Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write the formulas of the following compounds. (a) ammonia (b) laughing gas (c) hydrogen peroxide (d) sulfur trioxide

Short Answer

Expert verified
Question: Write the chemical formulas for the following compounds: a) Ammonia b) Laughing gas c) Hydrogen peroxide d) Sulfur trioxide. Answer: a) NH3 b) N2O c) H2O2 d) SO3

Step by step solution

01

(Ammonia)

Ammonia is a compound of nitrogen and hydrogen. The chemical symbol for nitrogen is N and for hydrogen is H. In ammonia, one nitrogen atom combines with three hydrogen atoms, resulting in the formula NH\(_3\).
02

(Laughing Gas)

Laughing gas is known as nitrous oxide. It is a compound of nitrogen and oxygen. The chemical symbol for nitrogen is N and for oxygen is O. In laughing gas, there are two nitrogen atoms and one oxygen atom. Therefore the chemical formula for laughing gas is N\(_2\)O.
03

(Hydrogen Peroxide)

Hydrogen peroxide is a compound of hydrogen and oxygen. The chemical symbol for hydrogen is H, and for oxygen is O. In hydrogen peroxide, there are two hydrogen atoms and two oxygen atoms. Hence, the chemical formula for hydrogen peroxide is H\(_2\)O\(_2\).
04

(Sulfur Trioxide)

Sulfur trioxide is a compound of sulfur and oxygen. The chemical symbol for sulfur is S, and for oxygen is O. In sulfur trioxide, there is one sulfur atom and three oxygen atoms. This leads to the chemical formula for sulfur trioxide: SO\(_3\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write a balanced net ionic equation for (a) the electrolytic decomposition of hydrogen fluoride. (b) the oxidation of iodide ion to iodine by hydrogen peroxide in acidic solution. Hydrogen peroxide is reduced to water.

The amount of sodium hypochlorite in a bleach solution can be determined by using a given volume of bleach to oxidize excess iodide ion to iodine; \(\mathrm{ClO}^{-}\) is reduced to \(\mathrm{Cl}^{-}\). The amount of iodine produced by the redox reaction is determined by titration with sodium thiosulfate, \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} ; \mathrm{I}_{2}\) is reduced to \(1^{-}\). The sodium thiosulfate is oxidized to sodium tetrathionate, \(\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6} .\) In this analysis, potassium iodide was added in excess to \(5.00 \mathrm{~mL}\) of bleach \(\left(d=1.00 \mathrm{~g} / \mathrm{cm}^{3}\right)\). If \(25.00 \mathrm{~mL}\) of \(0.0700 \mathrm{M} \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) was required to reduce all the iodine produced by the bleach back to iodide, what is the mass percent of \(\mathrm{NaClO}\) in the bleach?

In the electrolysis of a KI solution, using \(5.00 \mathrm{~V}\), how much electrical energy in kilojoules is consumed when one mole of \(\mathrm{I}_{2}\) is formed?

Give the Lewis structure of (a) the strongest oxoacid of bromine. (b) a hydrogen compound of nitrogen in which there is \(a n-N-N-\) bond. (c) an acid added to cola drinks.

A \(1.500-\mathrm{g}\) sample containing sodium nitrate was heated to form \(\mathrm{NaNO}_{2}\) and \(\mathrm{O}_{2}\). The oxygen evolved was collected over water at \(23^{\circ} \mathrm{C}\) and \(752 \mathrm{~mm} \mathrm{Hg} ;\) its volume was \(125.0 \mathrm{~mL} .\) Calculate the percentage of \(\mathrm{NaNO}_{3}\) in the sample. The vapor pressure of water at \(23^{\circ} \mathrm{C}\) is \(21.07 \mathrm{~mm} \mathrm{Hg}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free