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Arrange the following compounds in order of increasing boiling point. (a) \(\mathrm{Ar}\) (b) \(\mathrm{He}\) (c) \(\mathrm{Ne}\) (d) \(\mathrm{Xe}\)

Short Answer

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Question: Arrange the following noble gases in order of increasing boiling point: Argon (Ar), Helium (He), Neon (Ne), and Xenon (Xe). Answer: Helium (He) < Neon (Ne) < Argon (Ar) < Xenon (Xe)

Step by step solution

01

Identify which forces are responsible for holding the noble gases together as liquids

London dispersion forces play a significant role in determining the boiling points of noble gases since these gases have no other bonding.
02

Compare the molar mass and atomic size of each noble gas

The molar mass and atomic size and of each noble gas are as follows: (a) Argon (Ar): Molar Mass = 39.95 g/mol, Atomic size = 71 pm (b) Helium (He): Molar Mass = 4.00 g/mol, Atomic size = 31 pm (c) Neon (Ne): Molar Mass = 20.18 g/mol, Atomic size = 38 pm (d) Xenon (Xe): Molar Mass = 131.29 g/mol, Atomic size = 108 pm
03

Relate the strength of the London dispersion forces to molar mass and atomic size

The strength of the London dispersion forces increases with increasing molar mass and size, bigger atoms are more polarizable and can create temporary dipoles easier; therefore, noble gases with larger molar mass and atomic size will generally have higher boiling points.
04

Arrange the noble gases in order of increasing boiling point

Based on the strength of the London dispersion forces, the boiling points of the noble gases will increase in the following order: Helium (He) < Neon (Ne) < Argon (Ar) < Xenon (Xe)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

London Dispersion Forces
The notion of London dispersion forces can seem abstract at first, but it’s a fundamental concept when examining the boiling points of inert gases, like noble gases. Even though these gases do not form molecules and are monatomic, they can still exert forces on each other. This is where London dispersion forces come into play. Imagine if you had a group of people standing still but occasionally bumping into each other; these 'bumps' are somewhat analogous to London dispersion forces. They are weak intermolecular forces that arise due to the temporary shifts in electron density within an atom, causing a temporary dipole. These forces are present in all atoms and nonpolar molecules and become stronger as the atoms increase in size and molar mass. Why? Larger atoms have more electrons, leading to greater chances of uneven electron distribution and thus stronger temporary dipoles.

When atoms come close together, if one atom has a temporary dipole, it can induce a dipole in its neighbor, creating an attraction. Although very feeble compared to other types of intermolecular forces, London dispersion forces are significant in noble gases because they are the only type of intermolecular force between these solitary atoms.
Molar Mass
What could the weight of a mole of atoms possibly have to do with how they behave in terms of their boiling points? This is where the concept of molar mass becomes vital. Molar mass, commonly expressed in grams per mole (g/mol), measures the mass of 6.022 x 1023 (Avogadro's number) atoms of an element. It's an average, accounting for the mix of isotopes found in nature. The heavier the molar mass of a noble gas, the more mass each atom has. More mass means more electrons, which in turn means a greater ability to form those temporary dipoles we talked about, enhancing the strength of London dispersion forces. Thus, as the molar mass increases, boiling points typically increase as well because more energy (heat) is required to overcome these stronger forces to transition from liquid to gas.
Atomic Size
Think of atomic size as the 'reach' an atom has. The larger the atom, the more area it covers, and the easier it is for its electrons to be distributed unevenly, forming temporary dipoles. This is known as polarizability. Bigger atoms, like a large balloon, are more 'deformable' compared to smaller ones. In noble gases, atomic size increases with the number of electron shells. As the atoms get larger, their electrons are further from the nucleus and are shielded by inner-shell electrons, making them more influenced by nearby atoms. Therefore, larger atoms are more polarizable and can more easily induce dipoles in each other, leading to stronger intermolecular attractions β€” and therefore higher boiling points.
Intermolecular Forces
Intermolecular forces are the glue that holds substances together, but not all 'glue' is made equal. Among intermolecular forces, you have dipole-dipole interactions in polar molecules, hydrogen bonds in molecules like water, and London dispersion forces, which all atoms and molecules exhibit to some extent. Due to their full valence shells, noble gases don't form permanent dipoles and hence only exhibit London dispersion forces. It’s fascinating to observe how these only forces at work can lead to distinct boiling points, as seen in the noble gases. The boiling point indicates the temperature at which a substance transitions from liquid to gas. This transition requires enough energy to overcome the intermolecular forces holding the atoms together in the liquid state.

The more potent the intermolecular forces, the more energy is necessary to break free from the liquid phase, leading to a higher boiling point. So, if a student wants to predict the boiling point order of noble gases based on intermolecular forces, they would look for indications of the strength of London dispersion forcesβ€” primarily molar mass and atomic size.

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Most popular questions from this chapter

A pure substance A has a liquid vapor pressure of 6 atm at \(550^{\circ} \mathrm{C}\). Its triple point is at \(5 \mathrm{~atm}, 350^{\circ} \mathrm{C}\). The solid phase is denser than the liquid phase. (a) Sketch the phase diagram for compound \(A\). (b) From the phase diagram, estimate the temperature at which the compound boils when 6.3 atm of pressure are applied. (c) What changes occur when, at a constant pressure of 4 atm, the temperature drops from \(400^{\circ} \mathrm{C}\) to \(100^{\circ} \mathrm{C} ?\)

Which of the following compounds would you expect to show dispersion forces? Dipole forces? (a) \(\mathrm{F}_{2}\) (b) \(\mathrm{CO}\) (c) \(\mathrm{CO}_{2}\) (d) \(\mathrm{H}_{2} \mathrm{CO}\)

What are the strongest attractive forces that must be overcome to (a) boil silicon hydride, \(\mathrm{SiH}_{4}\) ? (b) vaporize calcium chloride? (c) dissolve \(\mathrm{Cl}_{2}\) in carbon tetrachloride, \(\mathrm{CCl}_{4}\) ? (d) melt iodine?

Which of the following statements are true? (a) The critical temperature must be reached to change liquid to gas. (b) To melt a solid at constant pressure, the temperature must be above the triple point. (c) \(\mathrm{CHF}_{3}\) can be expected to have a higher boiling point than \(\mathrm{CHCl}_{3}\) because \(\mathrm{CHF}_{3}\) has hydrogen bonding. (d) One metal crystallizes in a body-centered cubic cell and another in a face-centered cubic cell of the same volume. The two atomic radii are related by the factor \(\sqrt{1.5}\)

Four shiny solids are labeled \(A, B, C,\) and \(D\). Given the following information about the solids, deduce the identity of \(\mathrm{A}, \mathrm{B}, \mathrm{C},\) and \(\mathrm{D} .\) (1) The solids are a graphite rod, a silver bar, a lump of "fool's gold" (iron sulfide), and iodine crystals. (2) \(\mathrm{B}, \mathrm{C},\) and \(\mathrm{D}\) are insoluble in water. \(\mathrm{A}\) is slightly soluble. (3) Only C can be hammered into a sheet. (4) \(\mathrm{C}\) and \(\mathrm{D}\) conduct electricity as solids; \(\mathrm{B}\) conducts when melted; A does not conduct as a solid, melted, or dissolved in water.

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