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(a) Consider the combustion of H2(g):2H2(g)+O2(g) 2H2O(g). If hydrogen is burning at the rate of 0.48 mol/s, what is the rate of consumption of oxygen? What is the rate of formation of water vapor? (b) The reaction 2NO(g)+Cl2(g)2NOCl(g) is carried out in a closed vessel. If the partial pressure of NO is decreasing at the rate of 56 torr /min, what is the rate of change of the total pressure of the vessel?

Short Answer

Expert verified
The rate of consumption of oxygen is 0.24mol/s and the rate of formation of water vapor is 0.48mol/s. The rate of change of total pressure of the vessel is 28torr/min.

Step by step solution

01

Identify the stoichiometric coefficients

In the balanced combustion of hydrogen, we have the equation as: 2H2(g)+O2(g)2H2O(g) Here, the stoichiometric coefficients are 2 for hydrogen, 1 for oxygen, and 2 for water vapor.
02

Relate the rates using stoichiometry

We can relate the rate of consumption of hydrogen, oxygen, and formation of water vapor using their stoichiometric coefficients: d[H2]dt:d[O2]dt:d[H2O]dt=2:1:2
03

Calculate the rate of consumption of oxygen

The given rate of consumption of hydrogen is 0.48 mol/s: d[H2]dt=0.48mol/s Using the ratio from Step 2, we can calculate the rate of consumption of oxygen: d[O2]dt=(0.48(1))/(2)=0.24mol/s
04

Calculate the rate of formation of water vapor

Similarly, using the ratio from Step 2, we can calculate the rate of formation of water vapor: d[H2O]dt=(0.482)/(2)=0.48mol/s b) Rate of change of the total pressure of the vessel
05

Identify the stoichiometric coefficients

In the balanced reaction, we have the equation as: 2NO(g)+Cl2(g)2NOCl(g) Here, the stoichiometric coefficients are 2 for NO, 1 for Cl₂, and 2 for NOCl.
06

Relate the rates using stoichiometry

We can relate the rate of consumption of NO, Cl₂, and formation of NOCl using their stoichiometric coefficients: d[NO]dt:d[Cl2]dt:d[NOCl]dt=2:1:2
07

Calculate the rate of consumption of Cl₂ and formation of NOCl

The given rate of decrease in partial pressure of NO is 56 torr/min: d[PNO]dt=56torr/min Using the ratio from Step 2, we can calculate the rate of consumption of Cl₂ and formation of NOCl: d[PCl2]dt=(56(1))/(2)=28torr/min d[PNOCl]dt=(562)/(2)=56torr/min
08

Calculate the rate of change of the total pressure

Now, we can calculate the rate of change of the total pressure of the vessel by adding the rates of change in partial pressures: d[Ptotal]dt=d[PNO]dt+d[PCl2]dt+d[PNOCl]dt=56torr/min28torr/min+56torr/min=28torr/min So, the rate of change of the total pressure of the vessel is -28 torr/min.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combustion Reactions
Combustion reactions are chemical processes where a substance reacts quickly with oxygen, releasing energy in the form of light or heat. They are commonly known as burning and are fundamental in everyday life, from engines to candles. In these reactions, oxygen (O₂) combines with a fuel (like hydrogen in the given exercise), to form combustion products.
For the exercise, we look at hydrogen combustion:
  • Reactants: 2H₂(g) + O₂(g)
  • Products: 2H₂O(g)
The stoichiometric coefficients tell us the proportion of reactants and products: 2 moles of H₂ react with 1 mole of O₂ to produce 2 moles of water vapor (H₂O). Understanding this balanced equation is key as it shows how substances interact in fixed ratios, which helps predict how much of each substance is consumed or produced during the reaction.
These equations also allow for the calculation of unknown rates. For example, if H₂ is consumed at 0.48 mol/s, you can determine the rate at which O₂ is consumed (0.24 mol/s) and the rate of water vapor formation (0.48 mol/s). This is essential for engineering and scientific calculations related to energy release and resource consumption.
Stoichiometry
Stoichiometry is the study of the quantitative relationships between reactants and products in a chemical reaction. In simple terms, it’s all about measuring the correct amount of ingredients in chemistry, much like a recipe in cooking. Stoichiometry is crucial for understanding and balancing chemical equations.
In the context of the provided exercise, stoichiometry helps us determine the rates of consumption of reactants and formation of products. Let's go through the steps using the given reaction:
  • The balanced equation: 2H₂(g) + O₂(g) → 2H₂O(g)
  • The stoichiometry of the equation is 2:1:2, meaning every 2 moles of hydrogen will react with 1 mole of oxygen to produce 2 moles of water vapor.
By using these ratios, we can relate the rates of consumption and formation. If hydrogen is consumed at a rate of 0.48 mol/s, using stoichiometry, we calculate that oxygen is consumed at a rate of 0.24 mol/s and water is produced at 0.48 mol/s.
Stoichiometry not only aids in calculating chemical quantities but also ensures efficient use of resources and predictability in chemical processes.
Reaction Rate Calculations
Reaction rate calculations are used to determine the speed of a reaction, that is, how quickly reactants are converted into products. In chemical kinetics, the reaction rate can provide insights into the dynamics of a chemical process, crucial for industries and research.
For example, let's consider the exercise with nitric oxide (NO) and chlorine (Cl₂):
  • The reaction: 2NO(g) + Cl₂(g) → 2NOCl(g)
  • Here, if the partial pressure of NO decreases by 56 torr/min, we use stoichiometry to find the rate of pressure change for Cl₂ and NOCl.
By applying the stoichiometric ratios (2:1:2), we calculate:
  • The rate of pressure decrease for Cl₂ is 28 torr/min.
  • The rate of pressure increase for NOCl is 56 torr/min.
Next, we determine the overall rate of pressure change in the vessel:
Calculate it by summing the rates: i.e., i.e., -56 (NO) + -28 (Cl₂) + 56 (NOCl) which equals -28 torr/min.
Reaction rate calculations allow prediction and control of reaction speeds, essential for both safety and efficiency in chemical manufacturing.

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Most popular questions from this chapter

(a) Consider the combustion of ethylene, C2H4(g)+3O2(g) 2CO2(g)+2H2O(g). If the concentration of C2H4 is decreasing at the rate of 0.036M/s, what are the rates of change in the concentrations of CO2 and H2O? (b) The rate of decrease in N2H4 partial pressure in a closed reaction vessel from the reaction N2H4(g)+H2(g)2NH3(g) is 74 torr per hour. What are the rates of change of NH3 partial pressure and total pressure in the vessel?

The decomposition reaction of N2O5 in carbon tetrachloride is 2 N2O54NO2+O2. The rate law is first order in N2O5. At 64C the rate constant is 4.82×103 s1. (a) Write the rate law for the reaction. (b) What is the rate of reaction when [N2O5]=0.0240M? (c) What happens to the rate when the concentration of N2O5 is doubled to 0.0480M? (d) What happens to the rate when the concentration of N2O5 is halved to 0.0120M?

Consider the following hypothetical aqueous reaction: A(aq)B(aq). A flask is charged with 0.065 mol of A in a total volume of 100.0 mL. The following data are collected:  Time (min) 010203040 Moles of A 0.0650.0510.0420.0360.031 (a) Calculate the number of moles of B at each time in the table, assuming that there are no molecules of B at time zero, and that A cleanly converts to B with no intermediates. (b) Calculate the average rate of disappearance of A for each 10 -min interval in units of M/s. (c) Between t=10 min and t=30 min, what is the average rate of appearance of B in units of M/s ? Assume that the volume of the solution is constant.

Based on their activation energies and energy changes and assuming that all collision factors are the same, which of the following reactions would be fastest and which would be slowest? Explain your answer. (a) Ea=45 kJ/mol;ΔE=25 kJ/mol (b) Ea=35 kJ/mol;ΔE=10 kJ/mol (c) Ea=55 kJ/mol;ΔE=10 kJ/mol

For the elementary process N2O5(g)NO2(g)+NO3(g) the activation energy (Ea ) and overall ΔE are 154 kJ/mol and 136 kJ/mol, respectively. (a) Sketch the energy profile for this reaction, and label Ea and ΔE. (b) What is the activation energy for the reverse reaction?

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