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Polydentate ligands can vary in the number of coordination positions they occupy. In each of the following, identify the polydentate ligand present and indicate the probable number of coordination positions it occupies: (a) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}(o\) -phen \()\right] \mathrm{Cl}_{3}\) (b) \(\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right] \mathrm{Br}\) (c) \(\left[\mathrm{Cr}(\mathrm{EDTA})\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{-}\) (d) \(\left[\mathrm{Zn}(\mathrm{en})_{2}\right]\left(\mathrm{ClO}_{4}\right)_{2}\)

Short Answer

Expert verified
In the given complexes: (a) The polydentate ligand is o-phenanthroline (o-phen), which is a bidentate ligand occupying two coordination positions. (b) The polydentate ligand is oxalate ion (\(\mathrm{C}_{2}\mathrm{O}_{4}\)), which is a bidentate ligand occupying two coordination positions. (c) The polydentate ligand is ethylenediaminetetraacetic acid (EDTA), which is a hexadentate ligand occupying six coordination positions. (d) The polydentate ligand is ethylenediamine (en), which is a bidentate ligand occupying two coordination positions on the metal ion.

Step by step solution

01

(a) Identify the polydentate ligand and its probable coordination positions

In the complex \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}(o\) -phen \()\right] \mathrm{Cl}_{3}\), the polydentate ligand is "o-phen" which stands for o-phenanthroline. o-phenanthroline can act as a bidentate ligand, meaning it occupies two coordination positions on the metal ion. The nitrogen atoms in the heterocyclic aromatic ring system are the donor atoms that bind to the metal ion.
02

(b) Identify the polydentate ligand and its probable coordination positions

In the complex \(\left[\mathrm{Cr}\left(\mathrm{C}_{2}\mathrm{O}_{4}\right)\left(\mathrm{H}_{2}\mathrm{O}\right)_{4}\right] \mathrm{Br}\), the polydentate ligand is \(\mathrm{C}_{2}\mathrm{O}_{4}\) which is the oxalate ion. Oxalate ion can act as a bidentate ligand, as it has two oxygen atoms with lone pairs that can coordinate to the metal ion. The oxalate ion occupies two coordination positions on the metal ion.
03

(c) Identify the polydentate ligand and its probable coordination positions

In the complex \(\left[\mathrm{Cr}(\mathrm{EDTA})\left(\mathrm{H}_{2}\mathrm{O}\right)\right]^{-}\), the polydentate ligand is "EDTA" which stands for ethylenediaminetetraacetic acid. EDTA is a hexadentate ligand, meaning it occupies six coordination positions on the metal ion. The donor atoms in EDTA are the two nitrogen atoms and four oxygen atoms (attached to the carboxylate groups).
04

(d) Identify the polydentate ligand and its probable coordination positions

In the complex \(\left[\mathrm{Zn}(\mathrm{en})_{2}\right]\left(\mathrm{ClO}_{4}\right)_{2}\), the polydentate ligand is "en" which stands for ethylenediamine. Ethylenediamine is a bidentate ligand, as it has two nitrogen atoms with lone pairs that can coordinate to the metal ion. The ethylenediamine ligand occupies two coordination positions on the metal ion. There are two en ligands in this complex, each taking two coordination positions, for a total of four.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polydentate Ligands
Polydentate ligands are fascinating components in coordination chemistry. These ligands possess multiple donor atoms, allowing them to bind to a metal atom at several sites. This creates complex structures known as chelates.

Polydentate ligands can significantly increase the stability of metal complexes due to the chelate effect. This is because forming rings within the complex makes it less likely for the metal to dissociate from the ligand.
  • Monodentate ligands bind through a single atom, such as the chloride ion (Cl dsup-1).
  • Bidentate ligands coordinate through two atoms, providing additional stability.
  • Tridentate, tetradentate, and hexadentate ligands bind through three, four, or six atoms respectively, creating more robust complexes.
Understanding the nature of polydentate ligands is crucial in various applications, including catalysis, materials science, and medicine.
Coordination Number
The coordination number is a critical concept in coordination chemistry, describing how many ligand atoms are directly bonded to the central metal atom. This number can vary widely depending on the metal and ligands involved, typically ranging from 2 to 9.

A higher coordination number often means a more stable and complex structure. Here’s a basic outline of coordination:
  • 2-4: Linear or square planar geometries, often found in simple metal ions.
  • 6: Octahedral geometry, common for transition metals.
  • 8-9: More complex geometries, usually seen in larger metal ions.
The coordination number affects the geometry and properties of the metal complex, influencing its reactivity and biological activity.
Metal Complexes
Metal complexes are structured entities formed when metal ions bind with ligands. These complexes play an essential role in many biological and synthetic processes.

In a metal complex, the central metal atom or ion serves as the focus, surrounded by ligands that supply electron pairs for binding. This results in diverse geometrical arrangements, depending on the coordination number and the nature of the ligands involved.
  • Chemical Stability: Metal complexes' stability depends on the type of ligands and metal used. Polydentate ligands generally form more stable complexes due to the chelate effect.
  • Biological Importance: Metal complexes are present in various biological systems, such as hemoglobin, where an iron complex is crucial for oxygen transport.
  • Catalytic Applications: They are essential in catalysis for industrial processes, helping convert raw materials into valuable products efficiently.
Understanding metal complexes is vital for grasping how they impact both industrial applications and natural biological processes.
Bidentate Ligands
Bidentate ligands are a specific type of polydentate ligand capable of binding to a central metal atom via two distinct sites. This dual binding capability often leads to more stable complexes due to the formation of a chelate ring.

Ethylenediamine ("en") is a classic example of a bidentate ligand, as seen in the zinc complex ( [Zn(en) 2 ] (ClO 4 ) 2 ). Here are some features of bidentate ligands:
  • Coordination Versatility: Bidentate ligands can form more stable compounds compared to monodentate counterparts due to their ability to occupy two coordination sites.
  • Application Range: Commonly used in stabilizing metal ions for analytical and therapeutic purposes.
  • Structural Importance: Create rings with the metal center, enhancing complex robusticity and thermal stability.
By using bidentate ligands, chemists can tailor metal complexes for specific applications, enhancing stability and functionality.

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Most popular questions from this chapter

When Alfred Werner was developing the field of coordination chemistry, it was argued by some that the optical activity he observed in the chiral complexes he had prepared was because of the presence of carbon atoms in the molecule. To disprove this argument, Werner synthesized a chiral complex of cobalt that had no carbon atoms in it, and he was able to resolve it into its enantiomers. Design a cobalt(III) complex that would be chiral if it could be synthesized and that contains no carbon atoms. (It may not be possible to synthesize the complex you design, but we won't worry about that for now.)

A manganese complex formed from a solution containing potassium bromide and oxalate ion is purified and analyzed. It contains \(10.0 \% \mathrm{Mn}, 28.6 \%\) potassium, \(8.8 \%\) carbon, and \(29.2 \%\) bromine by mass. The remainder of the compound is oxygen. An aqueous solution of the complex has about the same electrical conductivity as an equimolar solution of \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] .\) Write the formula of the compound, using brackets to denote the manganese and its coordination sphere.

Give the number of (valence) \(d\) electrons associated with the central metal ion in each of the following complexes: (a) \(\mathrm{K}_{3}\left[\mathrm{TiCl}_{6}\right]\) (b) \(\mathrm{Na}_{3}\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)_{6}\right],\) (c) \(\left[\mathrm{Ru}(\mathrm{en})_{3}\right] \mathrm{Br}_{3},\) (d) \([\mathrm{Mo}(\mathrm{EDTA})] \mathrm{ClO}_{4},(\mathrm{e}) \mathrm{K}_{3}\left[\mathrm{ReCl}_{6}\right] .\)

The \(E^{\circ}\) values for two low-spin iron complexes in acidic solution are as follows: $$ \begin{aligned} \left[\mathrm{Fe}(o \text { -phen })_{3}\right]^{3+}(a q)+\mathrm{e}^{-} \rightleftharpoons\left[\mathrm{Fe}(o \text { -phen })_{3}\right]^{2+}(a q) & E^{\circ}=1.12 \mathrm{~V} \\\ \left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}(a q)+\mathrm{e}^{-} \rightleftharpoons\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}(a q) & E^{\circ}=0.36 \mathrm{~V} \end{aligned} $$ (a) Is it thermodynamically favorable to reduce both Fe(III) complexes to their Fe(II) analogs? Explain. (b) Which complex, \(\left[\mathrm{Fe}(o \text { -phen })_{3}\right]^{3+}\) or \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-},\) is more difficult to reduce? (c) Suggest an explanation for your answer to (b).

Consider the tetrahedral anions \(\mathrm{VO}_{4}^{3-}\) (orthovanadate ion), \(\mathrm{CrO}_{4}^{2-}(\) chromate ion \(),\) and \(\mathrm{MnO}_{4}^{-}\) (permanganate ion). (a) These anions are isoelectronic. What does this statement mean? (b) Would you expect these anions to exhibit \(d-d\) transitions? Explain. (c) As mentioned in "A Closer Look" on charge-transfer color, the violet color of \(\mathrm{MnO}_{4}^{-}\) is due to a ligand-to-metal charge transfer (LMCT) transition. What is meant by this term? (d) The LMCT transition in \(\mathrm{MnO}_{4}^{-}\) occurs at a wavelength of \(565 \mathrm{nm}\). The \(\mathrm{CrO}_{4}^{2-}\) ion is yellow. Is the wavelength of the LMCT transition for chromate larger or smaller than that for \(\mathrm{MnO}_{4}^{-}\) ? Explain. (e) The \(\mathrm{VO}_{4}{ }^{3-}\) ion is colorless. Do you expect the light absorbed by the LMCT to fall in the UV or the IR region of the electromagnetic spectrum? Explain your reasoning.

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