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Describe how you would precipitate (a) zinc carbonate from a solution of zinc nitrate. (b) copper(II) phosphate from a solution of copper(II) chloride. (c) barium sulfate from a solution of barium hydroxide.

Short Answer

Expert verified
Answer: Zinc carbonate can be precipitated from a solution of zinc nitrate by mixing it with sodium carbonate. The chemical reaction can be represented as: Zn(NO3)2 + Na2CO3 → 2NaNO3 + ZnCO3↓ 2. How can copper(II) phosphate be precipitated from a solution of copper(II) chloride? Answer: Copper(II) phosphate can be precipitated from a solution of copper(II) chloride by mixing it with sodium phosphate. The chemical reaction can be represented as: 3CuCl2 + 2Na3PO4 → 6NaCl + Cu3(PO4)2↓ 3. How can barium sulfate be precipitated from a solution of barium hydroxide? Answer: Barium sulfate can be precipitated from a solution of barium hydroxide by mixing it with sodium sulfate. The chemical reaction can be represented as: Ba(OH)2 + Na2SO4 → 2NaOH + BaSO4↓

Step by step solution

01

Precipitating Zinc Carbonate

To precipitate zinc carbonate (ZnCO3) from a solution of zinc nitrate (Zn(NO3)2), we need a source of carbonate ions (CO3^sup2-sdwn). Sodium carbonate (Na2CO3) is a suitable reactant for this purpose since it is soluble and dissociates into CO3^sup2-sdwn and sodium ions (Na^sup+sdwn) upon dissolving in water. Mixing these two solutions will result in the following chemical reaction: Zn(NO3)2 + Na2CO3 → 2NaNO3 + ZnCO3↓ Zinc carbonate (ZnCO3) is insoluble and will precipitate as a solid, while sodium nitrate (NaNO3) remains dissolved in the solution.
02

Precipitating Copper(II) Phosphate

To precipitate copper(II) phosphate (Cu3(PO4)2) from a solution of copper(II) chloride (CuCl2), we need a source of phosphate ions (PO4^sup3-sdwn). Sodium phosphate (Na3PO4) is a suitable reactant for this purpose since it is soluble and dissociates into PO4^sup3-sdwn and sodium ions (Na^sup+sdwn) upon dissolving in water. Mixing these two solutions will result in the following chemical reaction: 3CuCl2 + 2Na3PO4 → 6NaCl + Cu3(PO4)2↓ Copper(II) phosphate (Cu3(PO4)2) is insoluble and will precipitate as a solid, while sodium chloride (NaCl) remains dissolved in the solution.
03

Precipitating Barium Sulfate

To precipitate barium sulfate (BaSO4) from a solution of barium hydroxide (Ba(OH)2), we need a source of sulfate ions (SO4^sup2-sdwn). Sodium sulfate (Na2SO4) is a suitable reactant for this purpose since it is soluble and dissociates into SO4^sup2-sdwn and sodium ions (Na^sup+sdwn) upon dissolving in water. Mixing these two solutions will result in the following chemical reaction: Ba(OH)2 + Na2SO4 → 2NaOH + BaSO4↓ Barium sulfate (BaSO4) is insoluble and will precipitate as a solid, while sodium hydroxide (NaOH) remains dissolved in the solution.

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Most popular questions from this chapter

Ten \(\mathrm{mL}\) of concentrated \(\mathrm{H}_{3} \mathrm{PO}_{4} \quad(91.7 \%\) by mass, \(d=1.69 \mathrm{~g} / \mathrm{mL})\) was accidentally poured into a beaker containing \(20.0 \mathrm{~g}\) of \(\mathrm{NaOH} .\) Not all the \(\mathrm{NaOH}\) was consumed. How many grams of \(\mathrm{NaOH}\) were left unreacted? The equation for the reaction is $$ \mathrm{H}_{3} \mathrm{PO}_{4}(a q)+3 \mathrm{OH}^{-}(a q) \longrightarrow 3 \mathrm{H}_{2} \mathrm{O}+\mathrm{PO}_{4}^{3-}(a q) $$

A student is given \(0.930 \mathrm{~g}\) of an unknown acid, which can be either oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4},\) or citric acid, \(\mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}\). To determine which acid she has, she titrates the unknown acid with \(0.615 \mathrm{M} \mathrm{NaOH}\). The equivalence point is reached when \(33.6 \mathrm{~mL}\) are added. What is the unknown acid?

Consider several \(25.00-\mathrm{mL}\) solutions of perchloric acid. What is the molarity of the acid solution neutralized by (a) \(17.25 \mathrm{~mL}\) of \(0.3471 \mathrm{M}\) ethylamine \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}\right)\). (b) \(14.17 \mathrm{~g}\) of strontium hydroxide. (c) \(41.73 \mathrm{~mL}\) of an \(18 \%\) (by mass) solution of ammonia \((d=0.9295 \mathrm{~g} / \mathrm{mL})\)

Write a balanced net ionic equation for each of the following reactions in water. (a) acetic acid, \(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2},\) with strontium hydroxide (b) diethylamine, \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right) \mathrm{NH}\) with sulfuric acid (c) aqueous hydrofluoric acid with sodium hydroxide

Consider the following generic equation: $$For which of the following pairs would this be the correct prototype equation for the acid-base reaction in solution? If it is not correct, write the proper equation for the acid-base reaction between the pair. (a) nitric acid and calcium hydroxide (b) hydrochloric acid and \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) (c) hydrobromic acid and aqueous ammonia (d) perchloric acid and barium hydroxide (e) sodium hydroxide and nitrous acid\mathrm{H}^{+}(a q)+\mathrm{B}^{-}(a q) \longrightarrow \mathrm{HB}(a q)$$

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