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The temperature dependence of the rate constant for a reaction is tabulated as follows: $$ \begin{array}{lc} \hline \text { Temperature (K) } & k\left(M^{-1} \mathrm{~s}^{-1}\right) \\ \hline 600 & 0.028 \\ 650 & 0.22 \\ 700 & 1.3 \\ 750 & 6.0 \\ 800 & 23 \\ \hline \end{array} $$ Calculate \(E_{a}\) and \(A\).

Short Answer

Expert verified
After plotting the natural logarithm of the rate constants (ln(k)) against the inverse of the temperatures (1/T) and finding the linear regression, we can calculate the activation energy (Ea) and pre-exponential factor (A) using the equations: \(Ea = -mR\) and \(A = e^b\), where m is the slope and b is the y-intercept from the linear regression.

Step by step solution

01

Logarithmic form of Arrhenius equation

\[ ln(k) = ln(A) - \frac{Ea}{RT} \] #Step 2: Calculate slope and intercept of the linear regression# Now, we need to find the best linear regression for the given data to determine the activation energy (Ea) and the pre-exponential factor (A). To do this, we can plot the natural logarithm of the given rate constants (ln(k)) against the inverse of the temperatures (1/T), which should give us a linear result.
02

Linear regression equations

\[ ln(k) = b + m(1/T) \] \[ b = ln(A) \] \[ m = -\frac{Ea}{R} \] Where b is the y-intercept, m is the slope, and R is the gas constant. #Step 3: Calculate the slope and intercept from the data# Using the data given and some standard statistical methods, you can find the slope (m) and intercept (b) of the best-fit line. One can do this in either a spreadsheet program or using a calculator with regression capabilities. #Step 4: Calculate Ea and A from the slope and intercept#
03

Calculate Ea and A

Now that we have the slope (m) and intercept (b) from the best-fit line, we can use the equations we derived above to find the values of Ea and A: \[ Ea = -mR \] \[ A = e^b \] Once you calculate Ea and A using these equations, you will have solved the problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics is a branch of chemistry that deals with the rates of chemical reactions, how they change under different conditions, and what steps happen during the transition from reactants to products. Understanding chemical kinetics is crucial for various applications, such as the design of chemical reactors, the preservation of food, and even the development of medications. The speed of a reaction, or the rate at which it occurs, is affected by several factors such as temperature, pressure, and concentration of reactants.

For students diving into the realm of chemical kinetics, it's essential to understand the rate constant, which is a measure of how quickly a reaction takes place. The rate constant is dictated by the nature of the reactants, the activation energy, and the reaction's conditions. The problem provided explores how temperature influences the rate constant, emphasizing the importance of temperature in reaction kinetics.
Activation Energy
Activation energy, often symbolized as \(E_a\), is the minimum amount of energy required to initiate a chemical reaction. It can be visualized as a barrier that reactants must overcome to transform into products. The higher the activation energy, the fewer the number of molecules that have enough kinetic energy to react upon collision.

To overcome the activation energy barrier, molecules often need to collide with proper orientation and sufficient force, which can be facilitated by raising the temperature or using a catalyst. In the context of the exercise, activation energy is a vital parameter that can be extracted from data using the Arrhenius equation. Understanding \(E_a\) allows chemists to predict the speed of reactions and manipulate conditions for desired reaction rates.
Rate Constant
The rate constant \(k\) is an essential factor in chemical kinetics that provides a quantitative measure of the speed of a chemical reaction. It relates the concentration of the reactants to the rate of the reaction, reflecting how quickly reactants are converted into products. The value of the rate constant changes with different conditions, particularly temperature, and is influenced by the activation energy of the reaction.

As seen in the exercise, students are asked to comprehend how the rate constant varies with temperature, using real data to find the rate constant values at different temperatures. The Arrhenius equation, which incorporates the rate constant, activation energy, and temperature, allows students to calculate these important variables and develop a deeper understanding of reaction kinetics.
Temperature Dependence
Temperature plays a critical role in chemical kinetics by influencing the rate of a reaction. According to the Arrhenius equation, as the temperature increases, the rate constant of a reaction also increases, generally leading to a faster reaction. This is because a higher temperature means that more molecules have the kinetic energy required to overcome the activation energy barrier, resulting in more effective collisions.

In the exercise given, this temperature dependence is exhibited through a set of data connecting various temperatures with corresponding rate constants. By analyzing this data with the Arrhenius equation, students can see first-hand how a seemingly abstract concept like temperature dependence has practical implications in the calculation and understanding of a reaction's rate constant and activation energy.

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Most popular questions from this chapter

Indicate whether each statement is true or false. If it is false, rewrite it so that it is true. (a) If you measure the rate constant for a reaction at different temperatures, you can calculate the overall enthalpy change for the reaction. (b) Exothermic reactions are faster than endothermic reactions. (c) If you double the temperature for a reaction, you cut the activation energy in half.

Urea \(\left(\mathrm{NH}_{2} \mathrm{CONH}_{2}\right)\) is the end product in protein metabolism in animals. The decomposition of urea in \(0.1 \mathrm{M} \mathrm{HCl}\) occurs according to the reaction $$ \begin{aligned} \mathrm{NH}_{2} \mathrm{CONH}_{2}(a q)+\mathrm{H}^{+}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow & \mathrm{NH}_{4}^{+}(a q)+\mathrm{HCO}_{3}^{-}(a q) \end{aligned} $$ The reaction is first order in urea and first order overall. When \(\left[\mathrm{NH}_{2} \mathrm{CONH}_{2}\right]=0.200 \mathrm{M},\) the rate at \(61.05^{\circ} \mathrm{C}\) is \(8.56 \times 10^{-5} \mathrm{M} / \mathrm{s}\). (a) What is the rate constant, \(k ?\) (b) What is the concentration of urea in this solution after \(4.00 \times 10^{3} \mathrm{~s}\) if the starting concentration is \(0.500 \mathrm{M}\) ? (c) What is the half-life for this reaction at \(61.05^{\circ} \mathrm{C}\) ?

The reaction \(2 \mathrm{NO}_{2} \longrightarrow 2 \mathrm{NO}+\mathrm{O}_{2}\) has the rate constant \(k=0.63 \mathrm{M}^{-1} \mathrm{~s}^{-1}\). Based on the units for \(k\), is the reaction first or second order in \(\mathrm{NO}_{2}\) ? If the initial concentration of \(\mathrm{NO}_{2}\) is \(0.100 \mathrm{M}\), how would you determine how long it would take for the concentration to decrease to \(0.025 \mathrm{M}\) ?

The reaction between ethyl iodide and hydroxide ion in ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) solution, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}(a l c)+\mathrm{OH}^{-}(\) alc \() \longrightarrow\) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{I}^{-}(\) alc \(),\) has an activation energy of \(86.8 \mathrm{~kJ} / \mathrm{mol}\) and a frequency factor of \(2.10 \times 10^{11} \mathrm{M}^{-1} \mathrm{~s}^{-1}\). (a) Predict the rate constant for the reaction at \(35^{\circ} \mathrm{C}\). (b) \(\mathrm{A}\) solution of \(\mathrm{KOH}\) in ethanol is made up by dissolving \(0.335 \mathrm{~g}\) \(\mathrm{KOH}\) in ethanol to form \(250.0 \mathrm{~mL}\) of solution. Similarly, \(1.453 \mathrm{~g}\) of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}\) is dissolved in ethanol to form \(250.0 \mathrm{~mL}\) of solution. Equal volumes of the two solutions are mixed. Assuming the reaction is first order in each reactant, what is the initial rate at \(35^{\circ} \mathrm{C} ?\) (c) Which reagent in the reaction is limiting, assuming the reaction proceeds to completion? (d) Assuming the frequency factor and activation energy do not change as a function of temperature, calculate the rate constant for the reaction at \(50^{\circ} \mathrm{C}\).

(a) Consider the combustion of ethylene, \(\mathrm{C}_{2} \mathrm{H}_{4}(g)+3 \mathrm{O}_{2}(g)\) \(\longrightarrow 2 \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g) .\) If the concentration of \(\mathrm{C}_{2} \mathrm{H}_{4}\) is decreasing at the rate of \(0.036 \mathrm{M} / \mathrm{s}\), what are the rates of change in the concentrations of \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O} ?\) (b) The rate of decrease in \(\mathrm{N}_{2} \mathrm{H}_{4}\) partial pressure in a closed reaction vessel from the reaction \(\mathrm{N}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)\) is 74 torr per hour. What are the rates of change of \(\mathrm{NH}_{3}\) partial pressure and total pressure in the vessel?

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