Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Predict whether aqueous solutions of the following substances are acidic, basic, or neutral: (a) \(\mathrm{AlCl}_{3}\), (b) \(\mathrm{NaBr}\), (c) \(\mathrm{NaClO},(\mathrm{d})\) \(\left[\mathrm{CH}_{3} \mathrm{NH}_{3}\right] \mathrm{NO}_{3},(\mathrm{e}) \mathrm{Na}_{2} \mathrm{SO}_{3}\)

Short Answer

Expert verified
The aqueous solutions of the given substances have the following pH nature: (a) \(\mathrm{AlCl}_{3}\) - acidic, (b) \(\mathrm{NaBr}\) - neutral, (c) \(\mathrm{NaClO}\) - basic, (d) \(\left[\mathrm{CH}_{3} \mathrm{NH}_{3}\right] \mathrm{NO}_{3}\) - acidic, and (e) \(\mathrm{Na}_{2} \mathrm{SO}_{3}\) - basic.

Step by step solution

01

Analyzing AlCl3

When \(\mathrm{AlCl}_{3}\) is dissolved in water, it forms \(\mathrm{Al}^{3+}\) and \(\mathrm{Cl}^{-}\) ions. The \(\mathrm{Al}^{3+}\) ion can undergo hydrolysis to generate \(\mathrm{H}^{+}\) ions in the solution, which makes the solution acidic. Thus, an aqueous solution of \(\mathrm{AlCl}_{3}\) is acidic. #b)
02

Analyzing NaBr

When \(\mathrm{NaBr}\) is dissolved in water, it forms \(\mathrm{Na}^{+}\) and \(\mathrm{Br}^{-}\) ions. Neither of these ions undergoes hydrolysis in water, so no \(\mathrm{H}^{+}\) or \(\mathrm{OH}^{-}\) ions are produced. As a result, an aqueous solution of \(\mathrm{NaBr}\) is neutral. #c)
03

Analyzing NaClO

When \(\mathrm{NaClO}\) is dissolved in water, it forms \(\mathrm{Na}^{+}\) and \(\mathrm{ClO}^{-}\) ions. The \(\mathrm{ClO}^{-}\) ion can react with water to generate \(\mathrm{OH}^{-}\) ions, making the solution basic. Thus, an aqueous solution of \(\mathrm{NaClO}\) is basic. #d)
04

Analyzing [CH3NH3]NO3

When \(\left[\mathrm{CH}_{3} \mathrm{NH}_{3}\right] \mathrm{NO}_{3}\) is dissolved in water, it forms \(\mathrm{CH}_{3}\mathrm{NH}_{3}^+\) and \(\mathrm{NO}_{3}^-\) ions. The \(\mathrm{CH}_{3}\mathrm{NH}_{3}^{+}\) ion can release \(\mathrm{H}^{+}\) ions in the solution, making the solution acidic. Therefore, an aqueous solution of \(\left[\mathrm{CH}_{3} \mathrm{NH}_{3}\right] \mathrm{NO}_{3}\) is acidic. #e)
05

Analyzing Na2SO3

When \(\mathrm{Na}_{2} \mathrm{SO}_{3}\) is dissolved in water, it forms \(\mathrm{Na}^{+}\) and \(\mathrm{SO}_{3}^{2-}\) ions. The \(\mathrm{SO}_{3}^{2-}\) ion can undergo hydrolysis to generate \(\mathrm{OH}^{-}\) ions, making the solution basic. Thus, an aqueous solution of \(\mathrm{Na}_{2} \mathrm{SO}_{3}\) is basic.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrolysis
Hydrolysis is a fascinating reaction involving water molecules that can change the acidity or basicity of a solution. When certain salts dissolve in water, their ions may react with water to form either hydronium ions (\(\mathrm{H}^{+}\) ) or hydroxide ions (\(\mathrm{OH}^{-}\) ).
This process is called hydrolysis, and it's crucial to determining whether a solution becomes acidic or basic.
When an anion or cation from a dissolved salt interacts with water to form more \(\mathrm{H}^{+}\) ions, the resulting solution can become acidic. Conversely, if \(\mathrm{OH}^{-}\) ions are formed, the solution turns basic.
  • For example, in the case of \(\mathrm{AlCl}_{3}\), the \(\mathrm{Al}^{3+}\) ions hydrolyze and increase \(\mathrm{H}^{+}\) concentration, making the solution acidic.
  • Meanwhile, \(\mathrm{Na}_{2} \mathrm{SO}_{3}\) hydrolyzes to form \(\mathrm{OH}^{-}\) ions, resulting in a basic solution.
Ion Formation
Ion formation occurs when ionic compounds dissolve in water, leading to the splitting of the compound into its respective ions. This is a fundamental process in aqueous chemistry.
Depending on the ions formed, the resultant solution can have different properties.
For instance, when a salt like \(\mathrm{NaBr}\) dissolves, it simplifies into \(\mathrm{Na}^{+}\) and \(\mathrm{Br}^{-}\) ions.
  • Neither of these ions significantly reacts with water to alter acidity or basicity, thereby resulting in a neutral solution.
  • Contrastingly, \(\mathrm{NaClO}\) disintegrates into \(\mathrm{Na}^{+}\) and \(\mathrm{ClO}^{-}\) ions. The \(\mathrm{ClO}^{-}\) can then react with water to produce \(\mathrm{OH}^{-}\) ions, turning the solution basic.
Understanding ion formation helps predict the behavior of substances when dissolved in water.
Acidic Solutions
Acidic solutions are solutions where the concentration of \(\mathrm{H}^{+}\) ions exceeds that of \(\mathrm{OH}^{-}\) ions. These solutions have a pH less than 7.
They often arise when a cation from a dissolved substance can donate hydrogen ions to the aqueous environment.
Consider the compound \(\mathrm{AlCl}_{3}\).
  • When it dissolves, its \(\mathrm{Al}^{3+}\) ions undergo hydrolysis to release more \(\mathrm{H}^{+}\) ions, which lowers the pH and creates an acidic solution.
  • Another example is \(\left[\mathrm{CH}_{3} \mathrm{NH}_{3}\right] \mathrm{NO}_{3}\), where \(\mathrm{CH}_{3} \mathrm{NH}_{3}^{+}\) releases \(\mathrm{H}^{+}\) ions, also leading to an acidic outcome.
Acidic solutions are crucial in many chemical reactions, and understanding their formation and properties is fundamental in chemistry.
Basic Solutions
Basic solutions feature a higher concentration of \(\mathrm{OH}^{-}\) ions than \(\mathrm{H}^{+}\) ions, giving them a pH above 7. These solutions typically arise when anions interact with water leading to the release of hydroxide ions.
For example, consider \(\mathrm{Na}_2\mathrm{SO}_3\).
  • When this compound is dissolved in water, the \(\mathrm{SO}_{3}^{2-}\) ions undergo hydrolysis, thus producing \(\mathrm{OH}^{-}\) ions and raising the pH to make a basic solution.
  • Similarly, \(\mathrm{NaClO}\) forms from \(\mathrm{ClO}^{-}\) ions reacting with water to generate \(\mathrm{OH}^{-}\) ions, and thus a basic solution is formed.
Basic solutions are common in cleaning agents and are essential for chemical reactions needing higher pH environments.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Give the conjugate base of the following Bronsted- Lowry acids: (i) \(\mathrm{HIO}_{3}\), (ii) \(\mathrm{NH}_{4}^{+}\). (b) Give the conjugate acid of the following Bronsted-Lowry bases: (i) \(\mathrm{O}^{2-}\) (ii) \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)

Indicate whether each of the following statements is correct or incorrect. For those that are incorrect, explain why they are wrong. (a) Every Bronsted-Lowry acid is also a Lewis acid. (b) Every Lewis acid is also a Bronsted-Lowry acid. (c) Conjugate acids of weak bases produce more acidic solutions than conjugate acids of strong bases. (d) \(\mathrm{K}^{+}\) ion is acidic in water because it causes hydrating water molecules to become more acidic. (e) The percent ionization of a weak acid in water increases as the concentration of acid decreases.

Arrange the following \(0.10 \mathrm{M}\) solutions in order of increasing acidity (decreasing pH): (i) \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) (ii) \(\mathrm{NaNO}_{3}\), (iii) $$ \mathrm{CH}_{3} \mathrm{COONH}_{4} \text { , (iv) } \mathrm{NaF} \text { , (v) } \mathrm{CH}_{3} \mathrm{COONa} \text { . } $$

Based on their compositions and structures and on conjugate acid-base relationships, select the stronger base in each of the following pairs: (a) \(\mathrm{NO}_{3}^{-}\) or \(\mathrm{NO}_{2}^{-},\) (b) \(\mathrm{PO}_{4}^{3-}\) or \(\mathrm{AsO}_{4}^{3-},(\mathbf{c})\) \(\mathrm{HCO}_{3}^{-}\) or \(\mathrm{CO}_{3}^{2-}\)

Calculate the \(\mathrm{pH}\) of each of the following strong acid solutions: (a) \(8.5 \times 10^{-3} \mathrm{MHBr}\), (b) \(1.52 \mathrm{~g}\) of \(\mathrm{HNO}_{3}\) in \(575 \mathrm{~mL}\) of solution, (c) \(5.00 \mathrm{~mL}\) of \(0.250 \mathrm{M} \mathrm{HClO}_{4}\) diluted to \(50.0 \mathrm{~mL}\), (d) a solution formed by mixing \(10.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{HBr}\) with \(20.0 \mathrm{~mL}\) of \(0.200 \mathrm{M} \mathrm{HCl}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free