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Which of the following processes are spontaneous? (a) a ball rolling down a hill (b) a drop of ink dispersing in water (c) melting wax at \(10^{\circ} \mathrm{C}\)

Short Answer

Expert verified
A ball rolling down a hill is a spontaneous process, as it occurs naturally due to the force of gravity pulling the ball towards the center of the Earth. A drop of ink dispersing in water is also a spontaneous process, as it is driven by the random motion of ink and water molecules, causing the ink to spread out and mix with the water. However, melting wax at \(10^{\circ} \mathrm{C}\) is a non-spontaneous process because wax typically has a melting point above room temperature, and external input, such as heating the wax, is required for the melting process to occur.

Step by step solution

01

(a) A Ball Rolling Down a Hill

A ball rolling down a hill is a spontaneous process. It occurs naturally due to the force of gravity pulling the ball towards the center of the Earth. The potential energy of the ball at the top of the hill is converted into kinetic energy as it rolls downhill, without any external input or assistance needed.
02

(b) A Drop of Ink Dispersing in Water

A drop of ink dispersing in water is a spontaneous process. This process is driven by the random motion of ink and water molecules, causing the ink to spread out and mix with the water. This dispersion of ink molecules happens naturally, without any external input or assistance required.
03

(c) Melting Wax at \(10^{\circ} \mathrm{C}\)

Melting wax at \(10^{\circ} \mathrm{C}\) is a non-spontaneous process. Wax has a melting point above room temperature, typically around \(45^{\circ} \mathrm{C}\) to \(65^{\circ} \mathrm{C}\). This means that at room temperature or below (e.g., \(10^{\circ} \mathrm{C}\)), wax remains in its solid state and does not melt spontaneously. External input, such as heating the wax, is required for the melting process to occur.

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Most popular questions from this chapter

Consider the following reactions at \(25^{\circ} \mathrm{C}\) : $$ \begin{array}{r} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(a q)+6 \mathrm{O}_{2}(g) \longrightarrow 6 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O} \\ \Delta G^{\circ}=-2870 \mathrm{~kJ} \\ \mathrm{ADP}(a q)+\mathrm{HPO}_{4}^{2-}(a q)+2 \mathrm{H}^{+}(a q) \longrightarrow \mathrm{ATP}(a q)+\mathrm{H}_{2} \mathrm{O} \\ \Delta G^{\circ}=31 \mathrm{~kJ} \end{array} $$ Write an equation for a coupled reaction between glucose, \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6},\) and \(\mathrm{ADP}\) in which \(\Delta G^{\circ}=-390 \mathrm{~kJ}\).

Discuss the effect of temperature change on the spontaneity of the following reactions at 1 atm: $$ \text { (a) } \begin{aligned} \mathrm{Al}_{2} \mathrm{O}_{3}(s)+2 \mathrm{Fe}(s) \longrightarrow 2 \mathrm{Al}(s)+\mathrm{Fe}_{2} \mathrm{O}_{3}(s) \\ \Delta H^{\circ}=851.4 \mathrm{~kJ} ; & \Delta S^{\circ}=38.5 \mathrm{~J} / \mathrm{K} \end{aligned} $$ (b) \(\mathrm{N}_{2} \mathrm{H}_{4}(l) \longrightarrow \mathrm{N}_{2}+2 \mathrm{H}_{2}(g)\) $$ \Delta H^{\circ}=-50.6 \mathrm{~kJ} ; \quad \Delta S^{\circ}=0.3315 \mathrm{~kJ} / \mathrm{K} $$ (c) \(\mathrm{SO}_{3}(g) \longrightarrow \mathrm{SO}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g)\) $$ \Delta H^{\circ}=98.9 \mathrm{~kJ} ; \quad \Delta S^{\circ}=0.0939 \mathrm{~kJ} / \mathrm{K} $$

Red phosphorus is formed by heating white phosphorus. Calculate the temperature at which the two forms are at equilibrium, given $$ \begin{array}{l} \text { white } \mathrm{P}: \Delta H_{f}^{\circ}=0.00 \mathrm{~kJ} / \mathrm{mol} ; S^{\circ}=41.09 \mathrm{~J} / \mathrm{mol} \cdot \mathrm{K} \\ \text { red } \mathrm{P}: \Delta H_{\mathrm{f}}^{\circ}=-17.6 \mathrm{~kJ} / \mathrm{mol} ; S^{\circ}=22.80 \mathrm{~J} / \mathrm{mol} \cdot \mathrm{K} \end{array} $$

A student warned his friends not to swim in a river close to an electric plant. He claimed that the ozone produced by the plant turned the river water to hydrogen peroxide, which would bleach hair. The reaction is $$ \mathrm{O}_{3}(g)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{H}_{2} \mathrm{O}_{2}(a q)+\mathrm{O}_{2}(g) $$ Assuming that the river water is at \(25^{\circ} \mathrm{C}\) and all species are at standard concentrations, show by calculation whether his claim is plausible. Take \(\Delta G_{i}^{\circ} \mathrm{O}_{3}(g)\) at \(25^{\circ} \mathrm{C}\) to be \(+163.2 \mathrm{~kJ} / \mathrm{mol}\) $$ \text { and } \Delta G_{f}^{\circ} \mathrm{H}_{2} \mathrm{O}_{2}(a q)=-134 \mathrm{~kJ} / \mathrm{mol} \text { . } $$

Predict the sign of \(\Delta S^{\circ}\) for each of the following reactions. (a) \(\mathrm{H}_{2}(g)+\mathrm{Ni}^{2+}(a q) \longrightarrow 2 \mathrm{H}^{+}(a q)+\mathrm{Ni}(s)\) (b) \(\mathrm{Cu}(s)+2 \mathrm{H}^{+}(a q) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{Cu}^{2+}(a q)\) (c) \(\mathrm{N}_{2} \mathrm{O}_{4}(g) \longrightarrow 2 \mathrm{NO}_{2}(g)\)

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