Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Chlorophyll, the substance responsible for the green color of leaves, has one magnesium atom per chlorophyll molecule and contains \(2.72 \%\) magnesium by mass. What is the molar mass of chlorophyll?

Short Answer

Expert verified
Answer: The molar mass of chlorophyll is approximately 892.86 g/mol.

Step by step solution

01

Find the mass of magnesium in a given mass of chlorophyll

Since chlorophyll contains \(2.72 \%\) magnesium by mass, we can find the mass of magnesium in a given mass of chlorophyll. Let's consider a \(100 g\) sample of chlorophyll. In that sample, the mass of magnesium would be: Mass of magnesium \( = 2.72 \% \times 100 g = 2.72 g\)
02

Determine the moles of magnesium from its mass

In order to find the molar mass of chlorophyll, we need to relate the amount of magnesium in moles to the amount of chlorine in moles. First, we need to convert the mass of magnesium to moles. The atomic weight of magnesium is approximately \(24.3 g/mol\). We can use this to find the number of moles (n) of magnesium: \(n_{Mg} = \frac{\text{mass of magnesium}}{ \text{atomic weight of magnesium}}\) \(n_{Mg} = \frac{2.72 g}{24.3 g/mol} = 0.112 moles \, of \, Mg\)
03

Determine the moles of chlorophyll in the sample

There is one magnesium atom per chlorophyll molecule, and we have calculated the moles of magnesium in our sample to be \(0.112 moles\). Then, the moles of chlorophyll in the sample is also: \(n_{Chlorophyll} = 0.112 moles \, of \, Chlorophyll\) Now we can relate the mass of chlorophyll to the number of moles we calculated.
04

Calculate the molar mass of chlorophyll

From step 1, we have the mass of chlorophyll, \(100 g\), and from step 3 we know the number of moles, \(0.112 moles\). Now we can calculate the molar mass of chlorophyll using the formula: Molar mass of chlorophyll \( = \frac{\text{mass of chlorophyll}}{ \text{moles of chlorophyll}}\) Molar mass of chlorophyll \( = \frac{100 g}{0.112 moles} \approx 892.86 g/mol\) Hence, the molar mass of chlorophyll is approximately \(892.86 g/mol\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Phosphine gas reacts with oxygen according to the following equation: $$ 4 \mathrm{PH}_{3}(g)+8 \mathrm{O}_{2}(g) \longrightarrow \mathrm{P}_{4} \mathrm{O}_{10}(s)+6 \mathrm{H}_{2} \mathrm{O}(g) $$ Calculate (a) the mass of tetraphosphorus decaoxide produced from \(12.43 \mathrm{~mol}\) of phosphine. (b) the mass of \(\mathrm{PH}_{3}\) required to form \(0.739 \mathrm{~mol}\) of steam. (c) the mass of oxygen gas that yields \(1.000 \mathrm{~g}\) of steam. (d) the mass of oxygen required to react with \(20.50 \mathrm{~g}\) of phosphine.

Dimethylhydrazine, the fuel used in the Apollo lunar descent module, has a molar mass of \(60.10 \mathrm{~g} / \mathrm{mol}\). It is made up of carbon, hydrogen, and nitrogen atoms. The combustion of \(2.859 \mathrm{~g}\) of the fuel in excess oxygen yields \(4.190 \mathrm{~g}\) of carbon dioxide and \(3.428 \mathrm{~g}\) of water. What are the simplest and molecular formulas for dimethylhydrazine?

Determine (a) the mass of 0.429 mol of gold. (b) the number of atoms in \(0.715 \mathrm{~g}\) of gold. (c) the number of moles of electrons in \(0.336 \mathrm{~g}\) of gold.

Convert to moles. (a) \(128.3 \mathrm{~g}\) of sucralose, \(\mathrm{C}_{12} \mathrm{H}_{19} \mathrm{O}_{8} \mathrm{Cl}_{3},\) the active ingredient of the artificial sweetener Splenda \(^{\mathrm{TM}}\) (b) \(0.3066 \mathrm{~g}\) of uric acid, \(\mathrm{C}_{5} \mathrm{H}_{4} \mathrm{~N}_{4} \mathrm{O}_{3},\) the compound that can cause gout and arthritis (c) \(2.664 \mathrm{~g}\) of cadmium(II) telluride used to coat solar panels

Twenty-five \(\mathrm{mL}\) of a \(0.388 \mathrm{M}\) solution of \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) is mixed with \(35.3 \mathrm{~mL}\) of \(0.229 \mathrm{M} \mathrm{Na}_{2} \mathrm{SO}_{4}\). What is the molarity of the resulting solution? Assume that the volumes are additive.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free