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Write a balanced net ionic equation for the reaction of each of the following aqueous solutions with \(\mathrm{H}^{+}\) ions. (a) sodium sulfite (b) lithium hydroxide (c) potassium benzoate \(\left(\mathrm{KC}_{7} \mathrm{H}_{5} \mathrm{O}_{2}\right)\)

Short Answer

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Question: Write the balanced net ionic equation for each reaction of the given aqueous solutions with H+ ions: a) Sodium sulfite b) Lithium hydroxide c) Potassium benzoate Answer: a) SO3²⁻ (aq) + 2H+ (aq) → H2O (l) + SO2 (g) b) OH⁻ (aq) + H+ (aq) → H2O (l) c) C7H5O2⁻ (aq) + H+ (aq) → C7H6O2 (aq)

Step by step solution

01

Write the chemical equation

The reaction between sodium sulfite (Na2SO3) and H+ ions (from an acid) can be represented as: Na2SO3 (aq) + 2H+ (aq) → 2Na+ (aq) + H2O (l) + SO2 (g) #Step 2: Identify the spectator ions#
02

Spectator ions identification

Spectator ions are the ions in the equation that do not undergo any change during the reaction. In this case, Na+ ions are the spectator ions as they appear on both sides of the equation without any change. #Step 3: Write the balanced net ionic equation#
03

Balanced net ionic equation

The net ionic equation can be obtained by removing the spectator ions. SO3^{2-} (aq) + 2H+ (aq) → H2O (l) + SO2 (g) #b) Lithium hydroxide reacting with H+ ions# #Step 1: Write the chemical equation#
04

Write the chemical equation

The reaction between lithium hydroxide (LiOH) and H+ ions (from an acid) can be represented as: LiOH (aq) + H+ (aq) → Li+ (aq) + H2O (l) #Step 2: Identify the spectator ions#
05

Spectator ions identification

Spectator ions are the ions in the equation that do not undergo any change during the reaction. In this case, Li+ ions are the spectator ions as they appear on both sides of the equation without any change. #Step 3: Write the balanced net ionic equation#
06

Balanced net ionic equation

The net ionic equation can be obtained by removing the spectator ions. OH^{-} (aq) + H+ (aq) → H2O (l) #c) Potassium benzoate reacting with H+ ions# #Step 1: Write the chemical equation#
07

Write the chemical equation

The reaction between potassium benzoate (KC7H5O2) and H+ ions (from an acid) can be represented as: KC7H5O2 (aq) + H+ (aq) → K+ (aq) + C7H6O2 (aq) #Step 2: Identify the spectator ions#
08

Spectator ions identification

Spectator ions are the ions in the equation that do not undergo any change during the reaction. In this case, K+ ions are the spectator ions as they appear on both sides of the equation without any change. #Step 3: Write the balanced net ionic equation#
09

Balanced net ionic equation

The net ionic equation can be obtained by removing the spectator ions. C7H5O2^- (aq) + H+ (aq) → C7H6O2 (aq)

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Most popular questions from this chapter

A solution consisting of \(25.00 \mathrm{~g} \mathrm{NH}_{4} \mathrm{Cl}\) in \(178 \mathrm{~mL}\) of water is titrated with \(0.114 \mathrm{M} \mathrm{KOH}\). (a) How many milliliters of \(\mathrm{KOH}\) are required to reach the equivalence point? (b) Calculate \(\left[\mathrm{Cl}^{-}\right],\left[\mathrm{K}^{+}\right],\left[\mathrm{NH}_{3}\right],\) and \(\left[\mathrm{OH}^{-}\right]\) at the equivalence point. (Assume that volumes are additive.) (c) What is the \(\mathrm{pH}\) at the equivalence point?

Which of the following would form a buffer if added to \(295 \mathrm{~mL}\) of \(0.380 \mathrm{M} \mathrm{HCl}\) ? (a) \(0.100 \mathrm{~mol}\) of \(\mathrm{NH}_{4} \mathrm{Cl}\) (b) \(0.033 \mathrm{~mol}\) of \(\mathrm{KF}\) (c) \(0.167 \mathrm{~mol}\) of \(\mathrm{Sr}(\mathrm{OH})_{2}\) (d) \(0.279 \mathrm{~mol}\) of \(\mathrm{KNO}_{2}\) (e) \(0.112 \mathrm{~mol}\) of \(\mathrm{KClO}\)

Ammonia gas is bubbled into \(275 \mathrm{~mL}\) of water to make an aqueous solution of ammonia. To prepare a buffer with a \(\mathrm{pH}\) of \(9.56,15.0 \mathrm{~g}\) of \(\mathrm{NH}_{4} \mathrm{Cl}\) are added. How many liters of \(\mathrm{NH}_{3}\) at \(25^{\circ} \mathrm{C}\) and 0.981 atm should be used to prepare the buffer? Assume no volume changes and ignore the vapor pressure of water.

Each symbol in the box below represents a mole of a component in one liter of a buffer solution; \(\bigcirc\) represents the anion \(\left(\mathrm{X}^{-}\right), \square 0=\) the weak acid \((\mathrm{HX}), \square=\mathrm{H}^{+},\) and \(\Delta=\mathrm{OH}^{-}\). Water molecules and the few \(\mathrm{H}^{+}\) and \(\mathrm{OH}^{-}\) ions from the dissociation of \(\mathrm{HX}\) and \(\mathrm{X}^{-}\) are not shown. The box contains \(10 \mathrm{~mol}\) of a weak acid, \(\square 0,\) in a liter of solution. Show what happens upon (a) the addition of \(2 \mathrm{~mol}\) of \(\mathrm{OH}^{-}(2 \Delta)\). (b) the addition of \(5 \mathrm{~mol}\) of \(\mathrm{OH}^{-}(5 \Delta)\). (c) the addition of \(10 \mathrm{~mol}\) of \(\mathrm{OH}^{-}(10 \Delta)\). (d) the addition of \(12 \mathrm{~mol}\) of \(\mathrm{OH}^{-}(12 \Delta)\). Which addition (a)-(d) represents neutralization halfway to the equivalence point?

A \(0.2481 \mathrm{M}\) solution of \(\mathrm{KOH}\) is used to titrate \(30.00 \mathrm{~mL}\) of \(0.269 \mathrm{M}\) hydrobromic acid. Assume that volumes are additive. (a) Write a balanced net ionic equation for the reaction that takes place during the titration. (b) What are the species present at the equivalence point? (c) What volume of \(\mathrm{KOH}\) is required to reach the equivalence point? (d) What is the \(\mathrm{pH}\) of the solution 1\. before any \(\mathrm{KOH}\) is added? 2\. halfway to the equivalence point? 3\. at the equivalence point?

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