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In the Brønsted-Lowry concept of acids and bases, acid-base reactions are viewed as proton-transfer reactions. The stronger the acid, the weaker is its conjugate base. In what ways are redox reactions analogous? [Sections 20.1 and 20.2\(]\)

Short Answer

Expert verified
In the Brønsted-Lowry concept, acid-base reactions involve proton transfer, and conjugate acid-base pairs have a relationship between their strengths (strong acid, weak conjugate base). Analogously, redox reactions involve electron transfer, and there is a similar relationship between the strengths of oxidizing agents (strong oxidant, easily gains electrons) and reducing agents (strong reductant, easily loses electrons). Both types of reactions focus on a transfer of particles (protons for acid-base reactions and electrons for redox reactions) that determine the behavior and strength of the species involved in the reactions.

Step by step solution

01

Understanding the Brønsted-Lowry concept of acids and bases

The Brønsted-Lowry concept defines acids as proton donors and bases as proton acceptors. This concept focuses on the transfer of a proton (H⁺) between the species involved in the reaction. For instance, in the reaction: \(HA \rightarrow H⁺ + A⁻\) Here, HA is an acid, and the dissociation of HA produces a hydrogen ion (H⁺) and the conjugate base (A⁻) of the acid.
02

Conjugate acid-base pairs

In the Brønsted-Lowry concept, a conjugate acid-base pair is formed when an acid donates a proton and the conjugate base accepts it. The stronger an acid, the weaker its conjugate base and vice versa. This is because the acid's ability to donate a proton will be higher if it is strong and the conjugate base's ability to hold onto and not accept protons will also be higher.
03

Basics of redox (oxidation-reduction) reactions

Redox reactions are chemical reactions that involve the transfer of electrons between the species involved in the reaction. There are two key processes in redox reactions – oxidation (loss of electrons) and reduction (gain of electrons). These processes usually occur simultaneously, where one species is oxidized and another one is reduced.
04

Analogy between Brønsted-Lowry concept and redox reactions

In the Brønsted-Lowry concept, acid-base reactions involve proton transfer, while in redox reactions, there is a transfer of electrons. In both cases, we can notice a "transfer" involving either protons or electrons that determines the behavior of the species involved in the reactions. Additionally, just like the relationship between conjugate acid-base pairs (strong acid, weak conjugate base), in redox reactions, there exists a similar relationship between reducing agents (also called reductants) and oxidizing agents (also called oxidants). A strong reducing agent gets easily oxidized (loses electrons), while a strong oxidizing agent gets easily reduced (gains electrons). This relationship shows the similarities between the strength of these species and their counterparts in the Brønsted-Lowry concept. In conclusion, the analogy between the Brønsted-Lowry concept of acids and bases with redox reactions lies in the transfer of particles (protons in acid-base reactions and electrons in redox reactions) and the relationship between the strength of the species involved in the reactions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proton-Transfer Reactions
In the fascinating world of chemistry, proton-transfer reactions form the backbone of the Brønsted-Lowry acid-base concept. It presents a captivating dance of protons (H+) between molecules. Imagine acids as generous donors at a charity event, freely giving away protons, while bases are the gracious recipients, readily accepting these protons. This intimate transaction fundamentally changes the identity of the substances involved.

For example, when hydrochloric acid (HCl) dissolves in water, it parts ways with a proton to become chloride (Cl), leaving behind a hydronium ion (H3O+). It's crucial to understand that these reactions are reversible, indicating that the original acid can potentially regain its lost proton from the base it donated to, showcasing the dynamic equilibrium of chemical reactions.
  • Proton donors (Acids) → proton acceptors (Bases)
  • Reversible nature of reactions
  • Change in chemical identities
Conjugate Acid-Base Pairs
Delving deeper into acid-base chemistry, the Brønsted-Lowry concept introduces us to the concept of conjugate acid-base pairs. This concept is like a before-and-after photo; an acid loses a proton and transforms into its conjugate base, while a base gains a proton becoming its conjugate acid. The ability to visualize a substance in both roles is vital for mastering the concept.

Take ammonia (NH3) for instance; it readily scoops up a proton to become ammonium (NH4+), thus the pair of NH3/NH4+ is a conjugate base/acid pair. The strength of an acid or base is inversely proportional to its conjugate partner, just like the two sides of a see-saw. Strong acids give rise to weak conjugate bases, because after they donate their proton, they lack the eagerness to reacquire it. Conversely, weak acids form strong conjugate bases, reflecting their high propensity to snatch a proton back.
  • Acid → Conjugate Base (+H+)
  • Base → Conjugate Acid (−H+)
  • Inverse relationship of strength
Redox Reactions
Moving to another transformational realm, redox reactions involve the elegant trade of electrons between molecules, akin to stock exchanges trading shares. Redox stands for reduction-oxidation, where reduction is the acquisition of electrons (think: adding electrons), and oxidation is the loss of electrons. This conceptual couplet is the electron equivalent to the proton swapping in acid-base reactions.

In this electron marketplace, substances like metals often play the role of the donors, while nonmetals tend to be the electron acceptors. If we consider rusting of iron, iron atoms (Fe) lose electrons and are oxidized, while oxygen gains electrons and is reduced. Redox reactions are the driving force behind the workings of batteries, our cells' powerhouses, and even the breath we take. They teach us that every electron lost is gained somewhere else, maintaining the world's balance, where nothing is ever lost, merely transferred.
  • Oxidation: losing electrons
  • Reduction: gaining electrons
  • Central to energy production and transfer

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Most popular questions from this chapter

(a) Based on standard reduction potentials, would you expect copper metal to oxidize under standard conditions in the presence of oxygen and hydrogen ions? (b) When the Statue of Liberty was refurbished, Teflon spacers were placed between the iron skeleton and the copper metal on the surface of the statue. What role do these spacers play?

(a) What is electrolysis? (b) Are electrolysis reactions thermodynamically spontaneous? Explain. (c) What process occurs at the anode in the electrolysis of molten \(\mathrm{NaCl} ?\) (d) Why is sodium metal not obtained when an aqueous solution of \(\mathrm{NaCl}\) undergoes electrolysis?

A voltaic cell similar to that shown in Figure 20.5 is constructed. One electrode half-cell consists of a silver strip placed in a solution of \(\mathrm{AgNO}_{3}\), and the other has an iron strip placed in a solution of \(\mathrm{FeCl}_{2}\). The overall cell reaction is $$\mathrm{Fe}(s)+2 \mathrm{Ag}^{+}(a q) \longrightarrow \mathrm{Fe}^{2+}(a q)+2 \mathrm{Ag}(s)$$ (a) What is being oxidized, and what is being reduced? (b) Write the half-reactions that occur in the two half-cells. (c) Which electrode is the anode, and which is the cathode? (d) Indicate the signs of the electrodes. (e) Do electrons flow from the silver electrode to the iron electrode or from the iron to the silver? (f) In which directions do the cations and anions migrate through the solution?

If the equilibrium constant for a two-electron redox reaction at \(298 \mathrm{~K}\) is \(1.5 \times 10^{-4},\) calculate the corresponding \(\Delta G^{\circ}\) and \(E_{\text {red }}^{\circ}\).

Gold exists in two common positive oxidation states, +1 and +3. The standard reduction potentials for these oxidation states are $$ \begin{aligned} \mathrm{Au}^{+}(a q)+\mathrm{e}^{-} \longrightarrow \mathrm{Au}(s) & E_{\mathrm{red}}^{o}=+1.69 \mathrm{~V} \\ \mathrm{Au}^{3+}(a q)+3 \mathrm{e}^{-} \longrightarrow \mathrm{Au}(s) & E_{\mathrm{red}}^{\circ}=+1.50 \mathrm{~V} \end{aligned} $$ (a) Can you use these data to explain why gold does not tarnish in the air? (b) Suggest several substances that should be strong enough oxidizing agents to oxidize gold metal. (c) Miners obtain gold by soaking gold-containing ores in an aqueous solution of sodium cyanide. A very soluble complex ion of gold forms in the aqueous solution because of the redox reaction $$ \begin{aligned} 4 \mathrm{Au}(s)+8 \mathrm{NaCN}(a q)+& 2 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{O}_{2}(g) \longrightarrow \\ & 4 \mathrm{Na}\left[\mathrm{Au}(\mathrm{CN})_{2}\right](a q)+4 \mathrm{NaOH}(a q) \end{aligned} $$ What is being oxidized and what is being reduced in this reaction? (d) Gold miners then react the basic aqueous product solution from part (c) with Zn dust to get gold metal. Write a balanced redox reaction for this process. What is being oxidized, and what is being reduced?

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