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The generic structural formula for a 1 -alkyl-3-methylimidazolium cation is where \(\mathrm{R}\) is a \(-\mathrm{CH}_{2}\left(\mathrm{CH}_{2}\right)_{n} \mathrm{CH}_{3}\) alkyl group. The melting points of the salts that form between the 1 -alkyl-3-methylimidazolium cation and the \(\mathrm{PF}_{6}^{-}\) anion are as follows: \(\mathrm{R}=\mathrm{CH}_{2} \mathrm{CH}_{3}\left(\mathrm{~m} . \mathrm{p} .=60^{\circ} \mathrm{C}\right), \mathrm{R}=\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\left(\mathrm{m.p.}=40^{\circ} \mathrm{C}\right)\) \(\mathrm{R}=\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\left(\mathrm{~m} . \mathrm{p} .=10^{\circ} \mathrm{C}\right)\) and \(\mathrm{R}=\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\left(\mathrm{~m} . \mathrm{p} .=-61^{\circ} \mathrm{C}\right) . \mathrm{Why}\) does the melting point decrease as the length of alkyl group increases?

Short Answer

Expert verified
The melting points of 1-alkyl-3-methylimidazolium salts with PF6- anion decrease with increasing alkyl chain length because the increase in Van der Waals interactions is outweighed by the decrease in molecular packing efficiency. The reduced packing efficiency is caused by the decreased structural regularity of the molecules as the alkyl chain becomes longer, resulting in weaker overall intermolecular forces and lower melting points.

Step by step solution

01

Understanding the alkyl chain length and its relationship with melting points

To understand why the melting point decreases with the length of the alkyl chain, we should consider the interactions between molecules in the solid state. In general, greater intermolecular forces lead to higher melting and boiling points. The type and strength of these intermolecular forces can be influenced by the length and structure of the alkyl chain.
02

Investigate the intermolecular forces in 1-alkyl-3-methylimidazolium salts

In 1-alkyl-3-methylimidazolium salts, there are three main types of intermolecular forces: 1. Ionic interactions between cations and anions. 2. Hydrogen bonding between cations and anions. 3. Van der Waals (dispersion) forces between alkyl chains. The first two types of forces are generally strong and, considering that the cation-anion interactions do not change with the alkyl chain length, they should not lead to a decrease in melting points. Therefore, the change in the melting points must be attributed to the Van der Waals forces between alkyl chains.
03

Understand the influence of alkyl chain length on Van der Waals forces

Van der Waals forces are weak intermolecular forces that result from the temporary fluctuation of electron density around the molecules. These dispersion forces depend on the contact area between the molecules and increase with the molecular size. A longer alkyl chain means a greater molecular surface area, which would lead to stronger Van der Waals interactions between the molecules. However, as the length of the alkyl chain increases, the structural regularity of the molecule decreases since the chains on neighboring molecules cannot be perfectly aligned. This leads to reduced molecular packing efficiency, causing a decrease in overall intermolecular forces despite the increase in Van der Waals interactions.
04

Combine the explanations to answer the exercise question

In conclusion, the melting points of 1-alkyl-3-methylimidazolium salts with PF6- anion decrease with increasing alkyl chain length because the increase in Van der Waals interactions is outweighed by the decrease in molecular packing efficiency. The reduced packing efficiency is caused by the decreased structural regularity of the molecules as the alkyl chain becomes longer, resulting in weaker overall intermolecular forces and lower melting points.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intermolecular Forces
Understanding intermolecular forces is crucial to deciphering the behavior of substances, especially regarding their melting points. In simple terms, intermolecular forces are the attractive forces that occur between molecules. They are essential for holding a substance together and dictate how molecules interact with one another.

Some primary types of intermolecular forces include ionic bonds, which are strong attractions between oppositely charged ions, hydrogen bonds, which are strong attractions involving a hydrogen atom and a more electronegative atom, and Van der Waals forces, which are comparatively weaker and arise due to transient shifts in electron density. In the context of imidazolium salts, as the length of the alkyl group increases, the molecule's ability to align in a cohesive and organized manner diminishes, resulting in a reduction of these forces overall. This concept can be counterintuitive because longer alkyl chains do indeed increase Van der Waals forces; however, their impact on structural regularity and subsequent intermolecular attractions is a more dominating factor influencing melting points.
Molecular Packing Efficiency
The concept of molecular packing efficiency refers to how tightly molecules can pack together in a solid form. Highly efficient packing leads to stronger intermolecular interactions and typically translates to higher melting and boiling points, as more energy is required to break the orderly arrangement of molecules.

When analyzing imidazolium salts with varying alkyl chain lengths, the longer chains hamper the close packing of molecules. This happens because as chains get longer, they become more flexible and can adopt numerous conformations, making it difficult to achieve a uniform structure. This decrease in molecular packing efficiency undermines the cohesive forces between molecules, which is a primary reason behind the observed trend of decreasing melting points in these salts with increasing alkyl chain length. Despite longer chains potentially contributing to stronger Van der Waals interactions, it's the ability to pack efficiently that significantly affects the melting point.
Van der Waals Forces
The Van der Waals forces are weak, non-covalent intermolecular forces that include attractions and repulsions between atoms, molecules, and surfaces. They are named after Dutch physicist Johannes Diderik van der Waals and encompass dipole-dipole interactions, induced dipole interactions, and dispersion forces (also known as London dispersion forces).

For imidazolium salts, the dispersion forces play a noteworthy role; they are prevalent between the alkyl chains and are contingent on the chains' length. As we see with imidazolium salts, an increased alkyl chain length enhances the surface area, thereby theoretically increasing Van der Waals forces due to more opportunities for temporary dipoles to interact. However, the melting point paradox—where longer chains lead to lower melting points—is explained by the concurrent decrease in molecular packing efficiency. It's an elegant example of chemistry's complexity, where an increase in one type of intermolecular force is counterbalanced by a structural factor, leading to a change in a material's properties.

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Most popular questions from this chapter

Look up and compare the normal boiling points and normal melting points of \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{H}_{2} \mathrm{~S}\). Based on these physical properties, which substance has stronger intermolecular forces? What kinds of intermolecular forces exist for each molecule?

Explain the following observations: (a) The surface tension of \(\mathrm{CHBr}_{3}\) is greater than that of \(\mathrm{CHCl}_{3} .\) (b) As temperature increases, oil flows faster through a narrow tube. (c) Raindrops that collect on a waxed automobile hood take on a nearly spherical shape. (d) Oil droplets that collect on a waxed automobile hood take on a flat shape.

Describe how a cholesteric liquid crystal phase differs from a nematic phase.

In dichloromethane, \(\mathrm{CH}_{2} \mathrm{Cl}_{2}(\mu=1.60 \mathrm{D})\), the dispersion force contribution to the intermolecular attractive forces is about five times larger than the dipole-dipole contribution. Compared to \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\), would you expect the relative importance of the dipole-dipole contribution to increase or decrease (a) in dibromomethane \((\mu=1.43 \mathrm{D}),(\mathbf{b})\) in difluoromethane \((\mu=1.93 \mathrm{D}) ?\) Explain.

(a) When you exercise vigorously, you sweat. How does this help your body cool? (b) A flask of water is connected to a vacuum pump. A few moments after the pump is turned on, the water begins to boil. After a few minutes, the water begins to freeze. Explain why these processes occur.

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