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Explain the difference between homogeneous catalysis and heteroge- neous catalysis.

Short Answer

Expert verified
Homogeneous catalysis involves a catalyst in the same phase as the reactants, leading to easier mixing and control, while heterogeneous catalysis involves a catalyst in a different phase, often solid, with reactions occurring at the interface between phases.

Step by step solution

01

Understanding Catalysis

Firstly, recognize that catalysis is the process by which the rate of a chemical reaction is increased by adding a substance known as a catalyst. These catalysts are not consumed in the reaction and can act in different phases or states of matter relative to the reactants.
02

Identify Homogeneous Catalysis

Homogeneous catalysis occurs when the catalyst operates in the same phase (solid, liquid, or gas) as the reactants. Here, the catalyst is uniformly distributed throughout the reaction mixture, often leading to easier interaction with the reactants and sometimes more manageable control over the reaction.
03

Identify Heterogeneous Catalysis

In contrast, heterogeneous catalysis happens when the catalyst is in a different phase than the reactants. Typically, this means the catalyst is a solid while the reactants are in a liquid or gas phase. The reaction occurs at the interface between the phases, often at the surface of the solid catalyst.
04

Cite Examples for Clarity

Provide examples to illustrate the differences. A common example of homogeneous catalysis is the use of solvated protons (H+) as a catalyst in the esterification process in a liquid phase. An example of heterogeneous catalysis is the use of solid platinum in the catalytic converters of cars, where gas-phase pollutants react at the platinum surface.
05

Explain Differences in Mechanism

Highlight that homogeneous catalysis typically involves simpler mechanisms because of the ease of mixing between catalyst and reactants. Heterogeneous catalysis may involve more complex mechanisms such as adsorption, diffusion, reaction, and desorption at the catalyst's surface.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Homogeneous Catalysis
In the realm of chemistry, homogeneous catalysis is a process where the catalyst is present in the same phase as the reactants. This concert of similarity facilitates a seamless interaction that can often result in a more uniform reaction rate. For example, when sulfuric acid catalyzes the esterification reaction, it mingles freely with the starting materials since all are in the liquid phase. This can lead to a more consistent output and can sometimes be controlled more easily compared to its heterogeneous counterpart.

As catalysts are not consumed in the reaction, they can be recycled and used multiple times. This aspect of homogeneous catalysis underscores its appeal in industries that prioritize efficiency and sustainability. Moreover, because reactions are typically conducted in a single phase, separation and purification processes in homogeneous catalysis can often be straightforward.
Heterogeneous Catalysis
On the flip side, heterogeneous catalysis involves a catalyst in a different phase than the reactants, creating a scenic interface for the chemical reaction to take place. This is akin to a dance floor where only certain dancers (reactants) can reach the platform (solid catalyst) to perform. Commonly, solid catalysts like metals or metal oxides provide surfaces for gas or liquid reactants to adhere. This setting is often seen in automotive catalytic converters, where solid platinum expedites the transformation of noxious gases into less harmful substances.

Heterogeneous catalysis is marked by the complexity of the prolonged journey reactants must take, including adsorption to the catalyst's surface, possibly diffusing onto the surface, reacting, and eventually desorbing. These steps contribute to the complexity of the process and are pivotal to understanding the inner workings of such systems.
Chemical Reaction Rate
The chemical reaction rate is a measure of how quickly a reaction proceeds; it's the speedometer of chemical processes. This rate can be influenced by various factors—including temperature, concentration of reactants, and, notably, the presence of a catalyst. A catalyst can speed up a reaction by lowering the activation energy required for the reaction to occur, in a sense providing a shortcut for the reactants to form the desired products. This acceleration does not change the thermodynamics of the reaction; it merely hastens the rate at which equilibrium is reached.

For students grappling with reaction kinetics, visualizing a catalyst as a type of 'chemical helper' that doesn't sacrifice itself in the reaction can be an easy way to conceptualize this role in altering reaction rates.
Catalyst Mechanisms
The inner game of catalysis lies in the catalyst mechanisms, which is an umbrella term for the series of steps through which catalysts facilitate reactions. In homogeneous catalysis, the mechanism might be as straightforward as forming an intermediate complex with the reactant that has a lower activation energy pathway. In contrast, the mechanisms in heterogeneous catalysis are more involved, including adsorption of reactants onto the surface, their activation, the actual chemical reaction, and the subsequent desorption of the product.

This multi-step panorama is more intricate because the surface chemistry of the catalyst plays a crucial role, often requiring finer tuning and a deeper understanding of the surface properties. Grasping these mechanisms is a pivotal step for students aiming to unlock the nuances of catalytic behavior and their practical implications.
Adsorption and Desorption
At the heart of many catalytic reactions, especially heterogeneous ones, lie the processes of adsorption and desorption. Imagine a sponge soaking up water: adsorption is somewhat analogous, where molecules from a gas or liquid adhere to the solid surface of the catalyst. This is typically the first step in heterogeneous catalysis, creating a tapestry of reactants poised for transformation.

After the reaction has taken place on the surface, the newly formed products must leave, or desorb, from the catalyst surface, freeing up space for new reactant molecules to undergo the reaction. This cycle is crucial to a catalyst’s efficiency and longevity, and understanding the dynamics of adsorption and desorption can be a key factor in optimizing catalytic processes. The balance between these two intertwined phenomena affects the overall rate and success of the catalytic reaction.

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Most popular questions from this chapter

The half-life for the radioactive decay of \(\mathrm{C}-14\) is 5730 years and is inde- pendent of the initial concentration. How long does it take for 25\(\%\) of the C-14 atoms in a sample of \(C-14\) to decay? If a sample of C-14 initially contains 1.5 mmol of C-14, how many millimoles are left after 2255 years?

Explain the difference between the average rate of reaction and the in- stantancous rate of reaction.

For the reaction \(2 \mathrm{A}(g)+\mathrm{B}(g) \longrightarrow 3 \mathrm{C}(g),\) \begin{equation} \begin{array}{l}{\text { a. determine the expression for the rate of the reaction in terms of }} \\ {\text { the change in concentration of each of the reactants and products. }} \\ {\text { b. when A is decreasing at a rate of } 0.100 \mathrm{M} / \mathrm{s} \text { , how fast is } \mathrm{B} \text { decreas- }} \\ {\text { ing? How fast is Cincreasing? }}\end{array} \end{equation}

Why are reaction rates important (both practically and theoretically)?

\(\begin{aligned} \text { Consider the reaction. } \\ & 2 \operatorname{HBr}(g) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{Br}_{2}(g) \end{aligned}\) \begin{equation} \begin{array}{l}{\text { a. Express the rate of the reaction in terms of the change in concen- }} \\ {\text { tration of each of the reactants and products. }}\end{array} \end{equation} \begin{array}{l}{\text { b. In the first } 25.0 \text { s of this reaction, the concentration of HBr drops }} \\ {\text { from } 0.600 \mathrm{M} \text { to } 0.512 \mathrm{M} \text { . Calculate the average rate of the reac- }} \\\ {\text { tion during this time interval. }} \\ {\text { c. If the volume of the reaction vessel in part b is } 1.50 \mathrm{L}, \text { what }} \\ {\text { amount of } \mathrm{Br}_{2}(\text { in moles) forms during the first } 15.0 \mathrm{s} \text { of the }} \\ {\text { reaction? }}\end{array}

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