Chapter 12: Problem 43
Determine if each pair of compounds forms a homogeneous solution when combined. For those that form homogeneous solutions, indicate the type of forces that are involved. a. \(\mathrm{CCl}_{4}\) and \(\mathrm{H}_{2} \mathrm{O}\) b. \(\mathrm{KCl}\) and \(\mathrm{H}_{2} \mathrm{O}\) c. \(\mathrm{Br}_{2}\) and \(\mathrm{CCl}_{4}\) d. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) and \(\mathrm{H}_{2} \mathrm{O}\)
Short Answer
Step by step solution
- Examine Solubility of CCl4 and H2O
- Examine Solubility of KCl and H2O
- Determine Forces between KCl and H2O
- Examine Solubility of Br2 and CCl4
- Determine Forces between Br2 and CCl4
- Examine Solubility of CH3CH2OH and H2O
- Determine Forces between CH3CH2OH and H2O
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Homogeneous Solutions
In the context of the given exercise, the solubility of various substances in water was examined to determine if they form homogeneous solutions. For instance, while potassium chloride (KCl) dissolves in water to form a homogeneous solution, carbon tetrachloride (CCl4) does not mix well with water due to the difference in polarity between the two substances.
Polar and Nonpolar Substances
Nonpolar substances, on the other hand, do not have a significant difference in electronegativity between bonded atoms, leading to an even distribution of electrical charge. Carbon tetrachloride (CCl4), used in the exercise, is nonpolar because of its symmetrical tetrahedral shape and uniform distribution of charge. These characteristics determine how substances interact with each other and ultimately, whether they form homogeneous solutions.
Ion-Dipole Forces
During solvation, water molecules surround each ion from KCl. The positive part of the water's dipole aligns with the chloride anion and the negative part with the potassium cation, showcasing the ion-dipole attraction.
London Dispersion Forces
For example, the molecules of bromine (Br2) and carbon tetrachloride (CCl4) from the exercise display London dispersion forces. The nonpolar nature of both substances allows them to mix, forming a homogeneous solution due to these transient induced dipoles.
Hydrogen Bonding
In the exercise, the hydroxyl (−OH) group in ethanol can participate in hydrogen bonding with the water molecules, resulting in a stable homogeneous mixture. This strong interaction not only affects solubility but also influences boiling points and the physical properties of substances that can create these bonds.
Miscibility of Liquids
In the given exercise, the miscibility of ethanol in water leads to a uniform solution due to the similar polar nature of both and the strong hydrogen bonds that form between them. Understanding the concept of miscibility is essential in many applications, from pharmacology to chemical engineering.