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Suppose that the gas-phase reaction \(2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow\) \(2 \mathrm{NO}_{2}(g)\) were carried out in a constant-volume container at constant temperature. Would the measured heat change represent \(\Delta H\) or \(\Delta E ?\) If there is a difference, which quantity is larger for this reaction? Explain.

Short Answer

Expert verified
In this gas-phase reaction at constant volume and constant temperature, the measured heat change represents both ΔH (change in enthalpy) and ΔE (change in internal energy) since there is no difference between the two quantities. This is because the change in volume (ΔV) is 0, making the relationship between ΔH and ΔE as follows: ΔH = ΔE. Therefore, both ΔH and ΔE represent the same heat change for this reaction, and there is no need to compare them to determine which one is larger.

Step by step solution

01

Understanding ΔH and ΔE

ΔH (change in enthalpy) and ΔE (change in internal energy) are two important thermodynamic properties that can describe the energy changes in a chemical reaction. The relationship between the two can be given by the equation: ΔH = ΔE + PΔV, where P is the constant pressure and ΔV is the change in volume.
02

Analyzing the reaction at constant volume and temperature

Since we are told that the reaction takes place in a constant-volume container, there is no change in the volume of the system (ΔV = 0). The reaction is also happening at a constant temperature. Now, using the relationship between ΔH and ΔE, we will determine which quantity is represented by the measured heat change.
03

Determining the measured heat change

Given that ΔV = 0, we can rewrite the equation for the relationship between ΔH and ΔE as: ΔH = ΔE This means that at constant volume and constant temperature, there is no difference between the change in enthalpy (ΔH) and the change in internal energy (ΔE). Therefore, the measured heat change represents both ΔH and ΔE in this case.
04

Comparing ΔH and ΔE

Since ΔH and ΔE are the same for this particular reaction, there is no need to compare them to determine which one is larger. They are equal in magnitude and represent the same heat change for the given reaction at constant volume and temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy
Enthalpy, often represented as \(\Delta H\), is a key concept in thermodynamics used to measure the total heat content of a system during a reaction at constant pressure. It accounts for the internal energy of the system as well as the work done by the system due to volume change.

When a reaction occurs, energy can be absorbed or released, leading to changes in enthalpy. This change is significant when calculating how heat is transferred in open systems where pressure may change, like in reactions occurring in an open container.

However, when volume change is null, such as in our scenario with a constant volume container, the enthalpy and internal energy changes are the same. Therefore, the distinction between these terms becomes less relevant under these specific conditions. Under such circumstances, measuring the heat change provides you with only one value that represents both enthalpy and internal energy changes.
Internal Energy
Internal energy, denoted as \(\Delta E\), is the total energy contained within a thermodynamic system. It encompasses the kinetic and potential energy of the molecules in the system.

In chemical reactions, changes in internal energy can occur due to various factors, including changes in volume, temperature, or phase. However, if a reaction takes place at constant volume, like in the discussion of our given reaction in the exercise, the change in internal energy can be directly correlated to the heat of the reaction.

It is important to note that at constant volume, there is no work done by or on the system (because work is related to volume changes). Thus, all the heat absorbed or released is accounted for by the change in internal energy alone. This concept simplifies calculations and is critical in understanding thermodynamic changes in specific settings like sealed containers.
Constant Volume Reaction
A constant volume reaction refers to a process occurring within a system where the volume does not change. This is typically achieved by conducting the reaction in a sealed, rigid container.

The significance of maintaining a constant volume is that it simplifies the thermodynamic analysis: the pressure-volume work term (\(P\Delta V\)) becomes zero. Consequently, under these conditions, the heat exchange for the reaction is equal to the change in internal energy, \(\Delta E\), since no work is done by or against atmospheric pressure.

This makes constant volume settings ideal for calculating internal energy changes directly from measured heat. In the example reaction of forming \(\text{NO}_2\) from \(\text{NO}\) and \(\text{O}_2\), the calculation of energy changes becomes straightforward, enabling a clear understanding of the heat changes involved without the complication of volume work.

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Most popular questions from this chapter

Consider a system consisting of the following apparatus, in which gas is confined in one flask and there is a vacuum in the other flask. The flasks are separated by a valve. Assume that the flasks are perfectly insulated and will not allow the flow of heat into or out of the flasks to the surroundings. When the valve is opened, gas flows from the filled flask to the evacuated one. (a) Is work performed during the expansion of the gas? (b) Why or why not? (c) Can you determine the value of \(\Delta E\) for the process?

Consider two solutions, the first being \(50.0 \mathrm{~mL}\) of \(1.00 \mathrm{M} \mathrm{CuSO}_{4}\) and the second \(50.0 \mathrm{~mL}\) of \(2.00 \mathrm{MKOH}\). When the two solutions are mixed in a constant-pressure calorimeter, a precipitate forms and the temperature of the mixture rises from \(21.5^{\circ} \mathrm{C}\) to \(27.7^{\circ} \mathrm{C}\). (a) Before mixing, how many grams of Cu are present in the solution of \(\mathrm{CuSO}_{4} ?\) (b) Predict the identity of the precipitate in the reaction. (c) Write complete and net ionic equations for the reaction that occurs when the two solutions are mixed. (d) From the calorimetric data, calculate \(\Delta H\) for the reaction that occurs on mixing. Assume that the calorimeter absorbs only a negligible quantity of heat, that the total volume of the solution is 100.0 \(\mathrm{mL},\) and that the specific heat and density of the solution after mixing are the same as that of pure water.

Consider the following reaction: $$ 2 \mathrm{Mg}(s)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{MgO}(s) \quad \Delta H=-1204 \mathrm{~kJ} $$ (a) Is this reaction exothermic or endothermic? (b) Calculate the amount of heat transferred when \(3.55 \mathrm{~g}\) of \(\mathrm{Mg}(s)\) reacts at constant pressure. (c) How many grams of \(\mathrm{MgO}\) are produced during an enthalpy change of \(-234 \mathrm{~kJ}\) ? (d) How many kilojoules of heat are absorbed when \(40.3 \mathrm{~g}\) of \(\mathrm{MgO}(s)\) is decomposed into \(\mathrm{Mg}(s)\) and \(\mathrm{O}_{2}(g)\) at constant pressure?

(a) Calculate the kinetic energy in joules of a \(1200-\mathrm{kg}\) automobile moving at \(18 \mathrm{~m} / \mathrm{s}\). (b) Convert this energy to calories. (c) What happens to this energy when the automobile brakes to a stop?

(a) Why is the change in enthalpy usually easier to measure than the change in internal energy? (b) \(H\) is a state function, but \(q\) is not a state function. Explain. (c) For a given process at constant pressure, \(\Delta H\) is positive. Is the process endothermic or exothermic?

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