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Write a chemical equation, using molecular formulas, for the reaction of maltose with water to form glucose.

Short Answer

Expert verified
Answer: C12H22O11 + H2O -> 2 C6H12O6

Step by step solution

01

Reactants and Products

In this reaction, maltose (C12H22O11) is reacting with water (H2O) to form glucose (C6H12O6). The chemical formula of maltose is C12H22O11, and water is H2O. These are the reactants. The product is glucose, and its chemical formula is C6H12O6. Step 2: Write the balanced chemical equation
02

Balanced Chemical Equation

Since the reaction involves one water molecule reacting with one maltose molecule to form two glucose molecules, the balanced chemical equation for this reaction is: C12H22O11 + H2O -> 2 C6H12O6

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Most popular questions from this chapter

Cellulose consists of about \(10,000 \mathrm{C}_{6} \mathrm{H}_{10} \mathrm{O}_{5}\) units linked together. (a) What are the mass percents of \(\mathrm{C}, \mathrm{H},\) and \(\mathrm{O}\) in cellulose? (b) What is the molar mass of cellulose?

Plants synthesize carbohydrates from \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) by the process of photosynthesis. For example, $$ 6 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(a q)+6 \mathrm{O}_{2}(g) $$ \(\Delta G^{\circ}=2.87 \times 10^{3} \mathrm{~kJ}\) at \(\mathrm{pH} 7.0\) and \(25^{\circ} \mathrm{C}\). What is \(K\) for the reaction at \(25^{\circ} \mathrm{C}\) ?

Consider a polymer made from tetrachloroethylene. (a) Draw a portion of the polymer chain. (b) What is the molar mass of the polymer if it contains \(3.2 \times 10^{3}\) tetrachloroethylene molecules? (c) What are the mass percents of \(\mathrm{C}\) and \(\mathrm{Cl}\) in the polymer?

Give the structural formula of two different dipeptides formed between arginine and serine.

Glycolysis is the process by which glucose is metabolized to lactic acid according to the equation $$ \begin{array}{c} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(a q) \longrightarrow 2 \mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{3}(a q) \\ \Delta G^{\circ}=-198 \mathrm{~kJ} \text { at } \mathrm{pH} 7.0 \text { and } 25^{\circ} \mathrm{C} \end{array} $$ Glycolysis is the source of energy in human red blood cells. In these cells, the concentration of glucose is \(5.0 \times 10^{-3} \mathrm{M}\), while that of lactic acid is \(2.9 \times 10^{-3} \mathrm{M} .\) Calculate \(\Delta G\) for glycolysis in human blood cells under these conditions. Use the equation \(\Delta G=\Delta G^{\circ}+\mathrm{RT} \ln Q,\) where \(Q\) is the concentration quotient, analogous to \(K\).

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