Question

Allicin is responsible for the distinctive taste and odor of garlic. Its simple formula is \(\mathrm{C}_{6} \mathrm{H}_{10} \mathrm{O}_{2} \mathrm{~S} .\) How many grams of sulfur can be obtained from \(25.0 \mathrm{~g}\) of allicin?

Short answer

Answer: 5.476 grams of sulfur can be obtained from 25.0 grams of Allicin.

Step-by-step solution

Calculate the molar mass of Allicin and Sulfur

To find the molar mass of Allicin, we need to add the molar masses of all the elements present in its molecular formula: - Carbon (C): 6 atoms × 12.01 g/mol = 72.06 g/mol - Hydrogen (H): 10 atoms × 1.01 g/mol = 10.10 g/mol - Oxygen (O): 2 atoms × 16.00 g/mol = 32.00 g/mol - Sulfur (S): 1 atom × 32.07 g/mol = 32.07 g/mol Now, add all these values to get the molar mass of Allicin: Molar mass of Allicin = 72.06 + 10.10 + 32.00 + 32.07 = 146.23 g/mol The molar mass of Sulfur is 32.07 g/mol.

Calculate the moles of Allicin

Next, we need to find the moles of Allicin present in 25.0 grams. For this, we will use the formula: moles = (grams of substance) / (molar mass of substance) moles of Allicin = (25.0 g) / (146.23 g/mol) = 0.1709 mol

Calculate the moles of Sulfur in Allicin

Now, we can easily find the moles of Sulfur present in Allicin. Since there is one Sulfur atom in one Allicin molecule, the moles of Sulfur will be the same as the moles of Allicin: moles of Sulfur = 0.1709 mol

Calculate the grams of Sulfur in Allicin

Finally, we will convert the moles of Sulfur to grams using its molar mass: grams of Sulfur = (moles of Sulfur) × (molar mass of Sulfur) grams of Sulfur = (0.1709 mol) × (32.07 g/mol) = 5.476 g Therefore, 5.476 grams of Sulfur can be obtained from 25.0 grams of Allicin.