Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) What atoms must a molecule contain to participate in hydrogen bonding with other molecules of the same kind? (b) Which of the following molecules can form hydrogen bonds with other molecules of the same kind: \(\mathrm{CH}_{3} \mathrm{~F}, \mathrm{CH}_{3} \mathrm{NH}_{2}\), \(\mathrm{CH}_{3} \mathrm{OH}, \mathrm{CH}_{3} \mathrm{Br} ?\)

Short Answer

Expert verified
(a) A molecule must contain hydrogen (H) bonded to nitrogen (N), oxygen (O), or fluorine (F) to participate in hydrogen bonding with other molecules of the same kind. (b) The molecules that can form hydrogen bonds with other molecules of the same kind are \(\mathrm{CH}_{3}\mathrm{NH}_{2}\) and \(\mathrm{CH}_{3}\mathrm{OH}\).

Step by step solution

01

Understanding hydrogen bonding

Hydrogen bonding is a type of intermolecular force that occurs between molecules containing a hydrogen atom bonded to a highly electronegative element, usually nitrogen (N), oxygen (O), or fluorine (F). These special interactions occur when the positive end of a polar molecule (the hydrogen) is attracted to the negative end (N, O, or F) of another polar molecule.
02

Identifying atoms involved in hydrogen bonding for a molecule

For a molecule to participate in hydrogen bonding with other molecules of the same kind, it must have a hydrogen atom bonded to nitrogen, oxygen, or fluorine (N-H, O-H, or F-H). (a)
03

Identifying the elements required for hydrogen bonding

From Step 2, we know that a molecule must contain hydrogen (H) bonded to nitrogen (N), oxygen (O), or fluorine (F) to participate in hydrogen bonding with other molecules of the same kind. (b)
04

Determining if the given molecules can form hydrogen bonds

We will examine each molecule to see if it contains the necessary elements for hydrogen bonding. 1. \(\mathrm{CH}_{3}\mathrm{F}\): This molecule has a hydrogen atom, but it is bonded to a carbon atom instead of fluorine. Therefore, it does not have the necessary elements for hydrogen bonding. 2. \(\mathrm{CH}_{3}\mathrm{NH}_{2}\): In this molecule, hydrogen is bonded to nitrogen, so this molecule can form hydrogen bonds with other molecules of the same kind. 3. \(\mathrm{CH}_{3}\mathrm{OH}\): In this molecule, hydrogen is bonded to oxygen, so this molecule can form hydrogen bonds with other molecules of the same kind. 4. \(\mathrm{CH}_{3}\mathrm{Br}\): This molecule has a hydrogen atom, but it is bonded to a carbon atom instead of an electronegative atom (N, O, or F). Therefore, it does not have the necessary elements for hydrogen bonding.
05

Summarizing the results

The molecules that can form hydrogen bonds with other molecules of the same kind are \(\mathrm{CH}_{3}\mathrm{NH}_{2}\) and \(\mathrm{CH}_{3}\mathrm{OH}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intermolecular Forces
Intermolecular forces are the attractive forces that exist between individual molecules. They are responsible for determining the physical properties of substances, such as boiling and melting points, viscosity, and solubility. Different types of intermolecular forces include hydrogen bonds, dipole-dipole interactions, and London dispersion forces.

Hydrogen bonds are particularly strong intermolecular forces that form when a hydrogen atom bonded to a highly electronegative atom is attracted to another electronegative atom in a neighboring molecule. The strength of these bonds has a significant effect on the properties of the substance. For example, water's high boiling point and unique properties are primarily due to hydrogen bonding between the water molecules.

Dipole-dipole interactions occur between polar molecules, where the positive end of one molecule is attracted to the negative end of another. London dispersion forces are weak intermolecular forces that arise from the momentary changes in electron density in nonpolar molecules, causing temporary dipoles. All these interactions influence a substance's state, structure, and behavior.
Electronegativity
Electronegativity refers to the ability of an atom in a molecule to attract shared electrons to itself. On the periodic table, electronegativity values typically increase from left to right and bottom to top. Fluorine is the most electronegative element, followed by oxygen and nitrogen. These differences in electronegativity are crucial for understanding the formation of polar bonds and the emergence of intermolecular forces.

When there is a large difference in electronegativity between two atoms bonded together, the shared electrons are more likely to be found closer to the more electronegative atom. This creates a polar bond, with a partial negative charge on the more electronegative atom and a partial positive charge on the less electronegative one. In the context of hydrogen bonding, the high electronegativity of nitrogen, oxygen, or fluorine in relation to hydrogen is what enables these special intermolecular forces to exist. Electronegativity also helps to explain why certain molecules, despite containing hydrogen, cannot participate in hydrogen bonding if they lack sufficiently electronegative atoms bonded to hydrogen.
Polar Molecules
Polar molecules are molecules with an uneven distribution of charge due to the presence of polar bonds that are arranged asymmetrically. The existence of polar molecules is a result of differences in electronegativity between the atoms that form bonds in the molecule. A classic example is water (H_2O), where the oxygen atom is more electronegative than the hydrogen atoms, leading to a bent shape with a partial negative charge on the oxygen and a partial positive charge on the hydrogens.

Polarity in molecules is crucial for understanding solubility, reactivity, and the strength of intermolecular forces, such as hydrogen bonds. Polar molecules are often capable of forming dipole-dipole interactions with each other, and in cases where hydrogen is bound to nitrogen, oxygen, or fluorine, they can engage in hydrogen bonding, which is much stronger than regular dipole-dipole interactions. When molecules like CH_3NH_2 and CH_3OH, which have H atoms bonded to N or O, are present, they can align themselves such that opposite charges attract, forming hydrogen bonds. On the other hand, nonpolar molecules like CH_3Br cannot do this due to the uniform distribution of charge, which is why polar and nonpolar substances usually do not mix well.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The smectic liquid crystalline phase can be said to be more highly ordered than the nematic phase. In what sense is this true?

The critical temperatures \((\mathrm{K})\) and pressures \((\mathrm{atm})\) of a series of halogenated methanes are as follows: $$ \begin{array}{lcccc} \text { Compound } & \mathbf{C C l}_{3} \mathbf{F} & \mathbf{C C l}_{2} \mathbf{F}_{2} & \mathbf{C C I F}_{3} & \mathbf{C F}_{4} \\ \hline \text { Critical temperature } & 471 & 385 & 302 & 227 \\ \text { Critical pressure } & 43.5 & 40.6 & 38.2 & 37.0 \end{array} $$ (a) List the intermolecular forces that occur for each compound. (b) Predict the order of increasing intermolecular attraction, from least to most, for this series of compounds. (c) Predict the critical temperature and pressure for \(\mathrm{CCl}_{4}\) based on the trends in this table. Look up the experimentally determined critical temperatures and pressures for \(\mathrm{CCl}_{4}\), using a source such as the CRC Handbook of Chemistry and Physics, and suggest a reason for any discrepancies.

At standard temperature and pressure the molar volume of \(\mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) gases are \(22.06 \mathrm{~L}\) and \(22.40 \mathrm{~L},\) respectively (a) Given the different molecular weights, dipole moments, and molecular shapes, why are their molar volumes nearly the same? (b) \(\mathrm{On}\) cooling to \(160 \mathrm{~K}\), both substances form crystalline solids. Do you expect the molar volumes to decrease or increase on cooling to \(160 \mathrm{~K} ?\) (c) The densities of crystalline \(\mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) at \(160 \mathrm{~K}\) are \(2.02 \mathrm{~g} / \mathrm{cm}^{3}\) and \(0.84 \mathrm{~g} / \mathrm{cm}^{3}\), respectively. Calculate their molar volumes. (d) Are the molar volumes in the solid state as similar as they are in the gaseous state? Explain. (e) Would you expect the molar volumes in the liquid state to be closer to those in the solid or gaseous state?

Do you expect the viscosity of glycerol, \(\mathrm{C}_{3} \mathrm{H}_{5}(\mathrm{OH})_{3},\) to be larger or smaller than that of 1 -propanol, \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}\) ? Explain. [Section 11.3\(]\)

Explain the following observations: (a) The surface tension of \(\mathrm{CHBr}_{3}\) is greater than that of \(\mathrm{CHCl}_{3} .\) (b) As temperature increases, oil flows faster through a narrow tube. (c) Raindrops that collect on a waxed automobile hood take on a nearly spherical shape. (d) Oil droplets that collect on a waxed automobile hood take on a flat shape.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free