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(a) Determine the chemical formula of the product formed when the metallic element aluminum combines with the nonmetallic element bromine, \(\mathrm{Br}_{2}\). Write the balanced chemical equation for the reaction. (b) What products form when a compound containing \(\mathrm{C}, \mathrm{H},\) and \(\mathrm{O}\) is completely combusted in air? Write a balanced chemical equation for the combustion of acetone, \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l),\) in air.

Short Answer

Expert verified
The product formed when aluminum combines with bromine is AlBr₃, and the balanced chemical equation for the reaction is \(2 \mathrm{Al}(s) + 3 \mathrm{Br}_{2}(l) \rightarrow 2 \mathrm{AlBr}_{3}(s)\). When a compound containing C, H, and O is completely combusted in air, the products are carbon dioxide (CO₂) and water (H₂O). The balanced chemical equation for the combustion of acetone (\(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l)\)) is \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l) + 4 \mathrm{O}_{2}(g) \rightarrow 3 \mathrm{CO}_{2}(g) + 3 \mathrm{H}_{2}\mathrm{O}(l)\).

Step by step solution

01

Determine the ions formed by each element

Aluminum is a metal and forms a positive ion with a charge of +3 (Al³⁺) in a chemical reaction. Bromine is a non-metal and forms a negative ion with a charge of -1 (Br⁻) in a chemical reaction. Step 2: Combine the ions to form a compound
02

Write the chemical formula of the product

Since Al³⁺ has a charge of +3 and Br⁻ has a charge of -1, we need three Br⁻ ions to balance the charge of one Al³⁺ ion. Hence, the chemical formula of the compound formed is AlBr₃. Step 3: Write the balanced chemical equation
03

Write the balanced chemical equation for Al reacting with Br₂

The balanced chemical equation is: \[2 \mathrm{Al}(s) + 3 \mathrm{Br}_{2}(l) \rightarrow 2 \mathrm{AlBr}_{3}(s)\] For the second part of the exercise: Step 1: Determine the products of combustion
04

Identify the products of combustion

When compounds containing carbon, hydrogen, and oxygen are combusted in air, the products formed are carbon dioxide (CO₂) and water (H₂O). Step 2: Write the balanced chemical equation for the combustion of acetone
05

Write the balanced chemical equation for \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l)\)

The balanced chemical equation for the combustion of acetone is: \[\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l) + 4 \mathrm{O}_{2}(g) \rightarrow 3 \mathrm{CO}_{2}(g) + 3 \mathrm{H}_{2}\mathrm{O}(l)\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Formula
A chemical formula represents the types and numbers of atoms in a molecule of a compound. It acts like a shorthand notation that tells us the composition of a compound precisely. For example, when aluminum and bromine react, we first identify the ions they form. Aluminum, being a metal, forms a cation with a +3 charge, written as \( \text{Al}^{3+} \), whereas bromine, a non-metal, forms an anion with a -1 charge, \( \text{Br}^{-} \).

To form a neutral compound, these charges need to be balanced. This means we need three bromine atoms for each aluminum atom to balance the charges. The resulting chemical formula is \( \text{AlBr}_3 \), which indicates that each molecule of this compound consists of one aluminum atom and three bromine atoms.

The importance of the chemical formula is that it not only tells us the proportion of the elements but also helps to predict the possible reactions with other chemicals, as it reflects the internal structure of the molecule.
Balanced Chemical Equation
A balanced chemical equation is a statement that uses chemical formulas to show the identities and amounts of substances involved in a chemical reaction. This equation follows the law of conservation of mass, which states that matter cannot be created or destroyed in a closed system.

For a chemical reaction between aluminum and bromine, we have the formula \( 2 \text{Al}(s) + 3 \text{Br}_2(l) \rightarrow 2 \text{AlBr}_3(s) \). This shows that two moles of aluminum react with three moles of bromine to produce two moles of aluminum bromide.

Balancing chemical equations involves adjusting the coefficients (the numbers in front of the molecules) to ensure that there are equal numbers of each type of atom on both sides of the equation. This balance ensures that the mass and the atoms are conserved in the reaction. Balancing equations is crucial as it reflects the actual ratios in which substances react and informs us about the stoichiometry of the reaction.
Combustion Reaction
A combustion reaction involves the burning of a substance in the presence of oxygen, releasing energy in the form of heat and light. Many organic compounds, particularly those containing carbon (C), hydrogen (H), and sometimes oxygen (O), undergo combustion.

During combustion, complete oxidation of a carbon-containing compound leads to the formation of carbon dioxide (\( \text{CO}_2 \)) and water (\( \text{H}_2\text{O} \)). In the case of acetone, an organic compound with the formula \( \text{C}_3\text{H}_6\text{O} \), the combustion reaction in air can be represented as:

\[ \text{C}_3 \text{H}_6 \text{O}(l) + 4 \text{O}_2(g) \rightarrow 3 \text{CO}_2(g) + 3 \text{H}_2\text{O}(l) \]

This balanced reaction equation reveals that one molecule of acetone requires four molecules of oxygen to produce three molecules each of carbon dioxide and water. Understanding combustion reactions is essential because it relates to everyday events such as burning fuels in engines, cooking, and even breathing.

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Most popular questions from this chapter

A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the air sample through a "bubbler" containing sodium iodide, which removes the ozone according to the following equation: \(\mathrm{O}_{3}(g)+2 \mathrm{NaI}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\) $$ \mathrm{O}_{2}(g)+\mathrm{I}_{2}(s)+2 \mathrm{NaOH}(a q) $$ (a) How many moles of sodium iodide are needed to remove \(5.95 \times 10^{-6} \mathrm{~mol}\) of \(\mathrm{O}_{3} ?\) (b) How many grams of sodium iodide are needed to remove \(1.3 \mathrm{mg}\) of \(\mathrm{O}_{3} ?\)

Copper is an excellent electrical conductor widely used in making electric circuits. In producing a printed circuit board for the electronics industry, a layer of copper is laminated on a plastic board. A circuit pattern is then printed on the board using a chemically resistant polymer. The board is then exposed to a chemical bath that reacts with the exposed copper, leaving the desired copper circuit, which has been protected by the overlaying polymer. Finally, a solvent removes the polymer. One reaction used to remove the exposed copper from the circuit board is $$ \begin{aligned} \mathrm{Cu}(s)+\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}(a q)+4 \mathrm{NH}_{3}(a q) & \longrightarrow \\ & 2 \mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}(a q) \end{aligned} $$ A plant needs to produce 5000 circuit boards, each with a surface area measuring 2.0 in. \(\times 3.0\) in. The boards are covered with a \(0.65-\mathrm{mm}\) layer of copper. In subsequent processing, \(85 \%\) of the copper is removed. Copper has a density of \(8.96 \mathrm{~g} / \mathrm{cm}^{3} .\) Calculate the masses of \(\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) needed to produce the circuit boards, assuming that the reaction used gives a \(97 \%\) yield.

An iron ore sample contains \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) together with other substances. Reaction of the ore with CO produces iron metal: $$ \mathrm{Fe}_{2} \mathrm{O}_{3}(s)+\mathrm{CO}(g) \longrightarrow \mathrm{Fe}(s)+\mathrm{CO}_{2}(g) $$ (a) Balance this equation. (b) Calculate the number of grams of CO that can react with $$ 0.350 \mathrm{~kg} \text { of } \mathrm{Fe}_{2} \mathrm{O}_{3} $$ (c) Calculate the number of grams of Fe and the number of grams of \(\mathrm{CO}_{2}\) formed when \(0.350 \mathrm{~kg}\) of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) reacts. (d) Show that your calculations in parts (b) and (c) are consistent with the law of conservation of mass.

Write balanced chemical equations to correspond to each of the following descriptions: (a) When sulfur trioxide gas reacts with water, a solution of sulfuric acid forms. (b) Boron sulfide, \(\mathrm{B}_{2} \mathrm{~S}_{3}(s),\) reacts violently with water to form dissolved boric acid, \(\mathrm{H}_{3} \mathrm{BO}_{3},\) and hydrogen sulfide gas. (c) Phosphine, \(\mathrm{PH}_{3}(g)\), combusts in oxygen gas to form water vapor and solid tetraphosphorus decaoxide. (d) When solid mercury(II) nitrate is heated, it decomposes to form solid mercury(II) oxide, gaseous nitrogen dioxide, and oxygen. (e) Copper metal reacts with hot concentrated sulfuric acid solution to form aqueous copper(II) sulfate, sulfur dioxide gas, and water.

Determine the empirical formulas of the compounds with the following compositions by mass: (a) \(10.4 \% \mathrm{C}, 27.8 \% \mathrm{~S},\) and \(61.7 \% \mathrm{Cl}\) (b) \(21.7 \% \mathrm{C}, 9.6 \% \mathrm{O},\) and \(68.7 \% \mathrm{~F}\) (c) \(32.79 \% \mathrm{Na}, 13.02 \% \mathrm{Al},\) and the remainder \(\mathrm{F}\)

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