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Using the idea that reactions occur as a result of collisions between particles, explain why reaction rates depend on the concentration of the reactants.

Short Answer

Expert verified
Reaction rates depend on reactant concentration because a higher concentration increases the frequency of collisions between reactant particles, thus increasing the chances of a reaction occurring.

Step by step solution

01

Understanding Collision Theory

According to collision theory, chemical reactions occur when particles of reactants collide with sufficient energy and proper orientation. This initial step is crucial for students to understand the basic principle that governs the rates of reactions.
02

Relating Concentration to Collision Frequency

Explain that if the concentration of reactants is increased, there are more particles per unit volume. This increase in particle density leads to a higher probability of collisions between reactant particles.
03

Connecting Collision Frequency to Reaction Rates

Make the connection that since reactions happen upon successful collisions, more frequent collisions due to higher concentrations of reactants will likely result in a higher rate of reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Collision Theory
Imagine a busy street. The more cars there are, the more likely they are to bump into each other, especially if they're all trying to navigate through the same intersection. This is essentially what happens on a molecular level in chemical reactions according to collision theory.

Collision theory suggests that for a reaction to occur, reactant particles must collide with enough energy to overcome the activation energy barrier. This energy is known as the activation energy, and the correct orientation of the molecules during collision is equally essential. Without the proper angle of contact, molecules may just bounce off each other, unreacted. Think of it like a key needing to be in the correct position to turn in a lock.
Concentration of Reactants
Have you ever tried to start a conversation in a quiet library versus a crowded concert? The latter certainly has more potential for interaction simply because there are more people. This analogy helps explain concentration of reactants.

In chemical kinetics, the concentration of reactants is crucial because it's directly proportional to the likelihood of reactant particles meeting and reacting. To simplify: the higher the concentration, the more reactant particles there are in a given volume. This leads to an increase in the number of collisions, opening more opportunities for those all-important reactive collisions that produce products. It's a numbers game; dense concentrations make it easier for the right particles to crash into each other with the necessary energy and orientation.
Chemical Kinetics
When you watch a race, you're not just interested in who wins, but also how quickly they get to the finish line. This is similar to the role of chemical kinetics in chemistry, which studies the speed or rate of chemical reactions and the factors that affect this pace.

It's not just about whether reactants will form products, but how swiftly they'll do it. Chemical kinetics involves measurements of reaction rates, examination of how different conditions influence those rates, and the development of models that can predict the behavior of chemical systems. This field of study is broad, dealing with aspects such as reaction mechanisms (the step-by-step sequence of elementary reactions) and energy profiles of reactions, helping us understand the 'hows' and 'whys' of reaction rates.
Collision Frequency
A packed dance floor increases the chance of dancers stepping on each other's toes. This is akin to collision frequency in chemical reactions, which is the number of times reactant particles collide per unit time.

Naturally, with a higher concentration of reactants, the collision frequency goes up. You can also think of temperature as the dance floor's energy level; the higher the temperature, the more energetic the dancing, and the more frequent the toe-stepping incidents. Each collision has the potential to be 'successful'—meaning it results in a reaction—but only if it meets the energy and orientation requirements. Otherwise, it's just another 'near miss' in the bustling world of molecules.

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Most popular questions from this chapter

\(\begin{aligned} \text { Consider the reaction. } \\ & 2 \operatorname{HBr}(g) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{Br}_{2}(g) \end{aligned}\) \begin{equation} \begin{array}{l}{\text { a. Express the rate of the reaction in terms of the change in concen- }} \\ {\text { tration of each of the reactants and products. }}\end{array} \end{equation} \begin{array}{l}{\text { b. In the first } 25.0 \text { s of this reaction, the concentration of HBr drops }} \\ {\text { from } 0.600 \mathrm{M} \text { to } 0.512 \mathrm{M} \text { . Calculate the average rate of the reac- }} \\\ {\text { tion during this time interval. }} \\ {\text { c. If the volume of the reaction vessel in part b is } 1.50 \mathrm{L}, \text { what }} \\ {\text { amount of } \mathrm{Br}_{2}(\text { in moles) forms during the first } 15.0 \mathrm{s} \text { of the }} \\ {\text { reaction? }}\end{array}

The tabulated data shown here were collected for the first-order reaction: $$ \mathrm{N}_{2} \mathrm{O}(g) \longrightarrow \mathrm{N}_{2}(g)+\mathrm{O}(g) $$ Use an Arrhenius plot to determine the activation barrier and frequency factor for the reaction. $$ \begin{array}{|c|c|} \hline \text { Temperature (K) } & \text { Rate Constant (s }^{-1} \text {) } \\\ \hline 800 & 3.24 \times 10^{-5} \\ \hline 900 & 0.00214 \\ \hline 1000 & 0.0614 \\ \hline 1100 & 0.955 \\ \hline \end{array} $$

Why are reaction rates important (both practically and theoretically)?

A particular reaction, \(A \longrightarrow\) products, has a rate that slows down as the reaction proceeds. The half-life of the reaction is found to depend on the initial concentration of A. Determine whether each statement is like- ly to be true or false for this reaction. \begin{equation} \begin{array}{l}{\text { a. A doubling of the concentration of A doubles the rate of the reaction. }} \\ {\text { b. A plot of } 1 /[\mathrm{A}] \text { versus time is linear. }} \\ {\text { c. The half-life of the reaction gets longer as the initial concentration of }} \\ {\text { A increases. }} \\\ {\text { d. A plot of the concentration of A versus time has a constant slope. }}\end{array} \end{equation}

Many heterogencous catalysts are deposited on high surface-area sup- ports. Why?

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