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It often happens that a substance possessing a smectic liquid crystalline phase just above the melting point passes into a nematic liquid crystalline phase at a higher temperature. Account for this type of behavior.

Short Answer

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In conclusion, a substance can exhibit a smectic liquid crystalline phase just above the melting point due to the relatively low temperature allowing for the formation of ordered layers in the structure. As the temperature increases, molecular motion becomes more random, breaking the ordered layers and causing a transition into the less ordered nematic liquid crystalline phase.

Step by step solution

01

Understanding Liquid Crystalline Phases

Liquid crystals possess properties of both liquids and crystals. They have a fluidity like liquids but maintain order over longer molecular ranges like crystals. There are several types of liquid crystalline phases. The two phases we're focusing on are: 1. Smectic phase: In the smectic phase, molecules are arranged in well-ordered layers which can slide past each other, allowing for fluidity. Within each layer, the molecules are less ordered and possess random orientations. 2. Nematic phase: In the nematic phase, molecules have no long-range order in their position but are directionally aligned. The nematic phase is less ordered than the smectic phase.
02

Effects of Temperature on Liquid Crystalline Phases

Temperature plays a significant role in the transition between different liquid crystalline phases. As the temperature increases, molecules gain more thermal energy and their motion becomes more random. This causes a loss of order in the molecular structure.
03

Transition from Smectic to Nematic Phase as Temperature Increases

Now that we understand the differences between smectic and nematic phases, let's discuss their behavior with increasing temperature. A substance in the smectic phase has more order than one in the nematic phase. When the material is just above its melting point and in the smectic phase, the temperature is relatively low, allowing for the formation of layer-like structures. When the temperature increases, molecular motion becomes more random due to the increased thermal energy. This added energy compromises the long-range positional order of molecules, causing the layers to break down and transition into the less ordered nematic phase. In the nematic phase, molecular alignment is maintained to some extent, but there's no significant positional order in the layers. In conclusion, a substance can exhibit a smectic liquid crystalline phase just above the melting point due to the relatively low temperature allowing for the formation of ordered layers in the structure. As the temperature increases, molecular motion becomes more random, breaking the ordered layers and causing a transition into the less ordered nematic liquid crystalline phase.

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Most popular questions from this chapter

The phase diagram of a hypothetical substance is (a) Estimate the normal boiling point and freezing point of the substance. (b) What is the physical state of the substance under the following conditions: (i) \(T=150 \mathrm{~K}, P=0.2 \mathrm{~atm}\) (ii) \(T=100 \mathrm{~K}, P=0.8 \mathrm{~atm},(\mathrm{iii}) T=300 \mathrm{~K}, P=1.0 \mathrm{~atm} ?\) (c) What is the triple point of the substance? [Section 11.6\(]\)

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The boiling points, surface tensions, and viscosities of water and several alchohols are as follows: $$ \begin{array}{lrcc} & \begin{array}{l} \text { Boiling } \\ \text { Point }\left({ }^{\circ} \mathbf{C}\right) \end{array} & \begin{array}{l} \text { Surface } \\ \text { Tension }\left(\mathbf{J} / \mathbf{m}^{2}\right) \end{array} & \begin{array}{l} \text { Viscosity } \\ (\mathbf{k g} / \mathbf{m}-\mathbf{s}) \end{array} \\ \hline \text { Water, } \mathrm{H}_{2} \mathrm{O} & 100 & 7.3 \times 10^{-2} & 0.9 \times 10^{-3} \\ \text {Ethanol, } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} & 78 & 2.3 \times 10^{-2} & 1.1 \times 10^{-3} \\ \text {Propanol, } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH} & 97 & 2.4 \times 10^{-2} & 2.2 \times 10^{-3} \\ n \text { -Butanol, } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH} & 117 & 2.6 \times 10^{-2} & 2.6 \times 10^{-3} \\\ \text {Ethylene glycol, } \mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH} & 197 & 4.8 \times 10^{-2} & 26 \times 10^{-3} \end{array} $$ (a) For ethanol, propanol, and \(n\) -butanol the boiling points, surface tensions, and viscosities all increase. What is the reason for this increase? (b) How do you explain the fact that propanol and ethylene glycol have similar molecular weights \((60\) versus \(62 \mathrm{amu}),\) yet the viscosity of ethylene glycol is more than 10 times larger than propanol? (c) How do you explain the fact that water has the highest surface tension but the lowest viscosity?

(a) Two pans of water are on different burners of a stove. One pan of water is boiling vigorously, while the other is boiling gently. What can be said about the temperature of the water in the two pans? (b) A large container of water and a small one are at the same temperature. What can be said about the relative vapor pressures of the water in the containers?

Propyl alcohol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\) and isopropyl alcohol \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}\right],\) whose space- filling models are shown, have boiling points of \(97.2^{\circ} \mathrm{C}\) and \(82.5^{\circ} \mathrm{C}\), respectively. Explain why the boiling point of propyl alcohol is higher, even though both have the molecular formula \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\).

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