Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) What is the difference between a state and a microstate of a system? (b) As a system goes from state A to state B, its entropy decreases. What can you say about the number of microstates corresponding to each state? (c) In a particular spontaneous process, the number of microstates available to the system decreases. What can you conclude about the sign of \(\Delta S_{\text {surr }}\) ?

Short Answer

Expert verified
(a) A state of a system refers to a set of macroscopic properties, while a microstate refers to a specific arrangement of particles exhibiting those macroscopic properties. (b) As entropy decreases, the number of microstates available to the system also decreases, meaning state A has more microstates than state B. (c) If the number of microstates decreases in a spontaneous process, then the entropy change of the system is negative, and the change in entropy of the surroundings must be positive to maintain spontaneity, making \(\Delta S_{\text{total}} \geq 0\).

Step by step solution

01

(a) State and Microstate:

A state of a system refers to a specific set of macroscopic properties such as temperature, pressure, or volume. In contrast, a microstate refers to a specific arrangement of particles in a system, describing the position and momentum of each particle, such that the system exhibits the given macroscopic properties.
02

(b) Entropy and Number of Microstates:

As the system goes from state A to state B, with its entropy decreasing, it means the number of microstates available to the system is decreasing. In other words, state A has a higher number of possible microstates compared to state B since a higher entropy implies more possible microscopic arrangements.
03

(c) Change in Surroundings' Entropy:

In a particular spontaneous process, if the number of microstates available to the system decreases, it implies that the entropy change of the system, \(\Delta S_{\text{sys}}\), is negative. However, since the process is spontaneous, it is only possible if the change in entropy of the surroundings, \(\Delta S_{\text{surr}}\), compensates for this decrease. Thus, \(\Delta S_{\text{surr}}\) must be positive, making the total change in entropy, \(\Delta S_{\text{total}} = \Delta S_{\text{sys}} + \Delta S_{\text{surr}}\), greater than or equal to zero.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Microstates
In the realm of thermodynamics, "microstates" describe the myriad ways in which particles in a system can be arranged,resulting in the same macroscopic properties such as temperature or pressure. Think of microstates as the tiny building blocks that make up the larger structure of the state of a system.Each individual microstate corresponds to a unique way particles can be distributed in terms of position and momentum.For example, if you have a box with gas particles, a microstate could indicate where each particle is and how fast they're moving.
  • Microstates capture individual configurations of particles.
  • More microstates equate to higher entropy, as there's more disorder.
  • Microstates are crucial for understanding the statistical nature of entropy.
The concept of microstates allows scientists to quantify the idea of randomness or disorder in a system by using the formula for entropy:\[ S = k \ln W \]where \( S \) is the entropy, \( k \) is the Boltzmann constant, and \( W \) is the number of microstates available to the system.
Macrostates
Macrostates refer to the broader, observable properties of a system, such as temperature, pressure, and volume. These are the characteristics we can directly measure. While each macrostate can be constituted by numerous microstates, a system typically only exhibits its macroscopic properties without exposing these underlying complexities. Imagine a macrostate as the overall condition of our box of gas particles, defined by the temperature and pressure you feel or measure. While you know the gas is hot or dense, the specific arrangements of particles forming this state remain unseen.
  • Macrostates are defined by observable, measurable properties.
  • They are simplified versions of the complex arrangements inherent in microstates.
  • The shift from one macrostate to another can affect the system's entropy.
When understanding macrostates, it is essential to note that different configurations of microstates can result in the same macrostate. Thus, the number of microstates determines the macrostate's entropy level.
Spontaneous Process
A spontaneous process is one that occurs naturally without any external force helping it along.This type of process often results in an increase in the universe's total entropy.However, there can be cases where the entropy of the system itself decreases.When the number of microstates in a system decreases, such as in a system moving to a more ordered state, the system's entropy (\( \Delta S_{\text{sys}} \)) is negative.But for the process to remain spontaneous, the surroundings' entropy (\( \Delta S_{\text{surr}} \)) must increase.
  • A spontaneous process can decrease a system's entropy but still proceed due to increased surroundings' entropy.
  • This ensures the total entropy change (\( \Delta S_{\text{total}} = \Delta S_{\text{sys}} + \Delta S_{\text{surr}} \)) stays non-negative.
  • Spontaneity aligns with the second law of thermodynamics, dictating that the total entropy of a system and its surroundings never decreases.
Thus, even if within a spontaneous process the entropy of the system drops, the surrounding environment makes up for it, driving the natural progression of these processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the vaporization of liquid water to steam at a pressure of 1 atm. (a) Is this process endothermic or exothermic? (b) In what temperature range is it a spontaneous process? (c) In what temperature range is it a nonspontaneous process? (d) At what temperature are the two phases in equilibrium?

Suppose we vaporize a mole of liquid water at \(25^{\circ} \mathrm{C}\) and another mole of water at \(100{ }^{\circ} \mathrm{C}\). (a) Assuming that the enthalpy of vaporization of water does not change much between \(25^{\circ} \mathrm{C}\) and \(100^{\circ} \mathrm{C},\) which process involves the larger change in entropy? (b) Does the entropy change in either process depend on whether we carry out the process reversibly or not? Explain.

Acetylene gas, \(\mathrm{C}_{2} \mathrm{H}_{2}(g),\) is used in welding. (a) Write a balanced equation for the combustion of acetylene gas to \(\mathrm{CO}_{2}(g)\) and \(\mathrm{H}_{2} \mathrm{O}(l)\). (b) How much heat is produced in burning \(1 \mathrm{~mol}\) of \(\mathrm{C}_{2} \mathrm{H}_{2}\) under standard conditions if both reactants and products are brought to \(298 \mathrm{~K}\) ? (c) What is the maximum amount of useful work that can be accomplished under standard conditions by this reaction?

(a) What is the meaning of the standard free-energy change, \(\Delta G^{\circ},\) as compared with \(\Delta G\) ? (b) For any process that occurs at constant temperature and pressure, what is the significance of \(\Delta G=0 ?(c)\) For a certain process, \(\Delta G\) is large and negative. Does this mean that the process necessarily occurs rapidly?

Predict the sign of the entropy change of the system for each of the following reactions: (a) \(\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)\) (b) \(\mathrm{CaCO}_{3}(s) \longrightarrow \mathrm{CaO}(s)+\mathrm{CO}_{2}(g)\) (c) \(3 \mathrm{C}_{2} \mathrm{H}_{2}(g) \longrightarrow \mathrm{C}_{6} \mathrm{H}_{6}(g)\) (d) \(\mathrm{Al}_{2} \mathrm{O}_{3}(s)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{Al}(s)+3 \mathrm{H}_{2} \mathrm{O}(g)\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free