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Isomers are molecules that have the same chemical formula but different arrangements of atoms, as shown here for two isomers of pentane, \(\mathrm{C}_{5} \mathrm{H}_{12} .\) (a) Do you expect a significant difference in the enthalpy of combustion of the two isomers? Explain. (b) Which isomer do you expect to have the higher standard molar entropy? Explain. [Section 19.4\(]\)

Short Answer

Expert verified
(a) We expect a slight difference in the enthalpy of combustion of the two isomers due to the different arrangements of atoms affecting the strength of their chemical bonds. However, this difference is generally small since their overall chemical compositions remain the same. (b) Without the specific structures of the two isomers, it is impossible to definitively determine which one has a higher standard molar entropy. However, the isomer with a more complex structure, more possible conformations, or more rotational freedom will have a higher standard molar entropy.

Step by step solution

01

Understanding Enthalpy of Combustion

Enthalpy of combustion is the amount of heat released when a substance is completely burned in excess oxygen. It depends on the strength and number of chemical bonds in the molecules, as well as their arrangement.
02

Understanding Standard Molar Entropy

Standard molar entropy is a measure of the randomness or disorder of a substance. In general, larger and more complex molecules have higher standard molar entropy. Molecules with more possible conformations or arrangements also tend to have higher standard molar entropy.
03

Addressing Enthalpy of Combustion (Part a)

Since isomers have the same chemical formula, the overall number and types of atoms are the same. However, their arrangement of atoms may affect the strength of their chemical bonds to some extent. If the difference in the arrangement of atoms is significant, it can result in a small difference in the enthalpy of combustion. However, it is generally expected that the enthalpy of combustion of isomers remains relatively similar because the overall chemical composition remains the same.
04

Addressing Standard Molar Entropy (Part b)

To determine which isomer has a higher standard molar entropy, we need to analyze their molecular structures. The isomer with a more complex structure, more possible conformations, or more rotational freedom will have a higher standard molar entropy. Without knowing the specific structures of the two isomers, it is impossible to definitively determine which one has a higher standard molar entropy. However, we can make general predictions based on our understanding of entropy and its dependence on molecular structure.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy of combustion
Enthalpy of combustion is a fascinating concept that explores how much heat a substance releases when it burns in oxygen. For students studying chemistry, it's important to note how this helps us understand energy changes during chemical reactions. When looking specifically at isomers — molecules with identical molecular formulas but different configurations — the enthalpy of combustion can be expectedly similar. This is because they contain the same types and numbers of atoms.
Yet, their varied arrangements can slightly influence the strength of their bonds. This can result in minor differences in enthalpy. Nonetheless, since they share the same chemical composition, the expected difference is usually not substantial.
Comprehending how atoms are connected and how bonding influences energy release is an exciting part of exploring chemical reactions.
Standard molar entropy
Standard molar entropy offers us a peek into the disorder within substances. It's a measure of the randomness or chaos at the molecular level. Simply, it's a tally of all the different ways a molecule can be arranged. Entropy tends to increase with molecular complexity.
When considering isomers, even though they possess the same atoms, their molecular shapes might differ. Higher standard molar entropy is often seen in molecules with more complex structures, more possible arrangements, or greater freedom of rotation.
This means that the isomer with more available configurations or a more intricate structure could exhibit higher entropy. Therefore, understanding which form offers more "wiggle room" helps predict which isomer will potentially possess higher standard molar entropy.
Molecular structure
At its core, molecular structure is about how atoms are arranged within a molecule. For chemistry students, grasping this concept is crucial as it influences a molecule's properties and behavior.
Isomers are perfect exemplars of this, with their identical molecular formulas but distinct atomic arrangements. These varying structures can influence physical and chemical properties significantly. For instance, subtle differences can affect how molecules interact or the energy needed within reactions.
Additionally, the structure may impact physical characteristics such as melting or boiling points. Understanding molecular structures aids in predicting and explaining why certain isomers behave differently, even when their chemical formulas suggest otherwise.

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Most popular questions from this chapter

The following data compare the standard enthalpies and free energies of formation of some crystalline ionic substances and aqueous solutions of the substances: $$ \begin{array}{lrr} \text { Substance } & \Delta \boldsymbol{H}_{f}^{\circ}(\mathbf{k} \mathbf{J} / \mathbf{m o l}) & \Delta \mathbf{G}_{f}^{\circ}(\mathbf{k J} / \mathbf{m o l}) \\ \hline \mathrm{AgNO}_{3}(s) & -124.4 & -33.4 \\ \mathrm{AgNO}_{3}(a q) & -101.7 & -34.2 \\ \mathrm{MgSO}_{4}(s) & -1283.7 & -1169.6 \\ \mathrm{MgSO}_{4}(a q) & -1374.8 & -1198.4 \end{array} $$ (a) Write the formation reaction for \(\mathrm{AgNO}_{3}(s) .\) Based on this reaction, do you expect the entropy of the system to increase or decrease upon the formation of \(\mathrm{AgNO}_{3}(s) ?\) (b) Use \(\Delta H_{f}^{\circ}\) and \(\Delta G_{f}^{\circ}\) of \(\mathrm{AgNO}_{3}(s)\) to determine the entropy change upon formation of the substance. Is your answer consistent with your reasoning in part (a)? (c) Is dissolving \(\mathrm{AgNO}_{3}\) in water an exothermic or endothermic process? What about dissolving \(\mathrm{MgSO}_{4}\) in water? (d) For both \(\mathrm{AgNO}_{3}\) and \(\mathrm{MgSO}_{4},\) use the data to calculate the entropy change when the solid is dissolved in water. (e) Discuss the results from part (d) with reference to material presented in this chapter and in the "A Closer Look" box on page 540 .

The reaction $$ \mathrm{SO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{~S}(g) \rightleftharpoons 3 \mathrm{~S}(s)+2 \mathrm{H}_{2} \mathrm{O}(g) $$ is the basis of a suggested method for removal of \(\mathrm{SO}_{2}\) from power-plant stack gases. The standard free energy of each substance is given in Appendix \(\mathrm{C}\). (a) What is the equilibrium constant for the reaction at \(298 \mathrm{~K}\) ? (b) In principle, is this reaction a feasible method of removing \(\mathrm{SO}_{2} ?\) (c) If \(P_{\mathrm{SO}_{2}}=P_{\mathrm{H}_{2} \mathrm{~S}}\) and the vapor pressure of water is 25 torr, calculate the equilibrium \(\mathrm{SO}_{2}\) pressure in the system at \(298 \mathrm{~K}\). (d) Would you expect the process to be more or less effective at higher temperatures?

Using the data in Appendix \(C\) and given the pressures listed, calculate \(\Delta G^{\circ}\) for each of the following reactions: $$ \begin{array}{l} \text { (a) } \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g) \\ \quad P_{\mathrm{N}_{2}}=2.6 \mathrm{~atm}, P_{\mathrm{H}_{2}}=5.9 \mathrm{~atm}, P_{\mathrm{NH}_{3}}=1.2 \mathrm{~atm} \\ \text { (b) } 2 \mathrm{~N}_{2} \mathrm{H}_{4}(g)+2 \mathrm{NO}_{2}(g) \longrightarrow 3 \mathrm{~N}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(g) \\ \quad P_{\mathrm{N}_{2} \mathrm{H}_{4}}=P_{\mathrm{NO}_{2}}=5.0 \times 10^{-2} \mathrm{~atm} \\ \quad P_{\mathrm{N}_{2}}=0.5 \mathrm{~atm}, P_{\mathrm{H}_{2} \mathrm{O}}=0.3 \mathrm{~atm} \\ \text { (c) } \mathrm{N}_{2} \mathrm{H}_{4}(g) \longrightarrow \mathrm{N}_{2}(g)+2 \mathrm{H}_{2}(g) \\ \quad P_{\mathrm{N}_{2} \mathrm{H}_{4}}=0.5 \mathrm{~atm}, P_{\mathrm{N}_{2}}=1.5 \mathrm{~atm}, P_{\mathrm{H}_{2}}=2.5 \mathrm{~atm} \end{array} $$

(a) What do you expect for the sign of \(\Delta S\) in a chemical reaction in which two moles of gaseous reactants are converted to three moles of gaseous products? (b) For which of the processes in Exercise 19.11 does the entropy of the system increase?

The fuel in high-efficiency natural gas vehicles consists primarily of methane \(\left(\mathrm{CH}_{4}\right) .\) (a) How much heat is produced in burning 1 mol of \(\mathrm{CH}_{4}(g)\) under standard conditions if reactants and products are brought to \(298 \mathrm{~K}\) and \(\mathrm{H}_{2} \mathrm{O}(l)\) is formed? (b) What is the maximum amount of useful work that can be accomplished under standard conditions by this system?

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