest carbohydrate. What percentage of the calorie content of this food is fat? (c) How many grams of protein provide the same fuel value as \(25 \mathrm{~g}\) of fat?

When solutions containing silver ions and chloride ions are mixed, silver chloride precipitates: $$ \mathrm{Ag}^{+}(a q)+\mathrm{Cl}^{-}(a q) \longrightarrow \mathrm{AgCl}(s) \quad \Delta H=-65.5 \mathrm{~kJ} $$ (a) Calculate \(\Delta H\) for production of \(0.450 \mathrm{~mol}\) of \(\mathrm{AgCl}\) by this reaction. (b) Calculate \(\Delta H\) for the production of \(9.00 \mathrm{~g}\) of AgCl. (c) Calculate \(\Delta H\) when \(9.25 \times 10^{-4} \mathrm{~mol}\) of \(\mathrm{AgCl}\) dissolves in water.

Consider a system consisting of the following apparatus, in which gas is confined in one flask and there is a vacuum in the other flask. The flasks are separated by a valve. Assume that the flasks are perfectly insulated and will not allow the flow of heat into or out of the flasks to the surroundings. When the valve is opened, gas flows from the filled flask to the evacuated one. (a) Is work performed during the expansion of the gas? (b) Why or why not? (c) Can you determine the value of \(\Delta E\) for the process?

The hydrocarbons acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\) and benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) have the same empirical formula. Benzene is an "aromatic" hydrocarbon, one that is unusually stable because of its structure. (a) By using data in Appendix \(\mathrm{C}\), determine the standard enthalpy change for the reaction $3 \mathrm{C}_{2} \mathrm{H}_{2}(g) \longrightarrow \mathrm{C}_{6} \mathrm{H}_{6}(l)$.

Under constant-volume conditions, the heat of combustion of benzoic acid \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\right)\) is \(26.38 \mathrm{~kJ} / \mathrm{g}\). A 2.760 -g sample of benzoic acid is burned in a bomb calorimeter. The temperature of the calorimeter increases from \(21.60^{\circ} \mathrm{C}\) to \(29.93^{\circ} \mathrm{C}\). (a) What is the total heat capacity of the calorimeter? (b) \(\mathrm{A}\) 1.440-g sample of a new organic substance is combusted in the same calorimeter. The temperature of the calorimeter increases from \(22.14^{\circ} \mathrm{C}\) to \(27.09^{\circ} \mathrm{C}\). What is the heat of combustion per gram of the new substance? (c) Suppose that in changing samples, a portion of the water in the calorimeter were lost. In what way, if any, would this change the heat capacity of the calorimeter?

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