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19\. For an acid-base reaction, what is the reacting species, that is, the ion or molecule that appears in the chemical equation, in the following acids? (a) perchloric acid (b) hydriodic acid (c) nitrous acid (d) nitric acid (e) lactic acid, \(\mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{3}\)

Short Answer

Expert verified
Answer: In all of the given acids, the reacting species in an acid-base reaction is the hydrogen ion (H⁺).

Step by step solution

01

(a) Perchloric Acid

Perchloric acid has the chemical formula \(\mathrm{HClO}_{4}\). The reacting species in this acid-base reaction is the hydrogen ion (\(\mathrm{H}^{+}\)). The chemical equation of the dissociation is: \(\mathrm{HClO}_{4} \rightarrow \mathrm{H}^{+} + \mathrm{ClO}_{4}^{-}\)
02

(b) Hydriodic Acid

Hydriodic acid has the chemical formula \(\mathrm{HI}\). The reacting species in this acid-base reaction is the hydrogen ion (\(\mathrm{H}^{+}\)) again. The chemical equation of the dissociation is: \(\mathrm{HI} \rightarrow \mathrm{H}^{+} + \mathrm{I}^{-}\)
03

(c) Nitrous Acid

Nitrous acid has the chemical formula \(\mathrm{HNO}_{2}\). The reacting species in this acid-base reaction is the hydrogen ion (\(\mathrm{H}^{+}\)). The chemical equation of the dissociation is: \(\mathrm{HNO}_{2} \rightarrow \mathrm{H}^{+} + \mathrm{NO}_{2}^{-}\)
04

(d) Nitric Acid

Nitric acid has the chemical formula \(\mathrm{HNO}_{3}\). The reacting species in this acid-base reaction is the hydrogen ion (\(\mathrm{H}^{+}\)). The chemical equation of the dissociation is: \(\mathrm{HNO}_{3} \rightarrow \mathrm{H}^{+} + \mathrm{NO}_{3}^{-}\)
05

(e) Lactic Acid

Lactic acid has the chemical formula \(\mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{3}\). The reacting species in this acid-base reaction is the hydrogen ion (\(\mathrm{H}^{+}\)). The chemical equation of the dissociation is: \(\mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{3} \rightarrow \mathrm{H}^{+} + \mathrm{C}_{3} \mathrm{H}_{5} \mathrm{O}_{3}^{-}\)

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Most popular questions from this chapter

A \(50.00-\mathrm{mL}\) sample of \(0.0250 \mathrm{M}\) silver nitrate is mixed with \(0.0400 \mathrm{M}\) chromium(III) chloride. (a) What is the minimum volume of chromium(III) chloride required to completely precipitate silver chloride? (b) How many grams of silver chloride are produced from (a)?

Consider the following generic equation: $$For which of the following pairs would this be the correct prototype equation for the acid-base reaction in solution? If it is not correct, write the proper equation for the acid-base reaction between the pair. (a) nitric acid and calcium hydroxide (b) hydrochloric acid and \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) (c) hydrobromic acid and aqueous ammonia (d) perchloric acid and barium hydroxide (e) sodium hydroxide and nitrous acid\mathrm{H}^{+}(a q)+\mathrm{B}^{-}(a q) \longrightarrow \mathrm{HB}(a q)$$

21\. For an acid-base reaction, what is the reacting species (the ion or molecule that appears in the chemical equation) in the following bases? (a) barium hydroxide (b) trimethylamine \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}\) (c) aniline, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) (d) sodium hydroxide

71\. Calcium in blood or urine can be determined by precipitation as calcium oxalate, \(\mathrm{CaC}_{2} \mathrm{O}_{4} .\) The precipitate is dissolved in strong acid and titrated with potassium permanganate. The equation for reaction is $$ \begin{aligned} 2 \mathrm{MnO}_{4}^{-}(a q)+6 \mathrm{H}^{+}(a q)+& 5 \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q) \longrightarrow \\ & 2 \mathrm{Mn}^{2+}(a q)+10 \mathrm{CO}_{2}(g)+8 \mathrm{H}_{2} \mathrm{O} \end{aligned} $$ A 24 -hour urine sample is collected from an adult patient, reduced to a small volume, and titrated with \(26.2 \mathrm{~mL}\) of \(0.0946 \mathrm{M} \mathrm{KMnO}_{4}\). How many grams of calcium oxalate are in the sample? Normal range for \(\mathrm{Ca}^{2+}\) output for an adult is 100 to \(300 \mathrm{mg}\) per 24 hour. Is the sample within the normal range?

32\. A student tries to determine experimentally the molar mass of aspirin (HAsp). She takes \(1.00 \mathrm{~g}\) of aspirin, dissolves it in water, and neutralizes it with \(17.6 \mathrm{~mL}\) of \(0.315 \mathrm{M} \mathrm{KOH}\). The equation for the reaction is $$ \mathrm{HAsp}(a q)+\mathrm{OH}^{-}(a q) \longrightarrow \mathrm{Asp}^{-}(a q)+\mathrm{H}_{2} \mathrm{O} $$ What is the molar mass of aspirin?

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