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At \(25^{\circ} \mathrm{C}\) gallium is a solid with a density of \(5.91 \mathrm{~g} / \mathrm{cm}^{3}\). Its melting point, \(29.8{ }^{\circ} \mathrm{C},\) is low enough that you can melt it by holding it in your hand. The density of liquid gallium just above the melting point is \(6.1 \mathrm{~g} / \mathrm{cm}^{3} .\) Based on this information, what unusual feature would you expect to find in the phase diagram of gallium?

Short Answer

Expert verified
The unusual feature in the phase diagram of gallium is that it has a negative slope between the solid and liquid phases, as its liquid state has a higher density (\(6.1 \thinspace g/cm^3\)) than the solid state (\(5.91 \thinspace g/cm^3\)). This behavior implies that upon melting, gallium contracts rather than expands, which is uncommon among most substances.

Step by step solution

01

Compare Density of Solid and Liquid Gallium

Compare the density of solid gallium (5.91 g/cm³) and liquid gallium (6.1 g/cm³). We will notice that the density of liquid gallium is larger than the density of solid gallium.
02

Analyze the Unusual Feature

In most substances, the density of a solid state is greater than the liquid state. However, gallium is an exception to this rule as its liquid state has a higher density than the solid state. This implies that upon melting, gallium will contract rather than expand. This unusual behavior will be reflected in its phase diagram as a negative slope between the solid and liquid phases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density is a significant property of substances that determines how much mass is contained in a given volume. This property can alter under different conditions of temperature and pressure.
For most materials, solids are denser than their liquid forms. This means they have more mass packed into each cubic centimeter. When a solid melts into a liquid, it usually expands and occupies more volume, resulting in a lower density.
This is why ice floats on water, because water expands when it freezes, making the ice less dense than the liquid water.
  • Density in solid gallium: 5.91 g/cm³
  • Density in liquid gallium: 6.1 g/cm³
Gallium, however, defies this usual behavior, with a liquid density higher than its solid density. This peculiar property makes gallium contract upon melting, instead of expanding.
Gallium
Gallium is a fascinating element primarily because of its unique properties. It is a soft, silvery metal that can melt in your hand because of its low melting point, just under 30°C. It belongs to Group 13 in the periodic table, often associated with elements like aluminum.
Pieces of gallium can transform from solid to liquid when held, highlighting its unusual behavior. Unlike most metals, once gallium is liquid, it is denser than when it's solid. This trait shows that its molecules pack more tightly in the liquid form, which is not typical for metals under these conditions. Scientists capitalize on such properties to use gallium in electronics and material sciences.
  • Melting Point: 29.8°C
  • Solid Density: 5.91 g/cm³
  • Liquid Density: 6.1 g/cm³
Gallium’s unusual density behavior can be encountered in its phase diagram, which challenges typical expectations.
Solid and liquid phases
In chemistry, understanding the transitions between solid and liquid phases is crucial. These transitions are represented in phase diagrams, which map the conditions of temperature and pressure under which the phases of a substance exist.
Substances typically expand upon melting, with solid densities higher than liquid densities. For gallium, the contrary is true. This makes its phase diagram unique, featuring a negative slope between the solid and liquid phases. In a phase diagram, the slope indicates how a substance behaves when transitioning between phases.
For gallium, because the liquid is denser, the line indicating solid to liquid transition on the diagram slopes downwards. This reflects the contraction in volume as gallium melts – an unusual behavior that sets it apart from most substances. Such a phase transition also hints at interesting applications, especially in fields where density changes are critical.

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Most popular questions from this chapter

In dichloromethane, \(\mathrm{CH}_{2} \mathrm{Cl}_{2}(\mu=1.60 \mathrm{D})\), the dispersion force contribution to the intermolecular attractive forces is about five times larger than the dipole-dipole contribution. Compared to \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\), would you expect the relative importance of the dipole-dipole contribution to increase or decrease (a) in dibromomethane \((\mu=1.43 \mathrm{D}),(\mathbf{b})\) in difluoromethane \((\mu=1.93 \mathrm{D}) ?\) Explain.

Which type of intermolecular force accounts for each of these differences: (a) \(\mathrm{CH}_{3} \mathrm{OH}\) boils at \(65^{\circ} \mathrm{C} ; \mathrm{CH}_{3} \mathrm{SH}\) boils at \(6^{\circ} \mathrm{C}\). (b) Xe is liquid at atmospheric pressure and \(120 \mathrm{~K}\), whereas \(\mathrm{Ar}\) is a gas under the same conditions. (c) \(\mathrm{Kr}\), atomic weight 84 , boils at \(120.9 \mathrm{~K},\) whereas \(\mathrm{Cl}_{2},\) molecular weight about \(71,\) boils at \(238 \mathrm{~K}\). (d) Acetone boils at \(56^{\circ} \mathrm{C}\), whereas 2 -methylpropane boils at \(-12^{\circ} \mathrm{C}\)

The following data present the temperatures at which certain vapor pressures are achieved for dichloromethane \(\left(\mathrm{CH}_{2} \mathrm{Cl}_{2}\right)\) and methyl iodide \(\left(\mathrm{CH}_{3} \mathrm{I}\right)\) : $$ \begin{array}{lllll} \text { Vapor Pressure } & & & & \\ \text { (torr): } & 10.0 & 40.0 & 100.0 & 400.0 \\ \hline T \text { for } \mathrm{CH}_{2} \mathrm{Cl}_{2}\left({ }^{\circ} \mathrm{C}\right): & -43.3 & -22.3 & -6.3 & 24.1 \\ T \text { for } \mathrm{CH}_{3} \mathrm{I}\left({ }^{\circ} \mathrm{C}\right): & -45.8 & -24.2 & -7.0 & 25.3 \end{array} $$ (a) Which of the two substances is expected to have the greater dipole-dipole forces? Which is expected to have the greater dispersion forces? Based on your answers, explain why it is difficult to predict which compound would be more volatile. (b) Which compound would you expect to have the higher boiling point? Check your answer in a reference book such as the CRC Handbook of Chemistry and Physics. (c) The order of volatility of these two substances changes as the temperature is increased. What quantity must be different for the two substances in order for this phenomenon to occur? (d) Substantiate your answer for part (c) by drawing an appropriate graph.

Identify the type or types of intermolecular forces present in each substance and then select the substance in each pair that has the higher boiling point: (a) propane \(\mathrm{C}_{3} \mathrm{H}_{8}\) or \(n\) -butane \(\mathrm{C}_{4} \mathrm{H}_{10},\) (b) diethyl ether \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3}\) or 1 -butanol \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH},\) (c) sulfur dioxide \(\mathrm{SO}_{2}\) or sulfur trioxide (d) phosgene \(\mathrm{Cl}_{2} \mathrm{CO}\) or formaldehyde \(\mathrm{H}_{2} \mathrm{CO}\). \(\mathrm{SO}_{3},\)

A watch with a liquid crystal display (LCD) does not function properly when it is exposed to low temperatures during a trip to Antarctica. Explain why the LCD might not function well at low temperature.

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