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For a binary acid, \(\mathrm{H}-\mathrm{Y},\) which factors affect the relative ease with which the acid ionizes?

Short Answer

Expert verified
The relative ease with which a binary acid ionizes is affected by the strength of the H-Y bond, the stability of the conjugate base, the electronegativity, and the size of \(\mathrm{Y}\).

Step by step solution

01

Understand Acid Ionization

To understand the factors affecting the ionization of a binary acid (an acid that has hydrogen and one other element), one must first understand what ionization is. Ionization is the process by which a neutral molecule (in this case, the acid \(\mathrm{H}-\mathrm{Y}\)) loses a hydrogen ion (\(\mathrm{H}^+\)), resulting in the formation of the conjugate base (\(\mathrm{Y}^-\)).
02

Identify the Factors Affecting Ionization

The relative ease with which a binary acid ionizes is affected by the strength of the H-Y bond and the stability of the conjugate base (\(\mathrm{Y}^-\)). A weaker H-Y bond will result in easier ionization. Additionally, the stability of the conjugate base, often related to the electronegativity and size of \(\mathrm{Y}\), influences how readily the acid will ionize.
03

Consider Electronegativity and Atom Size

The electronegativity of \(\mathrm{Y}\) affects how strongly it attracts the bonding electrons in the H-Y bond; the more electronegative \(\mathrm{Y}\) is, the more polar the bond, which can lead to easier ionization. The size of \(\mathrm{Y}\) can also affect ionization, as larger atoms can better accommodate the negative charge, resulting in a more stable conjugate base and thus more likely ionization.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid Ionization Process
When studying binary acids, it’s important to grasp the mechanism behind the acid ionization process. Acid ionization involves a binary acid, which we represent as \(\mathrm{H}-\mathrm{Y}\), losing a proton (also known as a hydrogen ion, \(\mathrm{H}^+\)) to become its conjugate base, \(\mathrm{Y}^-\). This process can be represented by the chemical equation \(\mathrm{H}-\mathrm{Y} \rightarrow \mathrm{H}^+ + \mathrm{Y}^{-}\). In water, the \(\mathrm{H}^+\) typically associates with a water molecule, forming a hydronium ion \(\mathrm{H}_3\mathrm{O}^+\).

The ease of this ionization is a key factor in determining the strength of an acid: the more readily \(\mathrm{H}-\mathrm{Y}\) donates its proton, the stronger the acid. Several factors influence this, such as the H-Y bond strength, the stability of the resulting conjugate base, and attributes of the atom Y including electronegativity and size.
H-Y Bond Strength
The strength of the bond between hydrogen and the other atom in the acid, represented as \(\mathrm{H}-\mathrm{Y}\), is pivotal in acid ionization. A stronger bond makes it harder for the acid to lose its proton, hence making the acid weaker. To understand bond strength, consider the amount of energy required to break the bond. The higher the energy required, the stronger the bond.

Factors that influence H-Y bond strength include the difference in electronegativity between hydrogen and Y, as well as the orbital overlap between the two atoms. Bonds with strong orbital overlap and a lower difference in electronegativity tend to be stronger and thus resist ionization.
Conjugate Base Stability
Once the acid \(\mathrm{H}-\mathrm{Y}\) ionizes, it forms a conjugate base \(\mathrm{Y}^-\). The stability of this conjugate base is a key factor in acid strength. A more stable conjugate base is formed when the negative charge left behind is delocalized or distributed across the molecule.

Stability can be enhanced by several factors including resonance structures and the presence of electron-withdrawing groups if Y is a more complex atom. The more stable the conjugate base, the more the equilibrium favors ionization, making for a stronger acid. Understanding the concept of conjugate base stability can help predict the acid's behavior in chemical reactions.
Electronegativity
Electronegativity is a measure of an atom's ability to attract and hold onto electrons within a bond. Within a binary acid like \(\mathrm{H}-\mathrm{Y}\), if Y is highly electronegative, it pulls bonding electrons closer, thereby polarizing the bond. Polarization makes the hydrogen more positive and more prone to being pulled away, i.e., ionized.

Elements that are more electronegative can stabilize the negative charge as a conjugate base, which tends to increase acid strength. Conversely, when Y is less electronegative, the bond is less polar, making the acid weaker. Therefore, electronegativity is directly correlated with acid ionization.
Atom Size
The size of the atom Y in the binary acid \(\mathrm{H}-\mathrm{Y}\) also influences how easily the acid ionizes. Larger atoms have more diffuse electron clouds, which means they can better distribute and accommodate a negative charge when they become the conjugate base (\(\mathrm{Y}^-\)). This distribution leads to a more stable conjugate base.

Therefore, as atom size increases, the ease with which the acid ionizes can also increase. This is especially true down the groups in the periodic table, where atoms get larger and typically produce stronger acids when bonded to hydrogen. It's crucial to note, these factorsβ€”atom size and electronegativityβ€”often interact in nuanced ways to determine acid strength.

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Most popular questions from this chapter

Autoionization of Water and pH Calculate \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) in each aqueous solution at \(25^{\circ} \mathrm{C},\) and classify each solution as acidic or basic. $$\begin{array}{l}{\text { a. }[\mathrm{OH}]=1.1 \times 10^{-9} \mathrm{M}} \\\ {\text { b. }\left[\mathrm{OH}^{-}\right]=2.9 \times 10^{-2} \mathrm{M}} \\\ {\text { c. }\left[\mathrm{OH}^{-}\right]=6.9 \times 10^{-12} \mathrm{M}}\end{array}$$

Acid-Base Properties of Ions and Salts Determine whether each cation is acidic or pH-neutral. For the cations that are acidic, write an equation that shows how the cation acts as an acid. \(\begin{array}{l}{\text { a. } \mathrm{Sr}^{2+}} \\ {\text { b. } \mathrm{Mn}^{3+}} \\ {\text { c. } \mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NH}^{+}} \\ {\text { d. } \mathrm{Li}^{+}}\end{array} \)

Without doing any calculations, determine which solution in each pair is most basic. $$\begin{array}{l}{\text { a. } 0.100 \mathrm{M} \text { in } \mathrm{NaClO} \text { and } 0.100 \mathrm{M} \text { in } \mathrm{NaF}} \\ {\text { b. } 0.0100 \mathrm{M} \text { in } \mathrm{KCl} \text { and } 0.0100 \mathrm{M} \text { in } \mathrm{KClO}_{2}} \\ {\text { c. } 0.0100 \mathrm{M} \text { in } \mathrm{HNO}_{3} \text { and } 0.0100 \mathrm{M} \text { in NaOH }} \\\ {\text { d. } 0.0100 \mathrm{M} \text { in } \mathrm{NH}_{4} \mathrm{Cl} \text { and } 0.0100 \mathrm{M} \text { in HCN }}\end{array}$$

Acid Strength and \(K_{\mathrm{a}}\) Rank the solutions in order of decreasing \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right] : 0.10 \mathrm{M} \mathrm{HCl} ; 0.10\) \(\mathrm{M} \mathrm{HF} ; 0.10 \mathrm{MClO} ; 0.10 \mathrm{MHC}_{6} \mathrm{H}_{5} \mathrm{O} .\)

Base Solutions Morphine is a weak base. A 0.150 \(\mathrm{M}\) solution of morphine has a pH of \(10.5 .\) What is \(K_{\mathrm{b}}\) for morphine?

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