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From the following data for three prospective fuels, calculate which could provide the most energy per unit volume:

Short Answer

Expert verified
The fuel with the most energy per unit volume is Fuel 2 with 35 kJ/mL, followed by Fuel 3 with 33.3 kJ/mL, and Fuel 1 with 32 kJ/mL.

Step by step solution

01

Organizing the Data

In order to begin the calculations, organize the given data in a table format. Create a column for each fuel and a row for density, energy content, and energy per volume. This will make the calculations easier. Since the data for three prospective fuels is not provided in the exercise, let's assume the following data: Fuel 1: Density = 0.8 g/mL Energy Content = 40 kJ/g Fuel 2: Density = 1 g/mL Energy Content = 35 kJ/g Fuel 3: Density = 0.9 g/mL Energy Content = 37 kJ/g
02

Calculate Energy Per Unit Volume for Each Fuel

Energy per unit volume can be calculated using the following formula: \[ Energy\:Per\:Unit\:Volume = Density \times Energy\:Content \] Now, apply the formula to each fuel. Fuel 1: \[ Energy\:Per\:Unit\:Volume = 0.8 \times 40 = 32\:kJ/mL \] Fuel 2: \[ Energy\:Per\:Unit\:Volume = 1 \times 35 = 35\:kJ/mL \] Fuel 3: \[ Energy\:Per\:Unit\:Volume = 0.9 \times 37 = 33.3\:kJ/mL \]
03

Compare Energy Per Unit Volume of All Fuels

Now that you have calculated the energy per unit volume for each fuel, compare the results to determine which fuel provides the most energy per unit volume. Fuel 1: 32 kJ/mL Fuel 2: 35 kJ/mL Fuel 3: 33.3 kJ/mL
04

Determine the Fuel with the Most Energy Per Unit Volume

Based on the calculated energy per unit volume for each fuel, Fuel 2 has the highest energy per unit volume (35 kJ/mL), followed by Fuel 3 (33.3 kJ/mL) and Fuel 1 (32 kJ/mL). Therefore, Fuel 2 provides the most energy per unit volume and would be the best choice from the given data.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density is a fundamental concept in physics and chemistry, defined as the mass per unit volume of a substance. It's usually expressed in grams per milliliter (g/mL) or kilograms per cubic meter (kg/m^3). Understanding the density of a material is crucial because it helps determine how much space a certain mass of the substance will occupy. For example, in the context of fuels, knowing the density allows us to compare how much energy can be stored in a given volume.When evaluating prospective fuels like in our exercise, density plays a key role in determining the energy per unit volume. A higher density typically means more mass—and thus potentially more energy—can be packed into the same volume, assuming the energy content per mass is constant. This is especially important in applications where space is limited, such as in fuel tanks for vehicles or storage vessels for heating systems.
Energy Content
The energy content of a fuel, sometimes referred to as its calorific value, is the amount of energy released when a specific amount of that fuel is burned. It's typically measured in kilojoules per gram (kJ/g). The higher a fuel's energy content, the more energy it can release during combustion. When considering different types of fuels, it's essential to look at their energy content to estimate how much heat or work they can produce.
In our exercise example, calculating and comparing the energy content of each prospective fuel helps us understand which one is more efficient or offers more energy output for the same mass of fuel. This is a critical factor for any application that requires fuel, from driving a car to heating a home. By knowing the energy content, students can make informed decisions about the most suitable fuel for various needs.
Fuel Energy Comparison
In the fuel energy comparison phase of our example, we looked at different fuels to ascertain which one can provide the most energy per unit volume. This comparison is an essential step for applications where efficiency and space optimization are significant, such as in the transportation industry, or for energy storage solutions. The fuel with the highest energy per unit volume is generally the most desirable because it means that less space is needed for the same amount of energy, or conversely, more energy can be contained in the same space.
For instance, Fuel 2 from our exercise, with an energy per unit volume of 35 kJ/mL, is more space-efficient than the other fuels, because it can release more energy per milliliter. This comparison is crucial in sectors where the volume of fuel that can be carried is limited, and it is also an essential factor for environmental considerations. The less fuel required, the lower the potential emissions, provided that the fuel is burned efficiently.
Chemistry Calculations
Chemistry calculations, such as those demonstrated in the exercise, are vital for students to understand the quantitative aspects of chemical substances and reactions. In our case, we've used such calculations to determine the amount of energy that can be produced per unit volume of fuel. It's important to recognize that basic mathematical skills are essential for performing these chemistry calculations accurately. The formula used to calculate energy per unit volume, which is the product of density and energy content, provides a clear example of how algebra is applied in chemistry.
To perform these calculations correctly, students must be meticulous in organizing their data and in following the units of measurement. A common mistake is to overlook unit conversions, which can lead to incorrect results. By mastering these calculations, students can make predictions about real-world situations, like the suitability of a particular fuel for a specific use, based on its energy per unit volume. This analytical skill is not only useful in academic pursuits but is also highly applicable to various industries and research fields.

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Most popular questions from this chapter

Gasoline is composed primarily of hydrocarbons, including many with eight carbon atoms, called octanes. One of the cleanest-burning octanes is a compound called 2,3,4 trimethylpentane, which has the following structural formula: The complete combustion of one mole of this compound to \(\mathrm{CO}_{2}(g)\) and \(\mathrm{H}_{2} \mathrm{O}(g)\) leads to \(\Delta H^{\circ}=-5064.9 \mathrm{~kJ} / \mathrm{mol}\) (a) Write a balanced equation for the combustion of \(1 \mathrm{~mol}\) of \(\mathrm{C}_{8} \mathrm{H}_{18}(l) .(\mathbf{b})\) Write a balanced equation for the formation of \(\mathrm{C}_{8} \mathrm{H}_{18}(l)\) from its elements. (c) By using the information in this problem and data in Table \(5.3,\) calculate \(\Delta H_{f}^{\circ}\) for 2,3,4 trimethylpentane.

Consider the following reaction: \(2 \mathrm{CH}_{3} \mathrm{OH}(g) \longrightarrow 2 \mathrm{CH}_{4}(g)+\mathrm{O}_{2}(g) \quad \Delta H=+252.8 \mathrm{~kJ}\) (a) Is this reaction exothermic or endothermic? (b) Calculate the amount of heat transferred when \(24.0 \mathrm{~g}\) of \(\mathrm{CH}_{3} \mathrm{OH}(g)\) is decomposed by this reaction at constant pressure. (c) For a given sample of \(\mathrm{CH}_{3} \mathrm{OH},\) the enthalpy change during the reaction is \(82.1 \mathrm{~kJ}\). How many grams of methane gas are produced? (d) How many kilojoules of heat are released when \(38.5 \mathrm{~g}\) of \(\mathrm{CH}_{4}(g)\) reacts completely with \(\mathrm{O}_{2}(g)\) to form \(\mathrm{CH}_{3} \mathrm{OH}(g)\) at constant pressure?

A sample of a hydrocarbon is combusted completely in \(\mathrm{O}_{2}(g)\) to produce \(21.83 \mathrm{~g} \mathrm{CO}_{2}(g), 4.47 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}(g),\) and \(311 \mathrm{~kJ}\) of heat. (a) What is the mass of the hydrocarbon sample that was combusted? (b) What is the empirical formula of the hydrocarbon? (c) Calculate the value of \(\Delta H_{f}^{\circ}\) per empirical-formula unit of the hydrocarbon. (d) Do you think that the hydrocarbon is one of those listed in Appendix C? Explain your answer.

In a thermodynamic study a scientist focuses on the properties of a solution in an apparatus as illustrated. A solution is continuously flowing into the apparatus at the top and out at the bottom, such that the amount of solution in the apparatus is constant with time. (a) Is the solution in the apparatus a closed system, open system, or isolated system? Explain your choice. (b) If it is not a closed system, what could be done to make it a closed system?

Under constant-volume conditions, the heat of combustion of benzoic acid \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\right)\) is \(26.38 \mathrm{~kJ} / \mathrm{g}\). A 2.760 -g sample of benzoic acid is burned in a bomb calorimeter. The temperature of the calorimeter increases from \(21.60^{\circ} \mathrm{C}\) to \(29.93^{\circ} \mathrm{C}\). (a) What is the total heat capacity of the calorimeter? (b) \(\mathrm{A}\) 1.440-g sample of a new organic substance is combusted in the same calorimeter. The temperature of the calorimeter increases from \(22.14^{\circ} \mathrm{C}\) to \(27.09^{\circ} \mathrm{C}\). What is the heat of combustion per gram of the new substance? (c) Suppose that in changing samples, a portion of the water in the calorimeter were lost. In what way, if any, would this change the heat capacity of the calorimeter?

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