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How many electrons are in the valence d orbitals in these transition-metal ions? (a) Co3+,(b)Cu+, (d) Os3+. (c) Cd2+

Short Answer

Expert verified
The number of electrons in the valence d orbitals for each transition-metal ion is as follows: (a) Co3+: 6 electrons (b) Cu+: 10 electrons (c) Cd2+: 10 electrons (d) Os3+: 5 electrons

Step by step solution

01

Determine the ground-state electron configurations of the given metal ions

First, we need to determine the ground-state electron configurations of each metal ion before losing any electrons. For this, we can use the periodic table to identify the atomic number Z which represents the number of protons and, in a neutral atom, the number of electrons.
02

Determine the electronic configuration of each ion

Subtract the number of lost electrons from each ion's electron total to find the electronic configuration of each ion. This is important to define the number of electrons in the valence shell of each ion.
03

Identify the number of electrons in the valence d orbitals for each ion

Finally, find the number of electrons in the valence d orbitals for each ion. Now let's find the number of electrons in the valence d orbitals for each ion:
04

(a) Co3+

1. Ground-state electron configuration of Co (cobalt): Co has an atomic number of 27, which means it has 27 electrons in a neutral state. Thus, the electron configuration of neutral Co is [Ar]4s23d7. 2. Electronic configuration of Co3+: Since Co3+ has lost 3 electrons, its electron configuration is [Ar]4s03d6. 3. Number of valence d electrons in Co3+: There are 6 electrons in the valence d orbitals.
05

(b) Cu+

1. Ground-state electron configuration of Cu (copper): Cu has an atomic number of 29, which means it has 29 electrons in a neutral state. Thus, the electron configuration of neutral Cu is [Ar]4s23d9. 2. Electronic configuration of Cu+: Since Cu+ has lost 1 electron, its electron configuration is [Ar]4s03d10. 3. Number of valence d electrons in Cu+: There are 10 electrons in the valence d orbitals.
06

(c) Cd2+

1. Ground-state electron configuration of Cd (cadmium): Cd has an atomic number of 48, which means it has 48 electrons in a neutral state. Thus, the electron configuration of neutral Cd is [Kr]5s24d10. 2. Electronic configuration of Cd2+: Since Cd2+ has lost 2 electrons, its electron configuration is [Kr]5s04d10. 3. Number of valence d electrons in Cd2+: There are 10 electrons in the valence d orbitals.
07

(d) Os3+

1. Ground-state electron configuration of Os (osmium): Os has an atomic number of 76, which means it has 76 electrons in a neutral state. Thus, the electron configuration of neutral Os is [Xe]6s24f145d6. 2. Electronic configuration of Os3+: Since Os3+ has lost 3 electrons, its electron configuration is [Xe]6s04f145d5. 3. Number of valence d electrons in Os3+: There are 5 electrons in the valence d orbitals. In summary, the number of electrons in the valence d orbitals for each ion is: (a) Co3+: 6 electrons (b) Cu+: 10 electrons (c) Cd2+: 10 electrons (d) Os3+: 5 electrons

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transition Metal Ions
Transition metal ions play a vital role in chemistry, in part due to the unique properties of their valence d orbitals. These ions are formed when atoms of transition metals lose electrons, often from their outermost shells, resulting in a positively charged ion. The term 'transition' denotes their position on the periodic table, sandwiched between the s-block and p-block elements. They are known for their color, catalytic properties, and the ability to form a variety of complex compounds.

The valence d orbitals are particularly important because they can house up to ten electrons and are largely responsible for the magnetic and chemical behaviors of these metals and their ions. During ion formation, the energy required to remove electrons usually means that the s orbital electrons are lost before the d orbital electrons, despite the counterintuitive order on the periodic table. This behavior of transition metal ions is crucial in fields such as materials science, biochemistry, and industrial chemistry, where they are employed in everything from electronic structures to enzyme functions.
Electron Configuration
The electron configuration of an atom or ion tells us how electrons are distributed among various orbitals. For transition metals, this configuration becomes more complex due to the involvement of d orbitals, which are of higher energy than s and p orbitals in the same shell. The unique arrangement of electrons in these d orbitals gives transition metals their distinctive properties, including variable oxidation states.

When transition metals form ions, they tend to lose the s orbital electrons first, followed by the d orbital electrons, if necessary. Understanding and predicting the electron configuration of transition metal ions is central to explaining their reactivity, the types of bonds they can form, and their overall chemistry. For instance, the loss of electrons to form \(Co3+, Cu+, Cd2+, and Os3+ \) ions alters the electron configuration and directly affects the number of electrons in their valence d orbitals, which can be determined using the specifically defined steps in the step-by-step solution.
Periodic Table
The periodic table is an essential tool for chemists and a systematic way to organize the elements according to their atomic structure and properties. Its layout is such that it reflects the periodicity of element properties, which is instrumental in predicting the behavior of atoms during chemical reactions. For transition metals, the periodic table provides information on their position between Groups 3 to 12.

Through the periodic table, we can determine an element's atomic number, which is equal to its number of protons and, in an electrically neutral atom, its number of electrons. This assists us in figuring out the ground-state electron configurations of elements and their ions, as well as provides clues about their possible interactions with other elements. For example, knowing the position of Cobalt, Copper, Cadmium, and Osmium on the periodic table, and understanding their propensity to form specific ions, we can deduce their valence electron configurations and make predictions about their physical and chemical behavior.

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Most popular questions from this chapter

Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) hexaamminechromium(III) nitrate (b) tetraamminecarbonatocobalt(III) sulfate (c) dichlorobis(ethylenediamine) platinum(IV) bromide (d) potassium diaquatetrabromovanadate(III) (e) bis(ethylenediamine) zinc(II) tetraiodomercurate(II)

Oxyhemoglobin, with an O2 bound to iron, is a low-spin Fe(II) complex; deoxyhemoglobin, without the O2 molecule, is a high-spin complex. (a) Assuming that the coordination environment about the metal is octahedral, how many unpaired electrons are centered on the metal ion in each case? (b) What ligand is coordinated to the iron in place of O2 in deoxyhemoglobin? (c) Explain in a general way why the two forms of hemoglobin have different colors (hemoglobin is red, whereas deoxyhemoglobin has a bluish cast). (d) A 15 -minute exposure to air containing 400 ppm of CO causes about 10% of the hemoglobin in the blood to be converted into the carbon monoxide complex, called carboxyhemoglobin. What does this suggest about the relative equilibrium constants for binding of carbon monoxide and O2 to hemoglobin? (e) CO is a strong-field ligand. What color might you expect carboxyhemoglobin to be?

The molecule dimethylphosphinoethane [(CH3)2PCH2 CH2P(CH3)2, which is abbreviated dmpe ] is used as a ligand for some complexes that serve as catalysts. A complex that contains this ligand is Mo(CO)4( dmpe ). (a) Draw the Lewis structure for dmpe, and compare it with ethylenediammine as a coordinating ligand. (b) What is the oxidation state of Mo in Extra \left or missing \right dmpe Missing \left or extra \right Sketch the structure of the [Mo(CN)2(CO)2(dmpe)]2 ion, including all the pos- sible isomers.

(a) What is the difference between Werner's concepts of primary valence and secondary valence? What terms do we now use for these concepts? (b) Why can the NH3 molecule serve as a ligand but the BH3 molecule cannot?

For each of the following metals, write the electronic configu- ration of the atom and its 2+ ion: ( a) Mn, (b) Ru, (c) Rh. Draw the crystal-field energy-level diagram for the d orbitals of an octahedral complex, and show the placement of the d electrons for each 2+ ion, assuming a strong-field complex. How many unpaired electrons are there in each case?

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