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Using the activity series (Table 4.5 ), write balanced chemical equations for the following reactions. If no reaction occurs, simply write NR. (a) Nickel metal is added to a solution of copper(II) nitrate; (b) a solution of zinc nitrate is added to a solution of magnesium sulfate; (c) hydrochloric acid is added to gold metal; (d) chromium metal is immersed in an aqueous solution of cobalt(II) chloride; (e) hydrogen gas is bubbled through a solution of silver nitrate.

Short Answer

Expert verified
(a) \(Ni(s) + Cu(NO_3)_2(aq) \rightarrow Ni(NO_3)_2(aq) + Cu(s)\) (b) NR (c) NR (d) \(Cr(s) + 2CoCl_2(aq) \rightarrow 2Co(s) + CrCl_2(aq)\) (e) \(2AgNO_3(aq) + H_2(g) \rightarrow 2Ag(s) + 2HNO_3(aq)\)

Step by step solution

01

Use the activity series

In order to determine if a reaction will occur or not, we first need to consult the activity series of elements. From the table, the order of elements from the most to the least reactive is: K > Ca > Na > Mg > Al > Zn > Fe > Ni > Sn > Pb > H > Cu > Hg > Ag > Pt > Au. Now, let's discuss each subpart.
02

(a) Nickel metal is added to a solution of copper(II) nitrate

Since Nickel (Ni) is more reactive than Copper (Cu), a reaction will occur. Using the activity series, we can deduce that Nickel will displace Copper from its nitrate solution: Ni(s) + Cu(NO3)2(aq) -> Ni(NO3)2(aq) + Cu(s)
03

(b) A solution of zinc nitrate is added to a solution of magnesium sulfate

In this case, Zinc (Zn) is less reactive than Magnesium (Mg), so no reaction will occur. Thus, we simply write "NR."
04

(c) Hydrochloric acid is added to gold metal

Gold (Au) is one of the least reactive metals, and Hydrogen (H) is relatively more reactive. So, no reaction will occur when hydrochloric acid (which contains hydrogen ions) is added to gold metal. Thus, we simply write "NR."
05

(d) Chromium metal is immersed in aqueous solution of cobalt(II) chloride

Chrome (Cr) is more reactive than Cobalt (Co), so it will displace the latter from its chloride solution: Cr(s) + 2CoCl2(aq) -> 2Co(s) + CrCl2(aq)
06

(e) Hydrogen gas is bubbled through a solution of silver nitrate

Hydrogen (H) is more reactive than Silver (Ag), so it will displace the latter from its nitrate solution: 2AgNO3(aq) + H2(g) -> 2Ag(s) + 2HNO3(aq) In summary, the balanced chemical equations for each subpart are: (a) Ni(s) + Cu(NO3)2(aq) -> Ni(NO3)2(aq) + Cu(s) (b) NR (c) NR (d) Cr(s) + 2CoCl2(aq) -> 2Co(s) + CrCl2(aq) (e) 2AgNO3(aq) + H2(g) -> 2Ag(s) + 2HNO3(aq)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reactivity of Metals
The reactivity of metals is a key concept in understanding how chemical reactions involving metals take place. Some metals are more reactive than others, and this reactivity is often compared using the activity series. This series orders metals from most reactive to least reactive, allowing us to predict which metals can displace others in compounds.
For example, a metal that's higher up in the series will replace a metal that's lower in a compound.
  • Examples of highly reactive metals include Potassium (K) and Calcium (Ca), which can easily react with water and acids.
  • In contrast, metals like Gold (Au) and Silver (Ag) are less reactive and won’t easily participate in reactions.

Understanding how metals react is essential for predicting the outcomes of reactions in chemical equations, like determining if nickel can displace copper as it is higher in the activity series.
Chemical Equations
Chemical equations are symbolic representations of chemical reactions, showing the reactants transforming into products. They provide information not only about the substances involved but also their proportions. Writing balanced chemical equations means ensuring the same number of each type of atom is present on both sides.
For instance, in the reaction between nickel and copper(II) nitrate, the equation will be:
\[ \text{Ni(s) + Cu(NO}_3\text{)}_2\text{(aq) → Ni(NO}_3\text{)}_2\text{(aq) + Cu(s)} \]
Here, one atom of nickel displaces copper, forming nickel nitrate and solid copper.
  • Start by writing the unbalanced equation with the right formulas.
  • Then, adjust coefficients to balance the equation, making sure atoms are conserved.
Balanced equations are crucial for accurate representation and understanding of a chemical process.
Predicting Reactions
Predicting whether a chemical reaction will occur involves understanding the nature of the substances involved and their reactivity. The activity series is a useful tool in making such predictions.
For example, if a more reactive metal is added to a solution containing a less reactive metal ion, a displacement reaction is likely to occur.
  • In part (e), hydrogen gas bubbling through silver nitrate will result in silver being displaced, as hydrogen is more reactive according to the activity series.
  • Conversely, in part (b), zinc nitrate and magnesium sulfate don't react because zinc is less reactive than magnesium.

Predicting reactions is not always straightforward but using the activity series to assess and compare reactivity is a powerful strategy in chemical analysis.

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Most popular questions from this chapter

Explain how a redox reaction involves electrons in the same way that a neutralization reaction involves protons. [Sections 4.3 and 4.4\(]\)

You are presented with a white solid and told that due to careless labeling it is not clear if the substance is barium chloride, lead chloride, or zinc chloride. When you transfer the solid to a beaker and add water, the solid dissolves to give a clear solution. Next a \(\mathrm{Na}_{2} \mathrm{SO}_{4}(a q)\) solution is added and a white precipitate forms. What is the identity of the unknown white solid? \([\) Section 4.2\(]\)

Explain the following observations: (a) \(\mathrm{NH}_{3}\) contains no \(\mathrm{OH}^{-}\) ions, and yet its aqueous solutions are basic; (b) HF is called a weak acid, and yet it is very reactive; (c) although sulfuric acid is a strong electrolyte, an aqueous solution of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) contains more \(\mathrm{HSO}_{4}^{-}\) ions than \(\mathrm{SO}_{4}^{2-}\) ions.

You know that an unlabeled bottle contains a solution of one of the following: \(\mathrm{AgNO}_{3}, \mathrm{CaCl}_{2}\), or \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} .\) A friend suggests that you test a portion of the solution with \(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}\) and then with \(\mathrm{NaCl}\) solutions. Explain how these two tests together would be sufficient to determine which salt is present in the solution.

We have learned in this chapter that many ionic solids dissolve in water as strong electrolytes, that is, as separated ions in solution. What properties of water facilitate this process? Would you expect ionic compounds to be soluble in elemental liquids like bromine or mercury, just as they are in water? Explain.

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