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(a) Most commercial heterogeneous catalysts are extremely finely divided solid materials. Why is particle size important? (b) What role does adsorption play in the action of a heterogeneous catalyst?

Short Answer

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(a) The particle size of a heterogeneous catalyst is important because the larger its total surface area, the more efficient the catalysis and the higher the reaction rate. Finely divided solid catalysts provide a greater surface area for reactants to come into contact with the catalyst. (b) Adsorption plays a pivotal role in heterogeneous catalysis by activating reactant molecules when they attach to the catalyst's surface, promoting chemical reactions between adsorbed reactants, and allowing the formed products to desorb, making the catalyst available for further reactions.

Step by step solution

01

Part (a): Importance of particle size in heterogeneous catalysts

The particle size of a heterogeneous catalyst is important because the effectiveness of a catalyst in speeding up a chemical reaction is determined by the surface area that is available for the reactant molecules to come into contact with the catalyst. The more finely divided a solid catalyst is, the larger its total surface area. This means that the reactants have a higher probability of coming into contact with the catalyst, which leads to more efficient catalysis and a higher reaction rate.
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Part (b): Role of adsorption in heterogeneous catalysis

Adsorption plays a pivotal role in the action of a heterogeneous catalyst. When a reactant molecule comes into contact with the catalyst's surface, it gets adsorbed, or attached, to the catalyst's surface by forming chemical bonds with the catalyst. This adsorption process activates the reactant molecule by weakening its existing chemical bonds, making it more susceptible to undergo a chemical reaction. Additionally, when multiple reactant molecules are adsorbed onto the catalyst's surface, they come into closer proximity, which increases the likelihood of a reaction taking place between them. The products formed from the reaction are often weakly bound to the catalyst's surface, enabling them to desorb, or detach, from the surface and leave the catalyst available to adsorb further reactant molecules. Overall, adsorption is crucial for heterogeneous catalysis because it enables the catalyst to bring reactant molecules together on its surface, facilitate their interaction and promote the formation of products more efficiently than if the reaction were to proceed in the absence of the catalyst.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Importance of Particle Size in Catalysis
The efficiency of a heterogeneous catalyst is closely tied to the size of its particles. This is because the main arena where the catalytic action occurs is the catalyst’s surface. Smaller particles mean more surface area relative to volume, akin to how a finely ground coffee has more surface area than a coarse one, making extraction more effective.

In chemical reactions, reactants interact with the catalyst's surface, so a larger surface area provided by fine particles leads to more sites for the reactants to adhere to and react. This heightened interaction substantially accelerates the rate at which products are formed. Imagine a crowded marketplace – the more stalls there are, the more transactions can happen simultaneously. Similarly, in catalysis, reducing particle size essentially creates more 'stalls' for chemical reactions to occur, thereby boosting the reaction rate.
Adsorption in Heterogeneous Catalysis
Adsorption is the adhesion of atoms, ions, or molecules from a gas, liquid, or dissolved solid to a surface. This process is fundamental in heterogeneous catalysis as it is the first step where the reactant molecules 'stick' to the catalyst. Consider adsorption as a welcoming handshake between the reactants and the catalyst, initiating the chemical transformation.

During this handshake, the reactants may undergo changes that make them more reactive. For instance, certain chemical bonds may be weakened, facilitating a reaction that would otherwise require more energy. Moreover, adsorption brings reactants closer together, making it easier for them to interact. While ensuring that the reactants are in the right place at the right time, adsorption is the master coordinator of the catalytic event.
Surface Area and Reaction Rate
The reaction rate in catalytic processes is intrinsically linked to the surface area of the catalyst. Let’s compare it to a beach on a sunny day – the larger the beachfront, the more people can enjoy the sun simultaneously. Likewise, a catalyst with a large surface area offers more space for chemical reactions to occur at the same time.

Essentially, increasing surface area allows for greater adsorption of reactants, resulting in a higher possibility of collisions between reactant molecules and the active sites on the catalyst. It is these collisions that lead to reaction and the formation of products. Therefore, maximizing the surface area available to reactants is a crucial strategy in enhancing the overall rate and efficiency of catalytic reactions.
Chemical Bonds and Catalysis
The interaction between chemical bonds and catalysts is similar to a coach improving a sports team's performance. In catalysis, the catalyst does not become part of the final product but facilitates the breaking and formation of chemical bonds, effectively 'coaching' the reactants through the reaction process.

By adsorbing reactants, the catalyst can either weaken bonds within reactant molecules or create new, temporary bonds. This lowers the activation energy required for the reaction, making it easier for reactants to transform into products. Throughout the process, the catalyst remains unchanged, ready to assist the next set of reactant molecules. This transformative role of the catalyst as a mediator of chemical bonds is at the core of how it accelerates reactions without being consumed by them.

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Most popular questions from this chapter

Explain why rate laws generally cannot be written from balanced equations. Under what circumstance is the rate law related directly to the balanced equation for a reaction?

Consider a hypothetical reaction between \(A, B,\) and \(C\) that is first order in \(A,\) zero order in \(B,\) and second order in C. (a) Write the rate law for the reaction. (b) How does the rate change when \([\mathrm{A}]\) is doubled and the other reactant concentrations are held constant? (c) How does the rate change when \([\mathrm{B}]\) is tripled and the other reactant concentrations are held constant? (d) How does the rate change when [C] is tripled and the other reactant concentrations are held constant? (e) By what factor does the rate change when the concentrations of all three reactants are tripled? (f) By what factor does the rate change when the concentrations of all three reactants are cut in half?

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Dinitrogen pentoxide \(\left(\mathrm{N}_{2} \mathrm{O}_{5}\right)\) decomposes in chloroform as a solvent to yield \(\mathrm{NO}_{2}\) and \(\mathrm{O}_{2}\). The decomposition is first order with a rate constant at \(45^{\circ} \mathrm{C}\) of \(1.0 \times 10^{-5} \mathrm{~s}^{-1}\). Calculate the partial pressure of \(\mathrm{O}_{2}\) produced from \(1.00 \mathrm{~L}\) of \(0.600 \mathrm{M} \mathrm{N}_{2} \mathrm{O}_{5}\) solution at \(45^{\circ} \mathrm{C}\) over a period of \(20.0 \mathrm{hr}\) if the gas is collected in a \(10.0-\mathrm{L}\) container. (Assume that the products do not dissolve in chloroform.)

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