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What is selective precipitation? Under which conditions does selective precipitation occur?

Short Answer

Expert verified
Selective precipitation separates ions by forming an insoluble compound with a precipitating reagent when the ion product exceeds the solubility product (Ksp). It requires control of ion concentrations, pH, temperature, and a precipitating reagent.

Step by step solution

01

Understanding Selective Precipitation

Selective precipitation is a process used in chemistry to separate ions in a solution by adding a reagent that causes one or more specific types of ions to form an insoluble compound that precipitates out of the solution, while others remain in solution.
02

Conditions for Selective Precipitation

Selective precipitation occurs under conditions where the product of the ion concentrations in the solution exceeds the solubility product (Ksp) of the precipitate to be formed. This is typically achieved by controlling the concentration of the relevant ions, pH of the solution, and the temperature, as well as by the addition of a suitable precipitating reagent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility Product (Ksp)
Imagine you're adding sugar to your tea. There's a point where the tea can't dissolve any more sugar, and it starts to accumulate at the bottom of the cup. Similarly, in chemistry, the solubility product constant, or Ksp, is a value that describes the point at which a compound will no longer dissolve in a solution and begins to precipitate.

Each compound has a unique Ksp, which depends on temperature and the nature of the solid and the solvent. It's determined by multiplying the concentrations of the ions in a saturated solution, each raised to the power of their stoichiometric coefficients. For example, if the compound AB2 dissociates into A^+ and 2B^-, the Ksp would be calculated as follows: \[ K_{sp} = [A^+] \times [B^-]^2 \]
When dealing with selective precipitation, understanding Ksp is crucial because it allows us to predict whether a precipitate will form under certain conditions by comparing the actual product of ion concentrations to the Ksp.
Ion Separation
In many chemical processes, separating ions is a vital step. Think of it like sorting different colored marbles: if you want to separate the colors, you need a strategy that singles out one color from the mix. In chemistry, this process is a bit more complex, as it involves separating ions from a solution based on their individual chemical properties.

Ion separation is influenced by several factors, such as the different solubilities of the ionic compounds they form. By manipulating conditions like pH, temperature, or ionic strength, a particular ion can be targeted to form a less soluble compound. The selective precipitation works well because typically, ions have varying solubilities with different reagents. This makes it possible to precipitate one type of ion while keeping others in solution, ultimately leading to their separation. That's why understanding Ksp is vital—it provides the playbook for successfully executing this strategy.
Precipitation Reactions
Precipitation reactions are like the magic shows of chemistry: you mix two clear solutions and, as if by magic, a solid suddenly appears. But there's no magic here—just science. A precipitation reaction occurs when two soluble salts react in solution to form one or more insoluble products, known as precipitates.

For selective precipitation, it's not just about making any solid form—it's about having the right conditions for the specific solid you want to form while keeping the others dissolved. By carefully choosing the right reagent and adjusting the solution's conditions, a chemist can make one product precipitate without affecting others. Here are some key steps typically involved in precipitation reactions:
  • Determine the ions present in the solution.
  • Predict the possible products using solubility rules.
  • Calculate the Ksp of the products to see which will precipitate first.
  • Adjust conditions such as concentration and pH to control the reaction.
This targeted approach allows for the separation of specific ions in a controlled and predictable manner, showcasing the power and precision of chemical reactions in separations science.

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Most popular questions from this chapter

For each solution, calculate the initial and final pH after the addition of 0.010 mol of \(\mathrm{HCl} .\) a. 500.0 \(\mathrm{mL}\) of pure water b. 500.0 \(\mathrm{mL}\) of a buffer solution that is 0.125 \(\mathrm{M}\) in \(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\) and 0.115 \(\mathrm{M}\) in \(\mathrm{NaC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\) c. 500.0 \(\mathrm{mL}\) of a buffer solution that is 0.155 \(\mathrm{M}\) in \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}\) and 0.145 \(\mathrm{M}\) in \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{Cl}\)

Phenolphthalein has a \(\mathrm{pK}_{a}\) of \(9.7 .\) It is colorless in its acid form and pink in its basic form. For each of the pH's, calculate \(\left[\operatorname{In}^{-}\right] /[\operatorname{HIn}]\) and predict the color of a phenolphthalein solution. a. \(\mathrm{pH}=2.0\) b. \(\mathrm{pH}=5.0\) c. \(\mathrm{pH}=8.0\) d. \(\mathrm{pH}=11.0\)

Determine whether the mixing of each pair of solutions results in a buffer. a. 75.0 \(\mathrm{mL}\) of \(0.10 \mathrm{M} \mathrm{HF} ; 55.0 \mathrm{mL}\) of 0.15 \(\mathrm{MNaF}\) b. 150.0 \(\mathrm{mL}\) of \(0.10 \mathrm{M} \mathrm{HF} ; 135.0 \mathrm{mL}\) of 0.175 \(\mathrm{M} \mathrm{HCl}\) c. 165.0 \(\mathrm{mL}\) of \(0.10 \mathrm{M} \mathrm{HF} ; 135.0 \mathrm{mL}\) of 0.050 \(\mathrm{M} \mathrm{KOH}\) d. 125.0 \(\mathrm{mL}\) of \(0.15 \mathrm{M} \mathrm{CH}_{3} \mathrm{NH}_{2} ; 120.0 \mathrm{mL}\) of 0.25 \(\mathrm{M} \mathrm{CH}_{3} \mathrm{NH}_{3} \mathrm{Cl}\) e. 105.0 \(\mathrm{mL}\) of \(0.15 \mathrm{M} \mathrm{CH}_{3} \mathrm{NH}_{2} ; 95.0 \mathrm{mL}\) of 0.10 \(\mathrm{M} \mathrm{HCl}\)

Suppose that a buffer contains equal amounts of a weak acid and its conjugate base. What happens to the relative amounts of the weak acid and conjugate base when a small amount of strong acid is added to the buffer? What happens when a small amount of strong base is added?

What factors influence the effectiveness of a buffer? What are the characteristics of an effective buffer?

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