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Write balanced molecular and net ionic equations for the following reactions, and identify the gas formed in each: (a) solid cadmium sulfide reacts with an aqueous solution of sulfuric acid; (b) solid magnesium carbonate reacts with an aqueous solution of perchloric acid.

Short Answer

Expert verified
In the reaction between solid cadmium sulfide (CdS) and an aqueous solution of sulfuric acid (H2SO4), the balanced molecular equation is: \(CdS (s) + H2SO4 (aq) \rightarrow CdSO4 (aq) + H2S (g)\). The net ionic equation is: \(CdS (s) + 2H^+ (aq) \rightarrow Cd^{2+} (aq) + H2S (g)\). The gas formed is hydrogen sulfide (H2S). In the reaction between solid magnesium carbonate (MgCO3) and an aqueous solution of perchloric acid (HClO4), the balanced molecular equation is: \(MgCO3 (s) + 2HClO4 (aq) \rightarrow Mg(ClO4)2 (aq) + CO2 (g) + H2O (l)\). The net ionic equation is: \(MgCO3 (s) + 2H^+ (aq) \rightarrow Mg^{2+} (aq) + CO2 (g) + H2O (l)\). The gas formed is carbon dioxide (CO2).

Step by step solution

01

(Reaction a: Cadmium sulfide with sulfuric acid)

The reaction between solid cadmium sulfide (CdS) and an aqueous solution of sulfuric acid (H2SO4) can be represented as follows: CdS (s) + H2SO4 (aq) -> ? In this reaction, cadmium sulfide (a solid) reacts with sulfuric acid (an aqueous solution) to produce a cadmium sulfate (CdSO4) and hydrogen sulfide (H2S) gas. The balanced molecular equation for this reaction is: CdS (s) + H2SO4 (aq) -> CdSO4 (aq) + H2S (g) Now, let's determine the net ionic equation by identifying the spectator ions and removing them from the equation. The net ionic equation includes only the aqueous ions that undergo a chemical change. For this reaction, the net ionic equation is: CdS (s) + 2H^+ (aq) + SO4^2- (aq) -> Cd^2+(aq) + SO4^2- (aq) + H2S (g) Removing the common ion (spectator ion) SO4^2- from both sides of the equation, the final net ionic equation becomes: CdS (s) + 2H^+ (aq) -> Cd^2+ (aq) + H2S (g)
02

(Reaction b: Magnesium carbonate with perchloric acid)

The reaction between solid magnesium carbonate (MgCO3) and an aqueous solution of perchloric acid (HClO4) can be represented as follows: MgCO3 (s) + HClO4 (aq) -> ? In this reaction, magnesium carbonate (a solid) reacts with perchloric acid (an aqueous solution) to produce magnesium perchlorate (Mg(ClO4)2) and carbon dioxide (CO2) gas. The balanced molecular equation for this reaction is: MgCO3 (s) + 2HClO4 (aq) -> Mg(ClO4)2 (aq) + CO2 (g) + H2O (l) Now, let's determine the net ionic equation by identifying the spectator ions and removing them from the equation. The net ionic equation includes only the aqueous ions that undergo a chemical change. For this reaction, the net ionic equation is: MgCO3 (s) + 2H^+ (aq) + 2ClO4^- (aq) -> Mg^2+(aq) + 2ClO4^-(aq) + CO2 (g) + H2O (l) Removing the common ion (spectator ion) 2ClO4^- from both sides of the equation, the final net ionic equation becomes: MgCO3 (s) + 2H^+ (aq) -> Mg^2+ (aq) + CO2 (g) + H2O (l) So, in conclusion: a) The gas formed in the reaction between solid cadmium sulfide and an aqueous solution of sulfuric acid is hydrogen sulfide (H2S). b) The gas formed in the reaction between solid magnesium carbonate and an aqueous solution of perchloric acid is carbon dioxide (CO2).

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Most popular questions from this chapter

(a) How would you prepare \(175.0 \mathrm{~mL}\) of \(0.150 \mathrm{M} \mathrm{AgNO}_{3}\) solution starting with pure \(\mathrm{AgNO}_{3} ?\) (b) An experiment calls for you to use \(100 \mathrm{~mL}\) of \(0.50 \mathrm{M} \mathrm{HNO}_{3}\) solution. All you have available is a bottle of \(3.6 \mathrm{M} \mathrm{HNO}_{3} .\) How would you prepare the desired solution?

Which of the following ions will always be a spectator ion in a precipitation reaction? (a) \(\mathrm{Cl}^{-},(\mathrm{b}) \mathrm{NO}_{3}^{-},(\mathrm{c}) \mathrm{NH}_{4}^{+},(\mathrm{d}) \mathrm{S}^{2-},\) (e) \(\mathrm{SO}_{4}^{2-}\). Explain briefly. [Section \(\left.4.2\right]\)

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We have learned in this chapter that many ionic solids dissolve in water as strong electrolytes, that is, as separated ions in solution. What properties of water facilitate this process? Would you expect ionic compounds to be soluble in elemental liquids like bromine or mercury, just as they are in water? Explain.

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