Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

21\. For an acid-base reaction, what is the reacting species (the ion or molecule that appears in the chemical equation) in the following bases? (a) barium hydroxide (b) trimethylamine \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}\) (c) aniline, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) (d) sodium hydroxide

Short Answer

Expert verified
Based on the given solutions, identify the reacting species for each of the following bases in an acid-base reaction: (a) Barium hydroxide: The reacting species is the hydroxide ion, \(\mathrm{OH^-}\). (b) Trimethylamine: The reacting species is the nitrogen atom, \(\mathrm{N}\), which donates a pair of electrons to form a bond with the proton (\(\mathrm{H^+}\)). (c) Aniline: The reacting species is the nitrogen atom, \(\mathrm{N}\), in the amine group (\(\mathrm{-NH}_{2}\)), which donates a pair of electrons to form a bond with the proton (\(\mathrm{H^+}\)). (d) Sodium hydroxide: The reacting species is the hydroxide ion, \(\mathrm{OH^-}\).

Step by step solution

01

(a) Barium Hydroxide Reacting Species

Barium hydroxide has the chemical formula \(\mathrm{Ba(OH)_2}\). In an acid-base reaction, it will dissociate into its ions in water, which are \(\mathrm{Ba^{2+}}\) and \(\mathrm{OH^-}\). The reacting species, responsible for the base behavior, is the hydroxide ion, \(\mathrm{OH^-}\).
02

(b) Trimethylamine Reacting Species

Trimethylamine has the chemical formula \(\left(\mathrm{CH}_{3}\right)_{3}\mathrm{N}\). Upon reaction with an acid, it can accept a proton (\(\mathrm{H^+}\)) and form the ion \(\left(\mathrm{CH}_{3}\right)_{3}\mathrm{NH^+}\). So, the reacting species for trimethylamine is the nitrogen atom, \(\mathrm{N}\), which donates a pair of electrons to form a bond with the proton (\(\mathrm{H^+}\)).
03

(c) Aniline Reacting Species

Aniline has the chemical formula \(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{NH}_{2}\). In an acid-base reaction, the nitrogen in the amine group (\(\mathrm{-NH}_{2}\)) can accept a proton (\(\mathrm{H^+}\)) and form the ion \(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{NH}_{3}^+\). The reacting species for aniline is the nitrogen atom, \(\mathrm{N}\), in the amine group (\(\mathrm{-NH}_{2}\)), which donates a pair of electrons to form a bond with the proton (\(\mathrm{H^+}\)).
04

(d) Sodium Hydroxide Reacting Species

Sodium hydroxide has the chemical formula \(\mathrm{NaOH}\). In an acid-base reaction, it will dissociate into its ions in water, which are \(\mathrm{Na^+}\) and \(\mathrm{OH^-}\). The reacting species, responsible for the base behavior, is the hydroxide ion, \(\mathrm{OH^-}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reacting Species in Bases
Understanding the reacting species in bases is crucial for grasping how these substances behave in acid-base reactions. For instance, barium hydroxide (\( \text{Ba(OH)}_2 \) ) and sodium hydroxide (\( \text{NaOH} \) ) are both strong bases that dissociate completely in water. The dissociation releases hydroxide ions (\( \text{OH}^- \) ), which are the actual reacting species in any subsequent acid-base reaction.

Conversely, organic compounds such as trimethylamine (\( (\text{CH}_3)_3\text{N} \) ) and aniline (\( \text{C}_6\text{H}_5\text{NH}_2 \) ) act as bases through a different mechanism. Instead of releasing hydroxide ions, these compounds have a nitrogen atom that possesses a lone pair of electrons. It is this lone pair that makes them capable of accepting a proton (\( \text{H}^+ \) ), thus serving as the reacting species in acid-base reactions. It's crucial to identify these species because they determine how the molecule will interact with acids and participate in chemical reactions.
Dissociation in Water
Dissociation in water is a fundamental concept in understanding acid-base chemistry. When certain substances dissolve in water, they separate into their constituent ions. This phenomenon is particularly significant for bases, as the extent of their dissociation affects their strength and reactivity.

In strong bases such as barium hydroxide and sodium hydroxide, this process results in free hydroxide ions (\( \text{OH}^- \) ) that readily react with hydrogen ions (\( \text{H}^+ \) ). The complete dissociation of these bases means a higher concentration of hydroxide ions, which corresponds to a greater ability to neutralize acids. In essence, the degree of dissociation in water not only defines the nature of the reacting species but also provides insight into the strength of the base.
Proton Acceptance
As the cornerstone of base reactivity, proton acceptance can be deemed the inverse process of acid dissociation. In essence, while acids donate protons, bases accept them. In the context of our basic substances, different bases accept protons through different active sites. For example, hydroxide ions (\( \text{OH}^- \) ), readily available in the solutions of barium hydroxide and sodium hydroxide, can accept protons to form water (\( \text{H}_2\text{O} \) ).

On the other hand, organic bases such as trimethylamine and aniline utilize the nitrogen atom, capable of bonding with an additional proton due to its electron pair. This results in the formation of their respective ammonium ions (\( (\text{CH}_3)_3\text{NH}^+ \) and \( \text{C}_6\text{H}_5\text{NH}_3^+ \) ). This acceptance of protons is key to all acid-base reactions and is fundamental in the creation of salts and water when acids and bases react with each other.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A \(50.00-\mathrm{mL}\) sample of \(0.0250 \mathrm{M}\) silver nitrate is mixed with \(0.0400 \mathrm{M}\) chromium(III) chloride. (a) What is the minimum volume of chromium(III) chloride required to completely precipitate silver chloride? (b) How many grams of silver chloride are produced from (a)?

Copper metal can reduce silver ions to metallic silver. The copper is oxidized to copper ions according to the reaction $$ 2 \mathrm{Ag}^{+}(a q)+\mathrm{Cu}(s) \longrightarrow \mathrm{Cu}^{2+}(a q)+2 \mathrm{Ag}(s) $$ A copper strip with a mass of \(2.00 \mathrm{~g}\) is dipped into a solution of \(\mathrm{AgNO}_{3} .\) After some time has elapsed, the copper strip is coated with silver. The strip is removed from the solution, dried, and weighed. The coated strip has a mass of \(4.18 \mathrm{~g}\). What are the masses of copper and silver metals in the strip? (Hint: Remember that the copper metal is being used up as silver metal forms.)

Identify the type of aqueous reaction using the symbols PPT for precipitation, SA/SB for strong acid-strong base, SA/WB for strong acid-weak base, WA/SB for weak acidstrong base, and NR for no reaction. (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}+\mathrm{HCl}\) (b) \(\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{HF}\) (c) \(\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{Na}_{3} \mathrm{PO}_{4}\) (d) \(\mathrm{Ag}_{2} \mathrm{SO}_{4}+\mathrm{BaCl}_{2}\) (e) \(\mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{NaCl}\)

Write net ionic equations for the formation of (a) a precipitate when solutions of magnesium nitrate and potassium hydroxide are mixed. (b) two different precipitates when solutions of silver(I) sulfate and barium chloride are mixed.

Consider four beakers. Beaker A has an aqueous solution of \(\mathrm{NaOH}\) in which the \(\mathrm{OH}^{-}\) ions are represented by blue circles. Beaker \(\mathrm{B}\) has a weak acid; HX is represented by red circles. Beaker \(\mathrm{C}\) has a weak acid; \(\mathrm{H}_{2} \mathrm{X}\) is represented by green circles. Beaker \(\mathrm{D}\) has a weak acid; \(\mathrm{H}_{3} \mathrm{X}\) is represented by yellow circles. \(\mathrm{X}^{-}\) ions are represented by triangles. Match the pictorial representations with the reactions given below. $$ \begin{array}{l} \text { (a) } \mathrm{HX}(a q)+\mathrm{OH}^{-}(a q) \longrightarrow \mathrm{X}^{-}(a q)+\mathrm{H}_{2} \mathrm{O} \\ \text { (b) } \mathrm{H}_{2} \mathrm{X}(a q)+2 \mathrm{OH}^{-}(a q) \longrightarrow \mathrm{X}^{-}(a q)+2 \mathrm{H}_{2} \mathrm{O} \\ \text { (c) } \mathrm{H}_{3} \mathrm{X}(a q)+3 \mathrm{OH}^{-}(a q) \longrightarrow \mathrm{X}^{-}(a q)+3 \mathrm{H}_{2} \mathrm{O} \end{array} $$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free