Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) Draw the Lewis structures for at least four species that have the general formula $$ [: X=Y:]^{n} $$ where \(\mathrm{X}\) and \(\mathrm{Y}\) may be the same or different, and \(n\) may have a value from +1 to -2 . (b) Which of the compounds is likely to be the strongest Bronsted base? Explain. [Sections \(22.1,22.7,\) and 22.9\(]\)

Short Answer

Expert verified
The Lewis structures for the four species CO, NO^{-}, SO^{+}, and NN are as follows: CO: :C::[::]O: , NO^{-}: :N::[::]O^- , SO^{+}: [:S:]^+::O: , and NN: :N::[::]N:. Among these species, NO^{-} is likely to be the strongest Bronsted base due to its -1 charge and the electronegativity of the oxygen atom.

Step by step solution

01

Understanding the general formula of the compounds

The general formula given is [: X=Y:]^{n}, where X and Y can be the same or different, and they are both non-metal atoms as they are making a double bond with each other. We also need to remember that n can have a value from +1 to -2. This will give us variations in the compounds.
02

Choose different combinations of X and Y atoms and determine n for each

Let's choose some combinations of elements for X and Y and determine n for each: (i) CO: X=Carbon (C), Y=Oxygen (O). n=0 (neutral molecule) (ii) NO^{-}: X=Nitrogen (N), Y=Oxygen (O). n=-1 (iii) SO^{+}: X=Sulfur (S), Y=Oxygen (O). n=+1 (iv) NN: X=Nitrogen (N), Y=Nitrogen (N). n=0 (neutral molecule) Now, let's draw their Lewis structures.
03

Draw the Lewis structures for each compound

(i) CO (Carbon Monoxide): C being the central atom has 4 valence electrons, and O has 6 valence electrons: :C::[::]O: (ii) NO^{-} (Nitrogen Monoxide Ion): N has 5 valence electrons and O has 6 valence electrons, with an added electron because it has a -1 charge.: :N::[::]O^- (iii) SO^{+} (Sulfur-Oxygen Ion): S has 6 valence electrons, and O has 6 valence electrons, with one less electron due to the +1 charge: [:S:]^+::O: (iv) NN (Nitrogen Gas): N has 5 valence electrons: :N::[::]N:
04

Determine the strongest Bronsted base

Since a Bronsted base is a compound that donates electrons to an H^+ ion, we can assess the strength of a Bronsted base by considering its basicity (or tendency to attract H^+ ions). Several factors can contribute to the basicity of a compound, such as electronegativity and charge. Generally, the more negative the compound, the stronger Bronsted base it is. Based on electronegativity and charge, NO^{-} has a -1 charge, and the oxygen atom is electronegative. Thus, among these species, NO^{-} is likely to be the strongest Bronsted base.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bronsted Base
The concept of a Bronsted base is central to understanding many chemical reactions, particularly acid-base reactions. According to Bronsted's theory, a base is any substance that can accept a proton (a hydrogen ion, H+). This is an important concept to grasp because it helps explain how chemical species interact with each other in a solution.

Analyzing the exercise, we know that the strongest Bronsted base is the one that is most likely to accept a proton. Factors influencing a molecule's ability to act as a base include its charge and the presence of electronegative atoms, such as oxygen, which are keen on attracting protons due to their partial negative charge. Among the listed species, NO- stands out as the strongest Bronsted base because it has a negative charge, making it more likely to attract and accept a hydrogen ion.
Chemical Bonding
Chemical bonding is the force that holds atoms together in molecules and compounds. At the heart of chemical bonding is the concept of sharing or transferring electrons. There are several types of bonds, but the one we are concerned with here is the covalent bond, where atoms share pairs of valence electrons.

In Lewis structures, which reveal the nature of chemical bonding in molecules, a single line represents a shared pair of electrons, or a single bond. In the molecules from the exercise, like CO or NN, double lines between atoms indicate double bonds, where two pairs of electrons are shared. Determining how these electrons are shared is crucial for predicting molecular properties, reactivity, and how a molecule will interact with others, such as how it behaves as a Bronsted base.
Valence Electrons
The concept of valence electrons is fundamental in understanding chemical bonding and reactivity. These are the electrons that reside in the outermost shell of an atom and participate in the formation of chemical bonds. The number of valence electrons determines an atom's bonding behavior.

For example, in the step-by-step solution provided, carbon in CO has four valence electrons, which it uses to form multiple bonds with oxygen. Similarly, the negative charge in NO- indicates an extra valence electron that influences its ability to act as a Bronsted base. Recognizing the role valence electrons play is essential for drawing accurate Lewis structures and predicting the properties of a molecule or ion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Identify the following hydrides as ionic, metallic, or molecular: (a) \(\mathrm{BaH}_{2},\) (b) \(\mathrm{H}_{2} \mathrm{Te},\) (c) \(\mathrm{TiH}_{1.7}\).

One method proposed for removing \(\mathrm{SO}_{2}\) from the flue gases of power plants involves reaction with aqueous \(\mathrm{H}_{2} \mathrm{~S}\). Elemental sulfur is the product. (a) Write a balanced chemical equation for the reaction. (b) What volume of \(\mathrm{H}_{2} \mathrm{~S}\) at \(27^{\circ} \mathrm{C}\) and 760 torr would be required to remove the \(\mathrm{SO}_{2}\) formed by burning 2.0 tons of coal containing \(3.5 \% \mathrm{~S}\) by mass? (c) What mass of elemental sulfur is produced? Assume that all reactions are \(100 \%\) efficient.

Why does xenon form stable compounds with fluorine, whereas argon does not?

Write the chemical formula for each of the following \(\mathrm{com}^{-}\) pounds, and indicate the oxidation state of the group \(6 \mathrm{~A}\) element in each: (a) selenous acid, (b) potassium hydrogen sulfite, (c) hydrogen telluride, (d) carbon disulfide, (e) calcium sulfate, (f) cadmium sulfide, (g) zinc telluride.

Explain the following observations: (a) For a given oxidation state, the acid strength of the oxyacid in aqueous solution decreases in the order chlorine \(>\) bromine \(>\) iodine. (b) Hydrofluoric acid cannot be stored in glass bottles. (c) HI cannot be prepared by treating NaI with sulfuric acid. (d) The interhalogen \(\mathrm{ICl}_{3}\) is known, but \(\mathrm{BrCl}_{3}\) is not.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free