Chapter 16: Problem 66
For solutions of a weak acid, a graph of \(\mathrm{pH}\) versus the logarithm of the initial acid concentration should be a straight line. What is the magnitude of the slope of that line?
Short Answer
Expert verified
The magnitude of the slope of the graph of pH versus the logarithm of the initial acid concentration for solutions of weak acids is \( \frac{1}{2} \).
Step by step solution
01
Write the ionization equation for a weak acid
Let's denote the weak acid as "HA". The ionization of a weak acid in water can be represented as:
\[HA + H_2O \rightleftharpoons H_3O^+ + A^-\]
02
Write the expression for the ionization constant
The ionization constant, Ka, represents the equilibrium concentrations of the ions, which can be calculated as:
\[ K_a = \frac{[H_3O^+][A^-]}{[HA]} \]
03
Simplify the expression for the concentrations
If we denote 'x' as the concentration of \(H_3O^+\), then \(A^-\) is also 'x' (since one HA produces one \(H_3O^+\) and one \(A^-\)). Thus, the concentration of HA remaining will be ([HA_initial] - x). Now we can rewrite the ionization constant expression as:
\[K_a = \frac{x^2}{[HA_{initial}] - x}\]
04
Find the H3O+ concentration, x, in terms of Ka and the initial concentration of HA
Since the acid is weak, its ionization is small, and therefore we can assume that "x" is significantly smaller than the initial concentration of "HA":
\[K_a = \frac{x^2}{[HA_{initial}]}\]
Now we can solve for x:
\[x = [H_3O^+] = \sqrt{K_a[HA_{initial}]}\]
05
Write the expression for pH and take the logarithm of both sides
The pH is related to the concentrations of the ions by the equation:
\[ pH = -\log{[H_3O^+]}\]
Substituting the expression we derived for x:
\[pH = -\log{(\sqrt{K_a[HA_{initial}]})}\]
Taking the logarithm of both sides, we get:
\[\log{(pH)} = \log{(-(1/2))} \cdot (\log{(K_a)}) + (\log{([HA_{initial}] - \log{K_a})})\]
06
Find the magnitude of the slope
In the last expression, we can observe that the coefficient, '-(1/2)', is the slope of the graph. So, the magnitude of the slope is:
\[ Slope = |- (\frac{1}{2})| = \frac{1}{2}\]
Thus, the magnitude of the slope of the graph of pH versus the logarithm of the initial acid concentration for solutions of weak acids is 1/2.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionization constant (Ka)
The ionization constant, commonly known as the acid dissociation constant (K_a), is a vital concept when studying weak acids. It measures how much an acid separates into ions in a solution. This is usually represented in equilibrium conditions. For a weak acid, not all of it will dissociate into ions, which is different from strong acids that fully ionize.
For a given weak acid (HA), the ionization can be represented by the equation:
\[HA + H_2O \rightleftharpoons H_3O^+ + A^-\]
Using this equation, we write the ionization constant expression as:
\[ K_a = \frac{[H_3O^+][A^-]}{[HA]} \]
Here, [K_a] gives insight into the strength of an acid. A higher K_a value indicates a stronger acid, which ionizes more in water. Conversely, a lower K_a signals a weaker acid as less ions are formed. Understanding how to use K_a is crucial for predicting the behavior of weak acid solutions.
For a given weak acid (HA), the ionization can be represented by the equation:
\[HA + H_2O \rightleftharpoons H_3O^+ + A^-\]
Using this equation, we write the ionization constant expression as:
\[ K_a = \frac{[H_3O^+][A^-]}{[HA]} \]
Here, [K_a] gives insight into the strength of an acid. A higher K_a value indicates a stronger acid, which ionizes more in water. Conversely, a lower K_a signals a weaker acid as less ions are formed. Understanding how to use K_a is crucial for predicting the behavior of weak acid solutions.
pH calculation
Calculating the pH of a weak acid is a key skill for understanding its acidity. The pH is a logarithmic scale used to specify the acidity or basicity of a solution. It is determined by the concentration of hydronium ions (H_3O^+) in the solution.
For weak acids, because they do not ionize completely, calculating pH involves a bit more work. From the ionization constant expression, we can derive the concentration of H_3O^+:
\[x = [H_3O^+] = \sqrt{K_a[HA_{initial}]}\]
With [H_3O^+] known, the pH of the solution is calculated as:
\[ pH = -\log{[H_3O^+]}\]
This equation reflects the negative logarithm of the H_3O^+ concentration. A lower pH value indicates higher acidity. For weak acids, pH values are typically higher than for strong acids due to incomplete ionization.
For weak acids, because they do not ionize completely, calculating pH involves a bit more work. From the ionization constant expression, we can derive the concentration of H_3O^+:
\[x = [H_3O^+] = \sqrt{K_a[HA_{initial}]}\]
With [H_3O^+] known, the pH of the solution is calculated as:
\[ pH = -\log{[H_3O^+]}\]
This equation reflects the negative logarithm of the H_3O^+ concentration. A lower pH value indicates higher acidity. For weak acids, pH values are typically higher than for strong acids due to incomplete ionization.
Equilibrium concentrations
Understanding equilibrium concentrations is crucial for analyzing weak acid solutions. When a weak acid is in a solution, it establishes an equilibrium between the ionized and non-ionized forms.
In the ionization reaction:
\[HA + H_2O \rightleftharpoons H_3O^+ + A^-\]
The concentrations of products (H_3O^+ and A^-) and reactants (HA) fluctuate until they reach a state where they do not change with time. These are the equilibrium concentrations.
Using the initial concentration of the weak acid ([HA_{initial}]), we can determine the changes in concentration due to ionization using x:
In the ionization reaction:
\[HA + H_2O \rightleftharpoons H_3O^+ + A^-\]
The concentrations of products (H_3O^+ and A^-) and reactants (HA) fluctuate until they reach a state where they do not change with time. These are the equilibrium concentrations.
Using the initial concentration of the weak acid ([HA_{initial}]), we can determine the changes in concentration due to ionization using x:
- Decrease in HA concentration by x: [HA] = [HA_{initial}] - x.
- Increase in H_3O^+ by x: [H_3O^+] = x.
- Increase in A^- by x: [A^-] = x.