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For a given substance, the liquid crystalline phase tends to be more viscous than the liquid phase. Why?

Short Answer

Expert verified
The liquid crystalline phase tends to be more viscous than the liquid phase due to differences in molecular arrangement and interactions. In the liquid phase, molecules are randomly arranged and have weak intermolecular forces, allowing them to slide past each other easily, resulting in low viscosity. In the liquid crystalline phase, molecules are partially ordered and have stronger intermolecular forces due to elongated shape and alignment. This causes greater resistance to flow, making the liquid crystalline phase more viscous than the liquid phase.

Step by step solution

01

Understanding the liquid and liquid crystalline phases

Liquid phase is a state of matter where the substance has a definite volume but no definite shape, so it takes the shape of the container it is placed in. On the other hand, the liquid crystalline phase, also known as mesophase, is a state of matter that exhibits properties between those of crystalline solids and ordinary liquids. Liquid crystals can flow like a liquid but have long-range order like crystals. Their molecules tend to be elongated and partially orient themselves along a preferred direction.
02

Analyzing molecular arrangement

In a liquid phase, molecules are randomly arranged, and they have relatively weak interactions with each other due to their isotropic nature. They can easily move and slide past each other, which allows the liquid to flow freely. In the liquid crystalline phase, the molecules are partially ordered and tend to align in specific directions or planes. This results in a more organized structure than the liquid phase.
03

Understanding molecular interactions

In the liquid crystalline phase, due to the elongated shape of the molecules and their partial alignment, these molecules tend to have stronger intermolecular forces (such as van der Waals forces) between them than those in the liquid phase.
04

Understanding viscosity

Viscosity is a measure of a substance's resistance to flow. It is influenced by factors such as molecular arrangement, intermolecular forces, and temperature. When molecules are randomly arranged and have weak interactions (like in the liquid phase), they slide past each other easily, and their resistance to flow is low, resulting in low viscosity. When molecules are partially ordered and have stronger interactions (like in the liquid crystalline phase), they resist flowing and have difficulty sliding past each other. Their resistance to flow is higher, resulting in higher viscosity.
05

Comparing viscosity of liquid and liquid crystalline phases

Based on the analysis of molecular arrangement and intermolecular interactions, we can conclude that the liquid crystalline phase tends to have more organized molecular arrangements and stronger intermolecular forces than the liquid phase. This leads to a higher resistance to flow, resulting in a more viscous liquid crystalline phase as compared to the liquid phase.

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Most popular questions from this chapter

Ethyl chloride \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\right)\) boils at \(12^{\circ} \mathrm{C}\). When liquid \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\) under pressure is sprayed on a room-temperature \(\left(25^{\circ} \mathrm{C}\right)\) surface in air, the surface is cooled considerably. (a) What does this observation tell us about the specific heat of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(g)\) as compared with \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(l) ?\) (b) Assume that the heat lost by the surface is gained by ethyl chloride. What enthalpies must you consider if you were to calculate the final temperature of the surface?

Which member in each pair has the stronger intermolecular dispersion forces: (a) \(\mathrm{Br}_{2}\) or \(\mathrm{O}_{2}\), (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{SH}\) or \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{SH},(\mathrm{c}) \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Cl}\) or \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCl} ?\)

Ethylene glycol \(\left(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right),\) the major substance in antifreeze, has a normal boiling point of \(198^{\circ} \mathrm{C} .\) By comparison, ethyl alcohol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\right)\) boils at \(78^{\circ} \mathrm{C}\) at atmospheric pressure. Ethylene glycol dimethyl ether \(\left(\mathrm{CH}_{3} \mathrm{OCH}_{2} \mathrm{CH}_{2} \mathrm{OCH}_{3}\right)\) has a normal boiling point of \(83^{\circ} \mathrm{C}\), and ethyl methyl ether \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{3}\right)\) has a normal boiling point of \(11^{\circ} \mathrm{C}\). (a) \(\mathrm{Ex}-\) plain why replacement of a hydrogen on the oxygen by a \(\mathrm{CH}_{3}\) group generally results in a lower boiling point. (b) What are the major factors responsible for the difference in boiling points of the two ethers?

The following quote about ammonia \(\left(\mathrm{NH}_{3}\right)\) is from a textbook of inorganic chemistry: "It is estimated that \(26 \%\) of the hydrogen bonding in \(\mathrm{NH}_{3}\) breaks down on melting, \(7 \%\) on warming from the melting to the boiling point, and the final \(67 \%\) on transfer to the gas phase at the boiling point." From the standpoint of the kinetic energy of the molecules, explain (a) why there is a decrease of hydrogen-bonding energy on melting and (b) why most of the loss in hydrogen bonding occurs in the transition from the liquid to the vapor state.

Explain the following observations: (a) Water evaporates more quickly on a hot, dry day than on a hot, humid day. (b) It takes longer to cook an egg in boiling water at high altitudes than it does at lower altitudes.

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