Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

For each of the following polydentate ligands, determine (i) the maximum number of coordination sites that the ligand can occupy on a single metal ion and (ii) the number and type of donor atoms in the ligand: (a) ethylenediamine (en), (b) bipyridine (bipy), (c) the oxalate anion \(\left(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}\right),(\mathrm{d})\) the \(2-\) ion of the porphine molecule (Figure 23.13 ); (e) [EDTA] \(]\) -

Short Answer

Expert verified
In summary: (a) Ethylenediamine (en) can occupy 2 coordination sites with 2 nitrogen donor atoms. (b) Bipyridine (bipy) can occupy 2 coordination sites with 2 nitrogen donor atoms. (c) Oxalate anion can occupy 2 coordination sites with 2 oxygen donor atoms. (d) Porphine 2- ion can occupy 4 coordination sites with 4 nitrogen donor atoms. (e) [EDTA]^- can occupy 6 coordination sites with 2 nitrogen donor atoms and 4 oxygen donor atoms.

Step by step solution

01

(a) Ethylenediamine (en)

For ethylenediamine (en), the chemical formula is \(NH_2CH_2CH_2NH_2\). It has two nitrogen donor atoms, each with one lone pair of electrons that can form coordinate bonds with a metal ion. Therefore, the maximum number of coordination sites that the ligand can occupy on a single metal ion is 2. There are 2 nitrogen donor atoms in the ligand.
02

(b) Bipyridine (bipy)

Bipyridine (bipy) has the chemical formula \(C_{10}H_8N_2\), and it consists of two pyridine rings connected by a single carbon-carbon bond. Each pyridine ring has a nitrogen atom with a lone pair of electrons that can form a coordination bond with a metal ion. Therefore, the maximum number of coordination sites that the ligand can occupy on a single metal ion is 2, and there are 2 nitrogen donor atoms in the ligand.
03

(c) Oxalate anion

The oxalate anion has the chemical formula \(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}\). There are two oxygen atoms with lone pairs of electrons that can form coordinate bonds with a metal ion. Therefore, the maximum number of coordination sites that the ligand can occupy on a single metal ion is 2. There are 2 oxygen donor atoms in the ligand.
04

(d) Porphine 2- ion

The porphine 2- ion is a large and complex molecule with multiple potential donor atoms. The four nitrogen atoms located in the center of the porphine ring each have lone pairs of electrons that can form coordinate bonds with a metal ion. Therefore, the maximum number of coordination sites that the ligand can occupy on a single metal ion is 4. There are 4 nitrogen donor atoms in the ligand.
05

(e) [EDTA]

[EDTA]^- is the ethylenediaminetetraacetate ion and has a chemical formula of \(\mathrm{C}_{10} \mathrm{H}_{12} \mathrm{N}_{2} \mathrm{O}_{8}{ }^{2-}\). It has a total of 6 donor atoms: 2 nitrogen atoms and 4 oxygen atoms. The nitrogen donor atoms come from the two amino groups, and the oxygen donor atoms come from the four carboxylate groups. Therefore, the maximum number of coordination sites that the ligand can occupy on a single metal ion is 6. There are 2 nitrogen donor atoms and 4 oxygen donor atoms in the ligand.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordination Chemistry
Coordination chemistry is a branch of chemistry that focuses on the study of compounds featuring metal atoms or ions, which are surrounded by other chemical species known as ligands. These ligands are molecules or ions that can donate a pair of electrons to form a coordinate covalent bond with the metal, creating a coordination complex.

Each complex features a central metal ion or atom, which can vary in its oxidation state, size, and other chemical properties, and the ligands, which can bind to the metal in various numbers and arrangements. The region around the metal where the ligands are directly attached is called the coordination sphere.

A polydentate ligand, also known as a multidentate or chelating ligand, is capable of attaching to a metal ion or atom through multiple binding sites. This involves donation of electron pairs from the ligand to the metal, resulting in the formation of several coordinate covalent bonds within a single ligand-metal interaction. This multidentate bonding leads to the creation of highly stable complexes compared to those formed with monodentate ligands, which attach at a single point.
Donor Atoms
Donor atoms are the atoms within a ligand that actually bind to the central metal atom or ion in coordination complexes. They are the sources of the electron pairs that are donated to the metal center to form coordinate bonds. The most common donor atoms include nitrogen, oxygen, and sulfur, which have lone pairs of electrons that make them effective at binding to metal ions.

The nature of the donor atoms, including their size, electronegativity, and the electron-donating ability, can greatly influence the stability and properties of the resulting coordination complex. For instance, nitrogen donor atoms, as found in ethylenediamine and bipyridine, tend to form very strong bonds with metal ions, particularly those belonging to the first transition series. In contrast, oxygen donors, such as those in the oxalate anion, may form somewhat weaker bonds dependent on the metal but still result in significant stabilization of the complex.
Chelation
Chelation is a specific type of coordination where a single ligand occupies multiple coordination sites on a metal ion. This occurs because the ligand possesses more than one donor atom, each capable of donating a pair of electrons to the metal. The term chelation derives from the Greek word 'chele', which means claw, referring to the way these ligands appear to grasp the central metal ion.

Chelating ligands, such as ethylenediamine (en) or the ethylenediaminetetraacetate ion (EDTA), significantly increase the stability of a metal complex through the 'chelate effect'. This is primarily because chelate rings are formed during the coordination process, reducing the possibility of the ligand being replaced and thus enhancing the overall stability of the complex.

EDTA, a hexadentate ligand, forms up to six bonds with a single metal ion, making it one of the most potent chelators used in coordination chemistry. Its ability to tightly bind metal ions has made it incredibly useful in a variety of applications, such as water softening, as a chelating agent in medical treatments, and even in the remediation of heavy metal contaminated environments.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Metallic elements are essential components of many important enzymes operating within our bodies. Carbonic anhydrase, which contains \(\mathrm{Zn}^{2+}\) in its active site, is responsible for rapidly interconverting dissolved \(\mathrm{CO}_{2}\) and bicarbonate ion, \(\mathrm{HCO}_{3}^{-}\). The zinc in carbonic anhydrase is tetrahedrally coordinated by three neutral nitrogen- containing groups and a water molecule. The coordinated water molecule has a \(\mathrm{p} K_{a}\) of \(7.5,\) which is crucial for the enzyme's activity. (a) Draw the active site geometry for the \(\mathrm{Zn}(\mathrm{II})\) center in carbonic anhydrase, just writing \({ }^{4} \mathrm{~N}^{n}\) for the three neutral nitrogen ligands from the protein. (b) Compare the \(\mathrm{p} K_{a}\) of carbonic anhydrase's active site with that of pure water; which species is more acidic? (c) When the coordinated water to the \(\mathrm{Zn}(\mathrm{II})\) center in carbonic anhydrase is deprotonated, what ligands are bound to the \(\mathrm{Zn}(\mathrm{II})\) center? Assume the three nitrogen ligands are unaffected. (d) The \(\mathrm{p} K_{a}\) of \(\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) is \(10 .\) Suggest an explanation for the difference between this \(\mathrm{p} K_{a}\) and that of carbonic anhydrase. (e) Would you expect carbonic anhydrase to have a deep color, like hemoglobin and other metal-ion containing proteins do? Explain.

CC(=O)[O-] can act a… # Many trace metal ions exist in the blood complexed with amino acids or small peptides. The anion of the amino acid glycine (gly), N#CC(=O)[O-] can act as a bidentate ligand, coordinating to the metal through nitrogen and oxygen atoms. How many isomers are possible for (a) \(\left[\mathrm{Zn}(\mathrm{gly})_{2}\right]\) (tetrahedral), (b) \(\left[\mathrm{Pt}(\mathrm{gly})_{2}\right]\) (square planar), (c) \(\left[\mathrm{Co}(\mathrm{gly})_{3}\right]\) (octahedral)? Sketch all possible isomers. Use the symbol \(\mathrm{N}\) O to represent the ligand.

(a) Sketch a diagram that shows the definition of the crystal-field splitting energy \((\Delta)\) for an octahedral crystal field. (b) What is the relationship between the magnitude of \(\Delta\) and the energy of the d- \(d\) transition for a \(d^{1}\) complex? (c) Calculate \(\Delta\) in \(\mathrm{kJ} / \mathrm{mol}\) if a \(d^{1}\) complex has an absorption maximum at \(545 \mathrm{nm}\).

Which of the following objects is chiral: (a) a left shoe, (b) a slice of bread, \((c)\) a wood screw, (d) a molecular model of \(\mathrm{Zn}(\mathrm{en}) \mathrm{Cl}_{2}\) (e) a typical golf club?

Generally speaking, for a given metal and ligand, the stability of a coordination compound is greater for the metal in the +3 rather than in the +2 oxidation state (for metals that form stable +3 ions in the first place). Suggest an explanation, keeping in mind the Lewis acid-base nature of the metal-ligand bond.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free